{"id":122784,"date":"2022-02-20T14:58:43","date_gmt":"2022-02-20T09:28:43","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/?p=122784"},"modified":"2024-04-10T15:09:42","modified_gmt":"2024-04-10T09:39:42","slug":"ncert-exemplar-solutions-class-8-maths-solutions-chapter-9-comparing-quantities","status":"publish","type":"post","link":"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-8\/maths\/chapter-9-comparing-quantities\/","title":{"rendered":"NCERT Exemplar Solutions Class 8 Maths &#8211; Chapter 9 Comparing Quantities"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_37 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" style=\"display: none;\"><label for=\"item\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input type=\"checkbox\" id=\"item\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1' style='display:block'><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-8\/maths\/chapter-9-comparing-quantities\/#Access_Answers_to_NCERT_Exemplar_Solutions_for_Class_8_Maths_Chapter_9_Comparing_Quantities\" title=\"Access Answers to NCERT Exemplar Solutions for Class 8 Maths Chapter 9 Comparing Quantities\">Access Answers to NCERT Exemplar Solutions for Class 8 Maths Chapter 9 Comparing Quantities<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-8\/maths\/chapter-9-comparing-quantities\/#NCERT_Exemplar_Solutions_Class_8_Maths_Solutions_Chapter_9_Comparing_Quantities\" title=\"NCERT Exemplar Solutions Class 8 Maths Solutions Chapter 9 Comparing Quantities\">NCERT Exemplar Solutions Class 8 Maths Solutions Chapter 9 Comparing Quantities<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-8\/maths\/chapter-9-comparing-quantities\/#Key_Features_of_NCERT_Exemplar_Solutions_for_this_chapter\" title=\"Key Features of NCERT Exemplar Solutions for this chapter\">Key Features of NCERT Exemplar Solutions for this chapter<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-8\/maths\/chapter-9-comparing-quantities\/#Chapter_9_Comparing_Quantities_FAQs\" title=\"Chapter 9 Comparing Quantities FAQ&#8217;s\">Chapter 9 Comparing Quantities FAQ&#8217;s<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-8\/maths\/chapter-9-comparing-quantities\/#How_is_NCERT_Exemplar_Solutions_from_this_chapter_helpful_for_board_exams\" title=\" How is NCERT Exemplar Solutions from this chapter helpful for board exams?\"> How is NCERT Exemplar Solutions from this chapter helpful for board exams?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-8\/maths\/chapter-9-comparing-quantities\/#Is_it_necessary_to_practice_all_the_exercises_present_in_Chapter_9_of_NCERT_Exemplar_Solutions_for_Class_8_Maths\" title=\"Is it necessary to practice all the exercises present in Chapter 9 of NCERT Exemplar Solutions for Class 8 Maths?\">Is it necessary to practice all the exercises present in Chapter 9 of NCERT Exemplar Solutions for Class 8 Maths?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-8\/maths\/chapter-9-comparing-quantities\/#Mention_the_topics_that_are_covered_in_these_NCERT_Exemplar_Solutions\" title=\"Mention the topics that are covered in these NCERT Exemplar Solutions?\">Mention the topics that are covered in these NCERT Exemplar Solutions?