{"id":133455,"date":"2022-03-03T23:40:34","date_gmt":"2022-03-03T18:10:34","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/?p=133455"},"modified":"2024-10-07T15:13:33","modified_gmt":"2024-10-07T09:43:33","slug":"balancing-the-chemical-equations-part-2","status":"publish","type":"post","link":"https:\/\/infinitylearn.com\/surge\/class-10\/chemisry\/chemical-reactions-and-equations\/balancing-the-chemical-equations-part-2\/","title":{"rendered":"Balancing the chemical equations"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_37 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" style=\"display: none;\"><label for=\"item\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input type=\"checkbox\" id=\"item\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1' style='display:block'><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/infinitylearn.com\/surge\/class-10\/chemisry\/chemical-reactions-and-equations\/balancing-the-chemical-equations-part-2\/#How_to_balance_a_chemical_equation\" title=\"How to balance a chemical equation?\">How to balance a chemical equation?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/infinitylearn.com\/surge\/class-10\/chemisry\/chemical-reactions-and-equations\/balancing-the-chemical-equations-part-2\/#Table_1\" title=\"Table 1\">Table 1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/infinitylearn.com\/surge\/class-10\/chemisry\/chemical-reactions-and-equations\/balancing-the-chemical-equations-part-2\/#Table_2\" title=\"Table 2\">Table 2<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/infinitylearn.com\/surge\/class-10\/chemisry\/chemical-reactions-and-equations\/balancing-the-chemical-equations-part-2\/#Table_3\" title=\"Table 3\">Table 3<\/a><\/li><\/ul><\/nav><\/div>\n<p><strong>Table of Contents<\/strong><\/p>\n<ul>\n<li>Balancing a Chemical Equation<\/li>\n<li>Symbols of Physical States\n<ul>\n<li>Gaseous<\/li>\n<li>Liquid<\/li>\n<li>Aqueous<\/li>\n<li>Solid<\/li>\n<\/ul>\n<\/li>\n<li>Summary<\/li>\n<li>What\u2019s Next?<\/li>\n<\/ul>\n<p>In the first segment, we learnt about <strong>balancing the chemical equations. <\/strong>In this segment, we will revise the concept of balancing the chemical equations with another example.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"How_to_balance_a_chemical_equation\"><\/span>How to balance a chemical equation?<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To balance a chemical equation we need to follow a few steps. Let us consider the unbalanced equation ?? + ??? \u2192 ????? + ?? to understand these steps.<\/p>\n<ol>\n<li>Make boxes around the reactants and products as shown in the figure. The element or<\/li>\n<\/ol>\n<p>compound inside the box cannot be changed.<\/p>\n<p><strong>+ +<\/strong><\/p>\n<p>F2<\/p>\n<p>H2<\/p>\n<p>Fe2O4<\/p>\n<p>H2O<\/p>\n<ol>\n<li>Draw a table with the name of the elements and number of atoms as shown below.<\/li>\n<\/ol>\n<table>\n<tbody>\n<tr>\n<td><strong>Elements<\/strong><\/td>\n<td><strong>Number of Atoms in Reactants<\/strong><\/td>\n<td><strong>Number of Atoms in Products<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>Fe<\/strong><\/td>\n<td><strong>1<\/strong><\/td>\n<td><strong>3<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>H<\/strong><\/td>\n<td><strong>2<\/strong><\/td>\n<td><strong>2<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>O<\/strong><\/td>\n<td><strong>4<\/strong><\/td>\n<td><strong>1<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h2><span class=\"ez-toc-section\" id=\"Table_1\"><\/span>Table 1<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>According to table 1, the number of <strong>Oxygen <\/strong>and <strong>Iron <\/strong>atoms on the reactants side is<\/p>\n<p><strong>Not Equal <\/strong>to the number of atoms on the products side.