{"id":108824,"date":"2022-02-12T14:19:46","date_gmt":"2022-02-12T08:49:46","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/?p=108824"},"modified":"2025-01-27T17:40:58","modified_gmt":"2025-01-27T12:10:58","slug":"ncert-solutions-for-class-8-maths-chapter-11-mensuration-ex-11-4","status":"publish","type":"post","link":"https:\/\/infinitylearn.com\/surge\/ncert-solutions\/class-8\/maths\/ncert-solutions-for-class-8-maths-chapter-11-mensuration-ex-11-4\/","title":{"rendered":"NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4"},"content":{"rendered":"<h2>NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4<\/h2>\n<p><strong>NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Exercise 11.4<\/strong><\/p>\n<p>Ex 11.4 Class 8 Maths Question 1.<br \/>\nGiven a cylindrical tank, in which situation will you find the surface area and in which situation volume.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106499\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/02\/NCERT-Solutions-for-Class-8-Maths-Chapter-11-Mensuration-Ex-11.4-Q1.png\" alt=\"NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 Q1\" width=\"165\" height=\"186\" \/><br \/>\n(a) To find how much it can hold.<br \/>\n(b) Number of cement bags required to plaster it.<br \/>\n(c) To find the number of smaller tanks that can be filled with water from it.<br \/>\nSolution:<br \/>\n(a) In this situation, we can find the volume.<br \/>\n(b) In this situation, we can find the surface area.<br \/>\n(c) In this situation, we can find the volume.<\/p>\n<p>Ex 11.4 Class 8 Maths Question 2.<br \/>\nDiameter of cylinder A is 7 cm, and the height is 14 cm. Diameter of cylinder B is 14 cm and height is 7 cm. Without doing any calculations can you suggest whose volume is greater? Verify it by finding the volume of both the cylinders. Check whether the cylinder with greater volume also has greater surface area?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106502\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/02\/NCERT-Solutions-for-Class-8-Maths-Chapter-11-Mensuration-Ex-11.4-Q2.png\" alt=\"NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 Q2\" width=\"290\" height=\"189\" \/><br \/>\nSolution:<br \/>\nCylinder B has a greater volume.<br \/>\nVerification:<br \/>\nVolume of cylinder A = \u03c0r<sup>2<\/sup>h<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106501\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/02\/NCERT-Solutions-for-Class-8-Maths-Chapter-11-Mensuration-Ex-11.4-Q2.1.png\" alt=\"NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 Q2.1\" width=\"379\" height=\"580\" \/><\/p>\n<p>Ex 11.4 Class 8 Maths Question 3.<br \/>\nFind the height of a cuboid whose base area is 180 cm<sup>2<\/sup> and volume is 900 cm<sup>3<\/sup>.<br \/>\nSolution:<br \/>\nGiven: Area of base = lb = 180 cm<sup>2<\/sup><br \/>\nV = 900 cm<sup>3<\/sup><br \/>\nVolume of the cuboid = l \u00d7 b \u00d7 h<br \/>\n900 = 180 \u00d7 h<br \/>\nh = 5 cm<br \/>\nHence, the required height = 5 cm.<\/p>\n<p>Ex 11.4 Class 8 Maths Question 4.<br \/>\nA cuboid is of dimensions 60 cm \u00d7 54 cm \u00d7 30 cm. How many small cubes with side 6 cm can be placed in the given cuboid?<br \/>\nSolution:<br \/>\nVolume of the cuboid = l \u00d7 b \u00d7 h = 60 cm \u00d7 54 cm \u00d7 30 cm = 97200 cm<sup>3<\/sup><br \/>\nVolume of the cube = (Side)<sup>3<\/sup> = (6)<sup>3<\/sup> = 216 cm<sup>3<\/sup><br \/>\nNumber of the cubes from the cuboid<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106503\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/02\/NCERT-Solutions-for-Class-8-Maths-Chapter-11-Mensuration-Ex-11.4-Q4.png\" alt=\"NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 Q4\" width=\"202\" height=\"141\" \/><br \/>\nHence, the required number of cubes = 450.<\/p>\n<p>Ex 11.4 Class 8 Maths Question 5.<br \/>\nFind the height of the cylinder whose volume is 1.54 m<sup>3<\/sup> and the diameter of the base is 140 cm.<br \/>\nSolution:<br \/>\nV = 1.54 m<sup>3<\/sup>, d = 140 cm = 1.40 m<br \/>\nVolume of the cylinder = \u03c0r2h<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106504\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/02\/NCERT-Solutions-for-Class-8-Maths-Chapter-11-Mensuration-Ex-11.4-Q5.png\" alt=\"NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 Q5\" width=\"267\" height=\"205\" \/><br \/>\nHence, the height of cylinder = 1 m.<\/p>\n<p>Ex 11.4 Class 8 Maths Question 6.