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<p>Subject specialists have designed <a href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-8\/maths\/\"><strong>NCERT Exemplar Solutions for Maths Class 8<\/strong><\/a> Chapter 9 which includes thorough solutions for reference. These solutions are updated according to the latest <a href=\"https:\/\/infinitylearn.com\/surge\/cbse\/cbse-syllabus\/\"><strong>CBSE syllabus for 2024-25<\/strong><\/a> and are provided in easy language for understanding. Tips and tricks are also provided.<\/p>\n<p>These solutions are provided so a student can clear his doubts and get help with a deep understanding of the concept. Also, you can refer them to make the chapter notes and revisions notes. PDF of this can also be downloaded from the website.<\/p>\n<p>The <a href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/\"><strong>NCERT Exemplar Solutions<\/strong> <\/a>of this chapter starts with basic concepts like terms, factors, coefficients, like and unlike terms, addition and subtraction of algebraic expressions, and multiplication of two or more polynomials. Students can go through the various algebraic expression identities and solve problems applying these identities. In NCERT Class 8, this chapter carries a total weightage of 8 to 10 marks in the final examination. Students can use them to solve exercise questions and prepare for their examinations.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Access_Answers_to_NCERT_Exemplar_Solutions_for_Class_8_Maths_Chapter_9_Comparing_Quantities\"><\/span>Access Answers to NCERT Exemplar Solutions for Class 8 Maths Chapter 9 Comparing Quantities<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>There are four options, out of which one is correct. Write the correct answer.<\/strong><\/p>\n<p><strong>Question: Suppose for the principal P, rate R% and time T, the simple interest is S and compound interest is C. Consider the possibilities.<\/strong><br \/>\n<strong>(i) C &gt; S<\/strong><br \/>\n<strong>(ii) C = S<\/strong><br \/>\n<strong>(iii) C &lt; S<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(a) only (i) is correct.<\/p>\n<p><strong>Explanation:<\/strong> Let the principal P be Rs. 100, the rate R be 10% and the time T be 1 year.<br \/>\nSimple interest (SI) = (P \u00d7 R \u00d7 T) \/ 100 = (100 \u00d7 10 \u00d7 1) \/ 100 = Rs. 10<br \/>\nAmount = P(1 + R\/100)T = 100(1 + 10\/100)1 = 100(11\/10) = Rs. 110<br \/>\nCompound interest (CI) = Amount \u2013 Principal = 110 &#8211; 100 = Rs. 10<\/p>\n<p>As we can see, CI &gt; SI, which is the first possibility.<\/p>\n<p><strong>Question: Suppose a certain sum doubles in 2 years at r % rate of simple interest per annum or at R% rate of interest per annum compounded annually. We have<\/strong><br \/>\n<strong>(a) r &lt; R<\/strong><br \/>\n<strong>(b) R &lt; r<\/strong><br \/>\n<strong>(c) R = r<\/strong><br \/>\n<strong>(d) can\u2019t be decided<\/strong><\/p>\n<p><b>Answer &#8211;  <\/b>(b) R &lt; r<\/p>\n<p><strong>Explanation<\/strong>: Let the sum be Rs. 100.<\/p>\n<p>For simple interest,<br \/>\nAmount = P + SI = P + (P \u00d7 r \u00d7 T) \/ 100 = 100 + (100 \u00d7 r \u00d7 2) \/ 100 = 100 + 2r<\/p>\n<p>For compound interest,<br \/>\nAmount = P(1 + R\/100)T = 100(1 + R\/100)2 = 100(1 + R\/50) = 100 + 2R<\/p>\n<p>Since the sum doubles in 2 years, the amount becomes 200.