ZoologyThe recessive allele frequency in a Hardy-Weinberg population with 90% of individuals exhibiting dominant trait is approximately

The recessive allele frequency in a Hardy-Weinberg population with 90% of individuals exhibiting dominant trait is approximately

A
0.3
B
0.01
C
0.1
D
0.9

Solution:

Individuals exhibiting dominant trait = 90%
So individuals exhibiting recessive trait = 10%
$q^{2} = \frac{10}{100} = 0 .1$
Recessive allele frequency $= q = \sqrt{0 .1} = 0 .3 approximately$