<\/p>\n<ol>\n<li>Begin by balancing the atom of the element that has the highest number of atoms. Here, it&#8217;s <strong>Oxygen.<\/strong><\/li>\n<\/ol>\n<p>So, multiply ?<sub>2<\/sub>? with <strong>4 <\/strong>to balance the number of atoms of <strong>Oxygen<\/strong>.<\/p>\n<p>F2<\/p>\n<p>H2<\/p>\n<p><strong>+ <\/strong>4 <strong>+<\/strong><\/p>\n<p>Fe2O4<\/p>\n<p>H2O<\/p>\n<p>According to table 2, the number of <strong>Hydrogen <\/strong>and <strong>Iron <\/strong>atoms on the reactants side is<\/p>\n<p><strong>Not Equal <\/strong>to the number of atoms on the products side<\/p>\n<table>\n<tbody>\n<tr>\n<td><strong>Elements<\/strong><\/td>\n<td><strong>Number of Atoms in Reactants<\/strong><\/td>\n<td><strong>Number of Atoms in Products<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>Fe<\/strong><\/td>\n<td><strong>1<\/strong><\/td>\n<td><strong>3<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>H<\/strong><\/td>\n<td><strong>8<\/strong><\/td>\n<td><strong>2<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>O<\/strong><\/td>\n<td><strong>4<\/strong><\/td>\n<td><strong>4<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h2><span class=\"ez-toc-section\" id=\"Table_2\"><\/span>Table 2<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ol>\n<li>Multiply the ?? with <strong>4 <\/strong>to balance the number of atoms of <strong>Hydrogen<\/strong>.<\/li>\n<\/ol>\n<p>F2<\/p>\n<p>H2<\/p>\n<p><strong>+ <\/strong>4 <strong>+ <\/strong>4<\/p>\n<p>Fe2O4<\/p>\n<p>H2O<\/p>\n<p>According to table 3, the number of atoms of <strong>Oxygen <\/strong>and <strong>Hydrogen <\/strong>is now <strong>Equal<\/strong>, but the number of <strong>Iron <\/strong>atoms is <strong>Not Equal<\/strong>.<\/p>\n<table>\n<tbody>\n<tr>\n<td><strong>Elements<\/strong><\/td>\n<td><strong>Number of Atoms in Reactants<\/strong><\/td>\n<td><strong>Number of Atoms in Products<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>Fe<\/strong><\/td>\n<td><strong>1<\/strong><\/td>\n<td><strong>3<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>H<\/strong><\/td>\n<td><strong>8<\/strong><\/td>\n<td><strong>8<\/strong><\/td>\n<\/tr>\n<tr>\n<td><strong>O<\/strong><\/td>\n<td><strong>4<\/strong><\/td>\n<td><strong>4<\/strong><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h2><span class=\"ez-toc-section\" id=\"Table_3\"><\/span>Table 3<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ol>\n<li>To balance the number of <strong>Iron <\/strong>atoms, multiply <strong>Fe <\/strong>with <strong>3<\/strong>.<\/li>\n<\/ol>\n<p>3 <strong>+ <\/strong>4 <strong>+ <\/strong>4<\/p>\n<p>F2<\/p>\n<p>H2<\/p>\n<p>Fe2O4<\/p>\n<p>H2O<\/p>\n<p>According to table 4, the number of atoms of <strong>Oxygen, Hydrogen <\/strong>and <strong>Iron <\/strong>is now<\/p>\n<p><strong>Equal<\/strong>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Table of Contents Balancing a Chemical Equation Symbols of Physical States Gaseous Liquid Aqueous Solid Summary What\u2019s Next? In the [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"Balancing the chemical equations - Part 2","_yoast_wpseo_title":"Balancing Chemical Equations: How to Balance Chemistry Reactions","_yoast_wpseo_metadesc":"Learn how to balance chemical equations step by step. Explore chemical reaction balancing techniques and tools for chemistry problems.","custom_permalink":"class-10\/chemisry\/chemical-reactions-and-equations\/balancing-the-chemical-equations-part-2\/"},"categories":[53,59],"tags":[],"table_tags":[],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v17.9 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Balancing Chemical Equations: How to Balance Chemistry Reactions<\/title>\n<meta name=\"description\" content=\"Learn how to balance chemical equations step by step. 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