<\/p>\n<p>So, 200 = 100 + 2r and 200 = 100 + 2R<\/p>\n<p>Solving these equations, we get r = 50 and R = 25.<\/p>\n<p>Therefore, R &lt; r.<\/p>\n<p><strong>Question: The compound interest on Rs 50,000 at 4% per annum for 2 years compounded annually is<\/strong><br \/>\n<strong>(a) Rs 4,000<\/strong><br \/>\n<strong>(b) Rs 4,080<\/strong><br \/>\n<strong>(c) Rs 4,280<\/strong><br \/>\n<strong>(d) Rs 4,050<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(b) Rs 4,080<\/p>\n<p><strong>Explanation<\/strong>: P = Rs. 50,000, R = 4%, T = 2 years<\/p>\n<p>Amount = P(1 + R\/100)T = 50000(1 + 4\/100)2 = 50000(1 + 1\/25)2<\/p>\n<p>A = 50000(26\/25)2 = 54080<\/p>\n<p>Compound interest = A \u2013 P = 54080 \u2013 50000 = Rs. 4080<\/p>\n<p>Therefore, the compound interest is Rs. 4080.<\/p>\n<p><strong>Question: If the marked price of an article is Rs 1,200, and the discount is 12%, then the selling price of the article is<\/strong><br \/>\n<strong>(a) Rs 1,056<\/strong><br \/>\n<strong>(b) Rs 1,344<\/strong><br \/>\n<strong>(c) Rs 1,212<\/strong><br \/>\n<strong>(d) Rs 1,188<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(a) Rs 1,056<\/p>\n<p><strong>Explanation<\/strong>: Marked price = Rs. 1200<br \/>\nDiscount = 12%<\/p>\n<p>Discount price = 12% of 1200 = 12\/100 \u00d7 1200 = 12 \u00d7 12 = 144<\/p>\n<p>Selling price = Marked price \u2013 discount price = 1200 \u2013 144 = Rs. 1056<\/p>\n<p>Therefore, the selling price of the article is Rs. 1056.<\/p>\n<p><strong>Question: If 90% of x is 315 km, then the value of x is<\/strong><br \/>\n<strong>(a) 325 km<\/strong><br \/>\n<strong>(b) 350 km<\/strong><br \/>\n<strong>(c) 350 m<\/strong><br \/>\n<strong>(d) 325 m<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(b) 350 km<\/p>\n<p><strong>Explanation<\/strong>: 90% of x is 315 km<\/p>\n<p>90\/100 \u00d7 x = 315<\/p>\n<p>X = 315 \u00d7 100\/90 = 315 \u00d7 10\/9 = 350<\/p>\n<p>Therefore, the value of x is 350 km.<\/p>\n<p><strong>Question: To gain 25% after allowing a discount of 10%, the shopkeeper must mark the price of the article, which costs him Rs 360 as<\/strong><br \/>\n<strong>(a) Rs 500<\/strong><br \/>\n<strong>(b) Rs 450<\/strong><br \/>\n<strong>(c) Rs 460<\/strong><br \/>\n<strong>(d) Rs 486<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(a) Rs 500<\/p>\n<p><strong>Explanation<\/strong>: Let the marked price be x.<\/p>\n<p>Cost price = Rs. 360<\/p>\n<p>Discount = 10% of x = 10\/100 \u00d7 x<\/p>\n<p>Selling price = x \u2013 (10\/100) \u00d7 x<\/p>\n<p>Gain = 25% of 360 = 25\/100 \u00d7 360 = 90<\/p>\n<p>Selling price + Gain = Marked price<\/p>\n<p>x \u2013 (10\/100) \u00d7 x + 90 = x<\/p>\n<p>90 = (10\/100) \u00d7 x<\/p>\n<p>x = 90 \u00d7 100\/10 = 900<\/p>\n<p>Therefore, the shopkeeper must mark the price of the article as Rs. 900.<\/p>\n<p><strong>Question: If a % is the discount per cent on a marked price x, then discount is<\/strong><br \/>\n<strong>(a) (x\/a) \u00d7 100<\/strong><br \/>\n<strong>(b) (a\/x) \u00d7 100<\/strong><br \/>\n<strong>(c) x \u00d7 (a\/100)<\/strong><br \/>\n<strong>(d) 100\/(x \u00d7 a)<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(c) x \u00d7 (a\/100)<\/p>\n<p><strong>Explanation<\/strong>: Discount = Discount% on Marked price<\/p>\n<p>Discount = a\/100 \u00d7 x<\/p>\n<p>Therefore, discount is x \u00d7 (a\/100).