{"id":28671,"date":"2022-01-31T11:33:05","date_gmt":"2022-01-31T06:03:05","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/?p=28671"},"modified":"2022-01-31T11:33:05","modified_gmt":"2022-01-31T06:03:05","slug":"simple-equations-class-7-extra-questions-maths-chapter-4","status":"publish","type":"post","link":"https:\/\/infinitylearn.com\/surge\/study-material\/cbse-notes\/class-7\/maths\/simple-equations-class-7-extra-questions-maths-chapter-4\/","title":{"rendered":"Simple Equations Class 7 Extra Questions Maths Chapter 4"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_37 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" style=\"display: none;\"><label for=\"item\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input type=\"checkbox\" id=\"item\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1' style='display:block'><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse-notes\/class-7\/maths\/simple-equations-class-7-extra-questions-maths-chapter-4\/#Simple_Equations_Class_7_Extra_Questions_Maths_Chapter_4\" title=\"Simple Equations Class 7 Extra Questions Maths Chapter 4\">Simple Equations Class 7 Extra Questions Maths Chapter 4<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse-notes\/class-7\/maths\/simple-equations-class-7-extra-questions-maths-chapter-4\/#Simple_Equations_Class_7_Extra_Questions_Very_Short_Answer_Type\" title=\"Simple Equations Class 7 Extra Questions Very Short Answer Type\">Simple Equations Class 7 Extra Questions Very Short Answer Type<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse-notes\/class-7\/maths\/simple-equations-class-7-extra-questions-maths-chapter-4\/#Simple_Equations_Class_7_Extra_Questions_Short_Answer_Type\" title=\"Simple Equations Class 7 Extra Questions Short Answer Type\">Simple Equations Class 7 Extra Questions Short Answer Type<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"Simple_Equations_Class_7_Extra_Questions_Maths_Chapter_4\"><\/span>Simple Equations Class 7 Extra Questions Maths Chapter 4<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p><strong>Extra Questions for Class 7 Maths Chapter 4 Simple Equations<\/strong><\/p>\n<h3><span class=\"ez-toc-section\" id=\"Simple_Equations_Class_7_Extra_Questions_Very_Short_Answer_Type\"><\/span>Simple Equations Class 7 Extra Questions Very Short Answer Type<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Question 1.<br \/>\nWrite the following statements in the form of equations.<br \/>\n(a) The sum of four times a number and 5 gives a number five times of it.<br \/>\n(b) One-fourth of a number is 2 more than 5.<br \/>\nSolution:<br \/>\n(a) Let the number be x.<br \/>\nSum of 4x and 5 = 4x + 5<br \/>\nThe sum is 5x.<br \/>\nThe equation is 4x + 5 = 5x as required.<br \/>\n(b) Let the number be x.<br \/>\n\\(\\frac { 1 }{ 4 }\\)x = 5 + 2<br \/>\n\u21d2 \\(\\frac { 1 }{ 4 }\\)x = 7 as required.<\/p>\n<p>Question 2.<br \/>\nConvert the following equations in statement form:<br \/>\n(a) 5x = 20<br \/>\n(b) 3y + 7 = 1<br \/>\nSolution:<br \/>\n(a) Five times a number x gives 20.<br \/>\n(b) Add 7 to three times a number y gives 1.<\/p>\n<p>Question 3.<br \/>\nIf k + 7 = 10, find the value of 9k \u2013 50.<br \/>\nSolution:<br \/>\nk + 7 = 10<br \/>\n\u21d2 k = 10 \u2013 7 = 3<br \/>\nPut k = 3 in 9k \u2013 50, we get<br \/>\n9 \u00d7 3 \u2013 50 = 27 \u2013 50 = -23<br \/>\nThus the value of k = -23<\/p>\n<p>Question 4.<br \/>\nSolve the following equations and check the answers.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48042680641_ec98744cf8_o.png\" alt=\"Simple Equations Class 7 Extra Questions Maths Chapter 4 Q4\" width=\"302\" height=\"46\" \/><br \/>\nSolution:<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48042680726_dfcec2c90c_o.png\" alt=\"Simple Equations Class 7 Extra Questions Maths Chapter 4 Q4.1\" width=\"376\" height=\"427\" \/><br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48042776322_28634b493c_o.png\" alt=\"Simple Equations Class 7 Extra Questions Maths Chapter 4 Q4.2\" width=\"375\" height=\"384\" \/><\/p>\n<p>Question 5.<br \/>\nSolve the following equations:<br \/>\n3(y \u2013 2) = 2(y \u2013 1) \u2013 3<br \/>\nSolution:<br \/>\n3(y \u2013 2) = 2(y \u2013 1) \u2013 3<br \/>\n\u21d2 3y \u2013 6 = 2y \u2013 2 \u2013 3 (Removing the brackets)<br \/>\n\u21d2 3y \u2013 6 = 2y \u2013 5<br \/>\n\u21d2 3y \u2013 2y = 6 \u2013 5 (Transposing 6 to RHS and 2y to LHS)<br \/>\n\u21d2 y = 1<br \/>\nThus y = 1<\/p>\n<p>Question 6.<br \/>\nIf 5 is added to twice a number, the result is 29. Find the number.<br \/>\nSolution:<br \/>\nLet the required number be x.