<br \/>\nA milk tank is in the form of a cylinder whose radius is 1.5 m and length is 7 m. Find the quantity of milk in litres that can be stored in the tank.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106505\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/02\/NCERT-Solutions-for-Class-8-Maths-Chapter-11-Mensuration-Ex-11.4-Q6.png\" alt=\"NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 Q6\" width=\"225\" height=\"128\" \/><br \/>\nSolution:<br \/>\nHere, r = 1.5 m<br \/>\nh = 7 m<br \/>\n.\u2019. Volume of the milk tank = \u03c0r<sup>2<\/sup>h<br \/>\n= \\(\\frac { 22 }{ 7 }\\) \u00d7 1.5 \u00d7 1.5 \u00d7 7<br \/>\n= 22 \u00d7 2.25<br \/>\n= 49.50 m<sup>3<\/sup><br \/>\nVolume of milk in litres = 49.50 \u00d7 1000 L (\u2235 1 m<sup>3<\/sup> = 1000 litres)<br \/>\n= 49500 L<br \/>\nHence, the required volume = 49500 L.<\/p>\n<p>Ex 11.4 Class 8 Maths Question 7.<br \/>\nIf each edge of a cube is doubled,<br \/>\n(i) how many times will it be surface area increase?<br \/>\n(ii) how many times will its volume increase?<br \/>\nSolution:<br \/>\nLet the edge of the cube = x cm<br \/>\nIf the edge is doubled, then the new edge = 2x cm<br \/>\n(i) Original surface area = 6x<sup>2<\/sup> cm<sup>2<\/sup><br \/>\nNew surface area = 6(2x)<sup>2<\/sup> = 6 \u00d7 4x<sup>2<\/sup> = 24x<sup>2<\/sup><br \/>\nRatio = 6x<sup>2<\/sup> : 24x<sup>2<\/sup> = 1 : 4<br \/>\nHence, the new surface area will be four times the original surface area.<\/p>\n<p>(ii) Original volume of the cube = x<sup>3<\/sup> cm<sup>3<\/sup><br \/>\nNew volume of the cube = (2x)<sup>3<\/sup> = 8x<sup>3<\/sup> cm<sup>3<\/sup><br \/>\nRatio = x<sup>3<\/sup> : 8x<sup>3<\/sup> = 1 : 8<br \/>\nHence, the new volume will be eight times the original volume.<\/p>\n<p>Ex 11.4 Class 8 Maths Question 8.<br \/>\nWater is pouring into a cuboidal reservoir at the rate of 60 litres per minute. If the volume of the reservoir is 108 m<sup>3<\/sup>, find the number of hours it will take to fill the reservoir.<br \/>\nSolution:<br \/>\nVolume of the reservoir = 108 m<sup>3<\/sup> = 108000 L [\u22351 m<sup>3<\/sup> = 1000 L]\nVolume of water flowing into the reservoir in 1 minute = 60 L<br \/>\nTime taken to fill the reservoir<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106506\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/02\/NCERT-Solutions-for-Class-8-Maths-Chapter-11-Mensuration-Ex-11.4-Q8.png\" alt=\"NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 Q8\" width=\"254\" height=\"179\" \/><br \/>\nHence, the required hour to fill the reservoir = 30 hours.<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-106507\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/02\/NCERT-Solutions-for-Class-8-Maths-Chapter-11-Mensuration-Ex-11.4-q-1.png\" alt=\"NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 q-1\" width=\"691\" height=\"734\" \/><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-106508\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/02\/NCERT-Solutions-for-Class-8-Maths-Chapter-11-Mensuration-Ex-11.4-q-2.png\" alt=\"NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 q-2\" width=\"686\" height=\"686\" \/><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-106509\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/02\/NCERT-Solutions-for-Class-8-Maths-Chapter-11-Mensuration-Ex-11.4-q-3.png\" alt=\"NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 q-3\" width=\"689\" height=\"720\" \/><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-106510\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/02\/NCERT-Solutions-for-Class-8-Maths-Chapter-11-Mensuration-Ex-11.4-q-4.png\" alt=\"NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 q-4\" width=\"648\" height=\"687\" \/><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-106511\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/02\/NCERT-Solutions-for-Class-8-Maths-Chapter-11-Mensuration-Ex-11.4-q-5.png\" alt=\"NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 q-5\" width=\"679\" height=\"263\" \/><\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 NCERT Solutions for Class 8 Maths Chapter 11 Mensuration [&hellip;]<\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"\"Get NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Ex 11.4 on Infinity Learn.\"","custom_permalink":"ncert-solutions\/class-8\/maths\/ncert-solutions-for-class-8-maths-chapter-11-mensuration-ex-11-4\/"},"categories":[13,54,75],"tags":[],"table_tags":[],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v17.9 - 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