<\/p>\n<p><strong>Question: Ashima took a loan of Rs 1,00,000 at 12% p.a. compounded half-yearly. She paid Rs. 1,12,360. If (1.06)2 is equal to 1.1236, then the period for which she took the loan is:<\/strong><br \/>\n<strong>(a) 2 years<\/strong><br \/>\n<strong>(b) 1 year<\/strong><br \/>\n<strong>(c) 6 months<\/strong><br \/>\n<strong>(d) 1(1\/2) years<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(b) 1 year<\/p>\n<p><strong>Explanation<\/strong>: P = Rs. 100000, R = 12% per annum compounded half-yearly, Amount = Rs. 112360<\/p>\n<p>A = P(1 + R\/100)T<\/p>\n<p>112360 = 100000(1 + 12\/100)T<\/p>\n<p>112360\/100000 = (1 + 12\/100)T<\/p>\n<p>(1.1236)1 = (1.06)T<\/p>\n<p>T = 1 year<\/p>\n<p>Therefore, Ashima took the loan for 1 year.<\/p>\n<p><strong>Question: For the calculation of interest compounded half yearly, keeping the principal same, which one of the following is true?<\/strong><br \/>\n<strong>(a) Double the given annual rate and half the given number of years.<\/strong><br \/>\n<strong>(b) Double the given annual rate as well as the given number of years.<\/strong><br \/>\n<strong>(c) Half the given annual rate as well as the given number of years.<\/strong><br \/>\n<strong>(d) Half the given annual rate and double the given number of years.<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(d) Half the given annual rate and double the given number of years.<\/p>\n<p><strong>Explanation<\/strong>: If the interest is compounded half yearly, then the rate of interest is divided by 2 and the number of times the interest is charged is doubled.<\/p>\n<p>Therefore, the correct option is (d) Half the given annual rate and double the given number of years.<\/p>\n<p><strong>Question: Shyama purchases a scooter costing Rs 36,450, and the rate of sales tax is 9%. Then the total amount paid by her is:<\/strong><br \/>\n<strong>(a) Rs 36,490.50<\/strong><br \/>\n<strong>(b) Rs 39,730.50<\/strong><br \/>\n<strong>(c) Rs 36,454.50<\/strong><br \/>\n<strong>(d) Rs 33,169.50<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(b) Rs 39,730.50<\/p>\n<p><strong>Explanation<\/strong>: Cost of scooter = Rs. 36450<br \/>\nRate of sales tax = 9%<\/p>\n<p>Total amount paid = Cost of scooter + (Cost of scooter \u00d7 Sales tax) \/ 100<\/p>\n<p>Total amount paid = 36450 + (36450 \u00d7 9) \/ 100 = 36450 + 3280.50 = Rs. 39730.50<\/p>\n<p>Therefore, the total amount paid by Shyama is Rs. 39730.50.<\/p>\n<p><strong>Question: The marked price of an article is Rs 80, and it is sold at Rs 76. Then the discount rate is:<\/strong><br \/>\n<strong>(a) 5%<\/strong><br \/>\n<strong>(b) 95%<\/strong><br \/>\n<strong>(c) 10%<\/strong><br \/>\n<strong>(d) appx. 11%<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(a) 5%<\/p>\n<p><strong>Explanation<\/strong>: Marked price = Rs. 80<br \/>\nSelling price = Rs. 76<\/p>\n<p>Discount = Marked price \u2013 Selling price = Rs. 80 \u2013 Rs. 76 = Rs. 4<\/p>\n<p>Discount% = (Discount \/ Marked price) \u00d7 100 = (4 \/ 80) \u00d7 100 = 5%<\/p>\n<p>Therefore, the discount rate is 5%.<\/p>\n<p><strong>Question: A bought a tape recorder for Rs 8,000 and sold it to B. B in turn sold it to C, each earning a profit of 20%. Which of the following is true:<\/strong><br \/>\n<strong>(a) A and B earn the same profit.<\/strong><br \/>\n<strong>(b) A earns more profit than B.