{"id":30427,"date":"2022-01-29T15:59:33","date_gmt":"2022-01-29T10:29:33","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/?p=30427"},"modified":"2025-10-23T13:36:46","modified_gmt":"2025-10-23T08:06:46","slug":"arithmetic-progressions-class-10-extra-questions-maths-chapter-5","status":"publish","type":"post","link":"https:\/\/infinitylearn.com\/surge\/study-material\/maths\/class-10\/arithmetic-progressions-class-10-extra-questions-maths-chapter-5\/","title":{"rendered":"Important Questions for Class 10 Maths Chapter 5: Arithmetic Progression"},"content":{"rendered":"

Important questions for Class 10 Maths Chapter 5 on Arithmetic Progression are available here to help students get ready for the 2024-2025 board exams. These questions follow the NCERT book<\/a><\/strong> and CBSE syllabus<\/a><\/strong>. We’ve made these questions based on the exam style, past papers, exam trends, and the latest 2024-25 sample papers. Solving these questions can help students get high scores in their Maths exams. They can also check their answers using the provided solutions. So, it’s a good idea for students to practice these questions well. This will boost their confidence and improve their skills.<\/p>\n

Important Questions For Class 10 Chapter 5 With Solutions<\/h2>\n

Question:<\/strong> Define Arithmetic Progression (AP).<\/p>\n

Answer:<\/strong> Arithmetic Progression (AP) is a sequence of numbers in which the difference between consecutive terms is constant.<\/p>\n

Question:<\/strong> What is the common difference in an AP?<\/p>\n

Answer:<\/strong> The common difference in an AP is the constant value by which each term differs from its preceding term.<\/p>\n

Question: Which term of the AP 3, 15, 27, 39, \u2026 will be 132 more than its 54th term?<\/strong><\/p>\n

Answer: <\/strong>Given AP is: 3, 15, 27, 39, \u2026
\nFirst term, a = 3
\nCommon difference, d = a2<\/sub> \u2212 a1<\/sub> = 15 \u2212 3 = 12<\/p>\n

We know that,
\nan<\/sub> = a + (n \u2212 1) d<\/p>\n

Therefore,<\/p>\n

a54<\/sub> = a + (54 \u2212 1) d
\n= 3 + (53) (12)
\n= 3 + 636
\na54<\/sub> = 639<\/p>\n

We have to find the term of this AP.which is 132 more than a54<\/sub>, i.e. 771.
\nLet nth term be 771.
\nan<\/sub> = a + (n \u2212 1) d
\n771 = 3 + (n \u2212 1) 12
\n768 = (n \u2212 1) 12
\n\u21d2 (n \u2212 1) = 64
\n\u21d2 n = 65<\/p>\n

Therefore, the 65th term is 132 more than the 54th term of the given AP.<\/p>\n

Alternate Method:<\/strong><\/p>\n

Let nth term be 132 more than 54th term.
\nn = 54 + (132\/12)<\/p>\n

= 54 + 11<\/p>\n

= 65th term<\/p>\n

Question:<\/strong> If the first term of an AP is ‘a’ and the common difference is ‘d’, what is the nth term of the AP?<\/p>\n

Answer:<\/strong> The nth term<\/p>\n\ud835\udc47<\/mi>\ud835\udc5b<\/mi><\/msub><\/mrow><\/semantics><\/math>\n

T<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span> of an AP is given by the formula<\/p>\n\ud835\udc47<\/mi>\ud835\udc5b<\/mi><\/msub>=<\/mo>\ud835\udc4e<\/mi>+<\/mo>(<\/mo>\ud835\udc5b<\/mi>\u2212<\/mo>1<\/mn>)<\/mo>\ud835\udc51<\/mi><\/mrow><\/semantics><\/math>\n

T<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>+<\/span><\/span>(<\/span>n<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>d<\/span><\/span><\/span>.<\/p>\n

Question: Check whether \u2013 150 is a term of the AP: 11, 8, 5, 2 . . .<\/strong><\/p>\n

Answer:<\/strong> Given AP: 11, 8, 5, 2, \u2026<\/p>\n

First term, a = 11<\/p>\n

Common difference, d = a2<\/sub> \u2212 a1<\/sub> = 8 \u2212 11 = \u22123<\/p>\n

Let \u2212150 be the nth term of this AP.<\/p>\n

As we know, for an AP,<\/p>\n

an<\/sub> = a + (n \u2212 1) d<\/p>\n

-150 = 11 + (n \u2013 1)(-3)<\/p>\n

-150 = 11 \u2013 3n + 3<\/p>\n

\u21d2 -164 = -3n<\/p>\n

\u21d2 n = 164\/3<\/p>\n

Clearly, n is not an integer but a fraction.<\/p>\n

Therefore, \u2013 150 is not a term of the given AP.<\/p>\n

Question:<\/strong> How can you find the number of terms in an AP when given the first term, last term, and common difference?<\/p>\n

