Solution:
Frequency of dominant allele(B) p = 0.8
Frequency of recessive allele(b) q = 0.2
Frequency of heterozygotes is 2pq = 2 0.8 0.2 = 0.32
At a particular locus, frequency of allele B is 0.8 and that of b is 0.2. What would be the frequency of heterozygotes in a random mating population in equilibrium?
Frequency of dominant allele(B) p = 0.8
Frequency of recessive allele(b) q = 0.2
Frequency of heterozygotes is 2pq = 2 0.8 0.2 = 0.32