<\/strong><br \/>\n<strong>(c) A earns less profit than B.<\/strong><br \/>\n<strong>(d) Cannot be decided.<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(c) A earns less profit than B<\/p>\n<p><strong>Explanation<\/strong>: A bought a tape recorder for Rs 8,000 and sold it to B at a profit of 20%.<\/p>\n<p>Cost price for B = 8000 \u00d7 100 \/ (100 + 20) = 8000 \u00d7 100 \/ 120 = Rs. 6666.67<\/p>\n<p>B sold the tape recorder to C at a profit of 20%.<\/p>\n<p>Cost price for C = 6666.67 \u00d7 100 \/ (100 + 20) = 6666.67 \u00d7 100 \/ 120 = Rs. 5555.56<\/p>\n<p>Profit for A = 8000 \u2013 6666.67 = Rs. 1333.33<\/p>\n<p>Profit for B = 6666.67 \u2013 5555.56 = Rs. 1111.11<\/p>\n<p>Therefore, A earns more profit than B.<\/p>\n<p><strong>Question: Latika bought a teapot for Rs 120 and a set of cups for Rs 400. She sold the teapot at a profit of 5% and the cups at a loss of 5%. The amount received by her is:<\/strong><br \/>\n<strong>(a) Rs 494<\/strong><br \/>\n<strong>(b) Rs 546<\/strong><br \/>\n<strong>(c) Rs 506<\/strong><br \/>\n<strong>(d) Rs 534<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(c) Rs 506<\/p>\n<p><strong>Explanation<\/strong>: Cost price of teapot = Rs. 120<br \/>\nSelling price of teapot = 120 + (120 \u00d7 5) \/ 100 = 120 + 6 = Rs. 126<\/p>\n<p>Cost price of cups = Rs. 400<br \/>\nSelling price of cups = 400 \u2013 (400 \u00d7 5) \/ 100 = 400 \u2013 20 = Rs. 380<\/p>\n<p>Amount received by Latika = Selling price of teapot + Selling price of cups = 126 + 380 = Rs. 506<\/p>\n<p>Therefore, the amount received by Latika is Rs. 506.<\/p>\n<p><strong>Question: A jacket was sold for Rs 1,120 after allowing a discount of 20%. The marked price of the jacket is:<\/strong><br \/>\n<strong>(a) Rs 1440<\/strong><br \/>\n<strong>(b) Rs 1400<\/strong><br \/>\n<strong>(c) Rs 960<\/strong><br \/>\n<strong>(d) Rs 866.66<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(b) Rs. 1400<\/p>\n<p><strong>Explanation<\/strong>: Let the marked price be x.<\/p>\n<p>Discount = 20% of x = 20\/100 \u00d7 x<\/p>\n<p>Selling price = x \u2013 (20\/100) \u00d7 x = x \u2013 x\/5 = 4x\/5<\/p>\n<p>Selling price = 1120<\/p>\n<p>4x\/5 = 1120<\/p>\n<p>x = 1120 \u00d7 5\/4 = 1400<\/p>\n<p>Therefore, the marked price of the jacket is Rs. 1400.<\/p>\n<p><strong>Question: A sum is taken for two years at 16% p.a. If interest is compounded after every three months, the number of times for which interest is charged in 2 years is:<\/strong><br \/>\n<strong>(a) 8<\/strong><br \/>\n<strong>(b) 4<\/strong><br \/>\n<strong>(c) 6<\/strong><br \/>\n<strong>(d) 9<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(a) 8<\/p>\n<p><strong>Explanation<\/strong>: If interest is compounded after every three months, then the number of times interest is charged in 2 years is 2 \u00d7 4 = 8 times.<\/p>\n<p>Therefore, the correct option is (a) 8.<\/p>\n<p><strong>Question: The original price of a washing machine which was bought for Rs 13,500 inclusive of 8% VAT, is:<\/strong><br \/>\n<strong>(a) Rs 14,420<\/strong><br \/>\n<strong>(b) Rs 14,580<\/strong><br \/>\n<strong>(c) Rs 12,500<\/strong><br \/>\n<strong>(d) Rs 13,492<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(a) Rs 12,420<\/p>\n<p><strong>Explanation<\/strong>: Let the original price of the washing machine be x.