<br \/>\nStep I: 2x + 5<br \/>\nStep II: 2x + 5 = 29<br \/>\nSolving the equation, we get<br \/>\n2x + 5 = 29<br \/>\n\u21d2 2x = 29 \u2013 5 (Transposing 5 to RHS)<br \/>\n\u21d2 2x = 24<br \/>\n\u21d2 x = 12 (Dividing both sides by 2)<br \/>\n\u21d2 x = 12<br \/>\nThus the required number is 12.<\/p>\n<p>Question 7.<br \/>\nIf one-third of a number exceeds its one-fourth by 1, find the number.<br \/>\nSolution:<br \/>\nLet the required number be x.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48042680586_4dc783e81e_o.png\" alt=\"Simple Equations Class 7 Extra Questions Maths Chapter 4 Q7\" width=\"374\" height=\"168\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"Simple_Equations_Class_7_Extra_Questions_Short_Answer_Type\"><\/span>Simple Equations Class 7 Extra Questions Short Answer Type<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Question 8.<br \/>\nThe length of a rectangle is twice its breadth. If its perimeter is 60 cm, find the length and the breadth of the rectangle.<br \/>\nSolution:<br \/>\nLet the breadth of the rectangle be x cm.<br \/>\nits length = 2x<br \/>\nPerimeter = 2 (length + breadth) = 2(2x + x) = 2 \u00d7 3x = 6x<br \/>\nAs per the condition of the question, we have<br \/>\n6x = 60 \u21d2 x = 10<br \/>\nThus the required breadth = 10 cm<br \/>\nand the length = 10 \u00d7 2 = 20 cm.<\/p>\n<p>Question 9.<br \/>\nSeven times a number is 12 less than thirteen times the same number. Find the number.<br \/>\nSolution:<br \/>\nLet the required number be x.<br \/>\n7x = 13x \u2013 12<br \/>\n\u21d2 7x \u2013 13x = -12 (Transposing 13x to LHS)<br \/>\n\u21d2 -6x = -12<br \/>\n\u21d2 x = 2<br \/>\nThus, the required number is 2.<\/p>\n<p>Question 10.<br \/>\nThe present age of a son is half the present age of his father. Ten years ago, the father was thrice as old as his son. What are their present age?<br \/>\nSolution:<br \/>\nLet the present age of a father be x years.<br \/>\nSon\u2019s age = \\(\\frac { 1 }{ 2 }\\)x years<br \/>\n10 years ago, father\u2019s age was (x \u2013 10) years<br \/>\n10 years ago, son\u2019s age was (\\(\\frac { x }{ 2 }\\) \u2013 10) years<br \/>\nAs per the question, we have<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48042776187_0f58bf3dcd_o.png\" alt=\"Simple Equations Class 7 Extra Questions Maths Chapter 4 Q10\" width=\"374\" height=\"367\" \/><\/p>\n<p>Question 11.<br \/>\nThe sum of three consecutive multiples of 2 is 18. Find the numbers.<br \/>\nSolution:<br \/>\nLet the three consecutive multiples of 2 be 2x, 2x + 2 and 2x + 4.<br \/>\nAs per the conditions of the question, we have<br \/>\n2x + (2x + 2) + (2x + 4) = 18<br \/>\n\u21d2 2x + 2x + 2 + 2x + 4 = 18<br \/>\n\u21d2 6x + 6 = 18<br \/>\n\u21d2 6x = 18 \u2013 6 (Transposing 6 to RHS)<br \/>\n\u21d2 6x = 12<br \/>\n\u21d2 x = 2<br \/>\nThus, the required multiples are<br \/>\n2 \u00d7 2 = 4, 4 + 2 = 6, 6 + 2 = 8 i.e., 4, 6 and 8.<\/p>\n<p>Question 12.<br \/>\nEach of the 2 equal sides of an isosceles triangle is twice as large as the third side. If the perimeter of the triangle is 30 cm, find the length of each side of the triangle. [NCERT Exemplar]\nSolution:<br \/>\nLet the length of the third side be x cm.<br \/>\nEach equal side = 2x cm.<br \/>\nAs per the condition of the question, we have<br \/>\nPerimeter = x + 2x + 2x = 30<br \/>\n\u21d2 5x = 30<br \/>\n\u21d2 x = 6<br \/>\nThus, the third side of the triangle = 6 cm<br \/>\nand other two equal sides are 2 \u00d7 6 = 12 cm each<\/p>\n<p>Question 13.<br \/>\nA man travelled two-fifth of his journey by train, one-third by bus, one-fourth by car and the remaining 3 km on foot. What is the length of his total journey? [NCERT Exemplar]\nSolution:<br \/>\nLet the total length of total journey be x km.<br \/>\nDistance travelled by train = \\(\\frac { 2 }{ 5 }\\)x km<br \/>\nDistance travelled by bus = \\(\\frac { 1 }{ 3 }\\)x km<br \/>\nDistance travelled by car = \\(\\frac { 1 }{ 4 }\\)x km<br \/>\nRemaining distance = 3 km<br \/>\nAs per the question, we have<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48042776132_55f62cfbd7_o.png\" alt=\"Simple Equations Class 7 Extra Questions Maths Chapter 4 Q13\" width=\"371\" height=\"290\" \/><br \/>\nThus, the required journey = 180 km.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Simple Equations Class 7 Extra Questions Maths Chapter 4 Extra Questions for Class 7 Maths Chapter 4 Simple Equations Simple [&hellip;]<\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"Get Simple Equations Class 7 Extra Questions Maths Chapter 4 on Infinity Learn.","custom_permalink":"study-material\/cbse-notes\/class-7\/maths\/simple-equations-class-7-extra-questions-maths-chapter-4\/"},"categories":[92,13,21],"tags":[],"table_tags":[],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v17.9 - 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