<\/p>\n<p>Cost price of washing machine including VAT = x + (8\/100) \u00d7 x = x + 0.08x = 1.08x = 13500<\/p>\n<p>x = 13500 \/ 1.08 = 12500<\/p>\n<p>Therefore, the original price of the washing machine is Rs. 12500.<\/p>\n<p><strong>Question: Avinash bought an electric iron for Rs 900 and sold it at a gain of 10%. He sold another electric iron at 5% loss which was bought for Rs 1200. On the transaction, he has a:<\/strong><br \/>\n<strong>(a) Profit of Rs 75<\/strong><br \/>\n<strong>(b) Loss of Rs 75<\/strong><br \/>\n<strong>(c) Profit of Rs 30<\/strong><br \/>\n<strong>(d) Loss of Rs 30<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(c) Profit of Rs 30<\/p>\n<p><strong>Explanation<\/strong>: Cost price of first electric iron = Rs. 900<br \/>\nSelling price of first electric iron = 900 + (900 \u00d7 10) \/ 100 = 900 + 90 = Rs. 990<\/p>\n<p>Cost price of second electric iron = Rs. 1200<br \/>\nSelling price of second electric iron = 1200 \u2013 (1200 \u00d7 5) \/ 100 = 1200 \u2013 60 = Rs. 1140<\/p>\n<p>Total cost price = 900 + 1200 = Rs. 2100<\/p>\n<p>Total selling price = 990 + 1140 = Rs. 2130<\/p>\n<p>Profit = Total selling price \u2013 Total cost price = 2130 \u2013 2100 = Rs. 30<\/p>\n<p>Therefore, Avinash has a profit of Rs. 30.<\/p>\n<p><strong>Question: A TV set was bought for Rs 26,250, including 5% VAT. The original price of the TV set is:<\/strong><br \/>\n<strong>(a) Rs 27,562.50<\/strong><br \/>\n<strong>(b) Rs 25,000<\/strong><br \/>\n<strong>(c) Rs 24,937.50<\/strong><br \/>\n<strong>(d) Rs 26,245<\/strong><\/p>\n<p><b>Answer &#8211; <\/b>(c) Rs 24,937.50<\/p>\n<p><strong>Explanation<\/strong>: Let the original price of the TV set be x.<\/p>\n<p>Cost price of TV set including VAT = x + (5\/100) \u00d7 x = x + 0.05x = 1.05x = 26250<\/p>\n<p>x = 26250 \/ 1.05 = 25000<\/p>\n<p>Therefore, the original price of the TV set is Rs. 25000.<\/p>\n<p><b>Question &#8211; To calculate the growth of a bacteria if the rate of growth is known, the formula for calculation of the amount in compound interest can be used.<\/b><\/p>\n<p><b>Answer &#8211;  <\/b>True<\/p>\n<p><b>Question &#8211; Additional expenses made after buying an article are included in the cost price and are known as Value Added Tax.<\/b><\/p>\n<p><b>Answer &#8211;  <\/b>False<\/p>\n<p><b>Question &#8211; Discount is a reduction given on the cost price of an article.<\/b><\/p>\n<p><b>Answer &#8211;  <\/b>False<\/p>\n<p><b>Question &#8211; Compound interest is the interest calculated on the previous year\u2019s amount.<\/b><\/p>\n<p><b>Answer &#8211;  <\/b>True<\/p>\n<p><b>Question &#8211; C.P. = M.P. \u2013 Discount.<\/b><\/p>\n<p><b>Answer &#8211;  <\/b>False<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Exemplar_Solutions_Class_8_Maths_Solutions_Chapter_9_Comparing_Quantities\"><\/span>NCERT Exemplar Solutions Class 8 Maths Solutions Chapter 9 Comparing Quantities<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3><span class=\"ez-toc-section\" id=\"Key_Features_of_NCERT_Exemplar_Solutions_for_this_chapter\"><\/span>Key Features of NCERT Exemplar Solutions for this chapter<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ol>\n<li>NCERT Exemplar Solutions helps in providing fully resolved step-by-step solutions to all textbook questions.<\/li>\n<li>Set of solutions that come with a list of all important formulas on algebraic identities.<\/li>\n<li>These solutions are made according to the latest syllabus.<\/li>\n<li>Solutions are prepared by subject matter experts.<\/li>\n<li>NCERT Exemplar Solutions provides help for the preparation of competitive exams.<\/li>\n<\/ol>\n<h2><span class=\"ez-toc-section\" id=\"Chapter_9_Comparing_Quantities_FAQs\"><\/span>Chapter 9 Comparing Quantities FAQ&#8217;s<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\t\t<section class=\"sc_fs_faq sc_card \">\n\t\t\t<div>\n\t\t\t\t<h3><span class=\"ez-toc-section\" id=\"How_is_NCERT_Exemplar_Solutions_from_this_chapter_helpful_for_board_exams\"><\/span> How is NCERT Exemplar Solutions from this chapter helpful for board exams?<span class=\"ez-toc-section-end\"><\/span><\/h3>\t\t\t\t<div>\n\t\t\t\t\t\t\t\t\t\t<p>\n\t\t\t\t\t\t NCERT Exemplar Solutions of this chapter comes with detailed descriptions as per the term limit particularised by the Board for self-evaluation. Solving these solutions can help in providing good marks in exams. Students can improve their skills on siting on exam dah\t\t\t\t\t<\/p>\n\t\t\t\t<\/div>\n\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t<section class=\"sc_fs_faq sc_card \">\n\t\t\t<div>\n\t\t\t\t<h3><span class=\"ez-toc-section\" id=\"Is_it_necessary_to_practice_all_the_exercises_present_in_Chapter_9_of_NCERT_Exemplar_Solutions_for_Class_8_Maths\"><\/span>Is it necessary to practice all the exercises present in Chapter 9 of NCERT Exemplar Solutions for Class 8 Maths?<span class=\"ez-toc-section-end\"><\/span><\/h3>\t\t\t\t<div>\n\t\t\t\t\t\t\t\t\t\t<p>\n\t\t\t\t\t\tYes. As these questions seem to be important for exams. These questions are solved by subject matter experts for helping students to crack these exercises easily. These solutions give students knowledge about data handling. Solutions can be downloaded in PDF format on the Infinity Learn website.\t\t\t\t\t<\/p>\n\t\t\t\t<\/div>\n\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t<section class=\"sc_fs_faq sc_card \">\n\t\t\t<div>\n\t\t\t\t<h3><span class=\"ez-toc-section\" id=\"Mention_the_topics_that_are_covered_in_these_NCERT_Exemplar_Solutions\"><\/span>Mention the topics that are covered in these NCERT Exemplar Solutions?<span class=\"ez-toc-section-end\"><\/span><\/h3>\t\t\t\t<div>\n\t\t\t\t\t\t\t\t\t\t<p>\n\t\t\t\t\t\tThe topics included in NCERT Exemplar Solutions of this chapter are 9.1 \u2013 introduction to expressions 9.2 \u2013 terms, factors, and coefficients 9.3 \u2013 monomials, binomials, and polynomials 9.4 \u2013 like and unlike terms 9.5 \u2013 addition and subtraction of algebraic expressions 9.6 \u2013 multiplication of algebraic expressions: introduction 9.7 \u2013 multiplying a monomial by a monomial 9.8 \u2013 multiplying a monomial by a polynomial 9.9 \u2013 multiplying a polynomial by a polynomial 9.10 \u2013 definition and meaning of identity 9.11 \u2013 standard identities 9.12 \u2013 applying identities. \t\t\t\t\t<\/p>\n\t\t\t\t<\/div>\n\t\t\t<\/div>\n\t\t<\/section>\n\t\t\n<script type=\"application\/ld+json\">\n\t{\n\t\t\"@context\": \"https:\/\/schema.org\",\n\t\t\"@type\": \"FAQPage\",\n\t\t\"mainEntity\": [\n\t\t\t\t\t{\n\t\t\t\t\"@type\": \"Question\",\n\t\t\t\t\"name\": \" How is NCERT Exemplar Solutions from this chapter helpful for board exams?\",\n\t\t\t\t\"acceptedAnswer\": {\n\t\t\t\t\t\"@type\": \"Answer\",\n\t\t\t\t\t\"text\": \"NCERT Exemplar Solutions of this chapter comes with detailed descriptions as per the term limit particularised by the Board for self-evaluation. Solving these solutions can help in providing good marks in exams. Students can improve their skills on siting on exam dah\"\n\t\t\t\t\t\t\t\t\t}\n\t\t\t}\n\t\t\t,\t\t\t\t{\n\t\t\t\t\"@type\": \"Question\",\n\t\t\t\t\"name\": \"Is it necessary to practice all the exercises present in Chapter 9 of NCERT Exemplar Solutions for Class 8 Maths?\",\n\t\t\t\t\"acceptedAnswer\": {\n\t\t\t\t\t\"@type\": \"Answer\",\n\t\t\t\t\t\"text\": \"Yes. As these questions seem to be important for exams. These questions are solved by subject matter experts for helping students to crack these exercises easily. These solutions give students knowledge about data handling. Solutions can be downloaded in PDF format on the Infinity Learn website.\"\n\t\t\t\t\t\t\t\t\t}\n\t\t\t}\n\t\t\t,\t\t\t\t{\n\t\t\t\t\"@type\": \"Question\",\n\t\t\t\t\"name\": \"Mention the topics that are covered in these NCERT Exemplar Solutions?\",\n\t\t\t\t\"acceptedAnswer\": {\n\t\t\t\t\t\"@type\": \"Answer\",\n\t\t\t\t\t\"text\": \"The topics included in NCERT Exemplar Solutions of this chapter are 9.1 \u2013 introduction to expressions 9.2 \u2013 terms, factors, and coefficients 9.3 \u2013 monomials, binomials, and polynomials 9.4 \u2013 like and unlike terms 9.5 \u2013 addition and subtraction of algebraic expressions 9.6 \u2013 multiplication of algebraic expressions: introduction 9.7 \u2013 multiplying a monomial by a monomial 9.8 \u2013 multiplying a monomial by a polynomial 9.9 \u2013 multiplying a polynomial by a polynomial 9.10 \u2013 definition and meaning of identity 9.11 \u2013 standard identities 9.12 \u2013 applying identities.\"\n\t\t\t\t\t\t\t\t\t}\n\t\t\t}\n\t\t\t\t\t\t]\n\t}\n<\/script>\n\n","protected":false},"excerpt":{"rendered":"<p>Subject specialists have designed NCERT Exemplar Solutions for Maths Class 8 Chapter 9 which includes thorough solutions for reference. These [&hellip;]<\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"NCERT Exemplar Solutions Class 8 Maths - Chapter 9","_yoast_wpseo_title":"NCERT Exemplar Solutions Class 8 Maths - Chapter 9 | Infinity Learn","_yoast_wpseo_metadesc":"Free PDF download of NCERT Exemplar Solutions for Class 8 Maths Chapter 9 Comparing Quantities solved by Expert Teachers as per NCERT CBSE Book guidelines. All Chapter wise Questions with Solutions of Class 8 to help you to revise complete Syllabus and Score More marks in your examinations.","custom_permalink":"study-materials\/ncert-exemplar-solutions\/class-8\/maths\/chapter-9-comparing-quantities\/"},"categories":[153,161,105,21],"tags":[],"table_tags":[],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v17.9 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Exemplar Solutions Class 8 Maths - Chapter 9 | Infinity Learn<\/title>\n<meta name=\"description\" content=\"Free PDF download of NCERT Exemplar Solutions for Class 8 Maths Chapter 9 Comparing Quantities solved by Expert Teachers as per NCERT CBSE Book guidelines. 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