Answer:<\/strong> The number of terms in an AP can be found using the formula<\/p>\n\ud835\udc5b<\/mi>=<\/mo>\ud835\udc59<\/mi>\u2212<\/mo>\ud835\udc4e<\/mi><\/mrow>\ud835\udc51<\/mi><\/mfrac>+<\/mo>1<\/mn><\/mrow><\/semantics><\/math>\n

n<\/span>=<\/span><\/span>d<\/span><\/span><\/span>l<\/span>\u2212<\/span>a<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>+<\/span><\/span>1<\/span><\/span><\/span>, where<\/p>\n\ud835\udc4e<\/mi><\/mrow><\/semantics><\/math>\n

a<\/span><\/span><\/span> is the first term,<\/p>\n\ud835\udc59<\/mi><\/mrow><\/semantics><\/math>\n

l<\/span><\/span><\/span> is the last term, and<\/p>\n\ud835\udc51<\/mi><\/mrow><\/semantics><\/math>\n

d<\/span><\/span><\/span> is the common difference.<\/p>\n

Question:<\/strong> What is the sum of the first ‘n’ terms of an AP?<\/p>\n

Answer:<\/strong> The sum<\/p>\n\ud835\udc46<\/mi>\ud835\udc5b<\/mi><\/msub><\/mrow><\/semantics><\/math>\n

S<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span> of the first ‘n’ terms of an AP is given by the formula<\/p>\n\ud835\udc46<\/mi>\ud835\udc5b<\/mi><\/msub>=<\/mo>\ud835\udc5b<\/mi>2<\/mn><\/mfrac>(<\/mo>2<\/mn>\ud835\udc4e<\/mi>+<\/mo>(<\/mo>\ud835\udc5b<\/mi>\u2212<\/mo>1<\/mn>)<\/mo>\ud835\udc51<\/mi>)<\/mo><\/mrow><\/semantics><\/math>\n

S<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span><\/span>n<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>(<\/span>2<\/span>a<\/span>+<\/span><\/span>(<\/span>n<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>d<\/span>)<\/span><\/span><\/span>.<\/p>\n

Question:<\/strong> If the 5th term of an AP is 17 and the 10th term is 32, find the common difference.<\/p>\n

Answer:<\/strong><\/p>\n\ud835\udc51<\/mi>=<\/mo>\ud835\udc47<\/mi>10<\/mn><\/msub>\u2212<\/mo>\ud835\udc47<\/mi>5<\/mn><\/msub><\/mrow>10<\/mn>\u2212<\/mo>5<\/mn><\/mrow><\/mfrac>=<\/mo>32<\/mn>\u2212<\/mo>17<\/mn><\/mrow>5<\/mn><\/mfrac>=<\/mo>3<\/mn><\/mrow><\/semantics><\/math>\n

d<\/span>=<\/span><\/span>10\u2212<\/span>5<\/span><\/span>T<\/span>10<\/span>\u200b<\/span><\/span>\u2212<\/span>T<\/span>5<\/span>\u200b<\/span><\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>5<\/span><\/span>32\u2212<\/span>17<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>3<\/span><\/span><\/span>.<\/p>\n

Question:<\/strong> If the sum of 4th and 9th terms of an AP is 60 and the common difference is 3, find the first term.<\/p>\n

Answer:<\/strong> Using<\/p>\n\ud835\udc47<\/mi>4<\/mn><\/msub>=<\/mo>\ud835\udc4e<\/mi>+<\/mo>3<\/mn>(<\/mo>4<\/mn>\u2212<\/mo>1<\/mn>)<\/mo><\/mrow><\/semantics><\/math>\n

T<\/span>4<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>+<\/span><\/span>3<\/span>(<\/span>4<\/span>\u2212<\/span><\/span>1<\/span>)<\/span><\/span><\/span> and<\/p>\n\ud835\udc47<\/mi>9<\/mn><\/msub>=<\/mo>\ud835\udc4e<\/mi>+<\/mo>3<\/mn>(<\/mo>9<\/mn>\u2212<\/mo>1<\/mn>)<\/mo><\/mrow><\/semantics><\/math>\n

T<\/span>9<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>+<\/span><\/span>3<\/span>(<\/span>9<\/span>\u2212<\/span><\/span>1<\/span>)<\/span><\/span><\/span>, we get<\/p>\n\ud835\udc4e<\/mi>=<\/mo>8<\/mn><\/mrow><\/semantics><\/math>\n

a<\/span>=<\/span><\/span>8<\/span><\/span><\/span>.<\/p>\n

Question:<\/strong> If the 12th term of an AP is 29 and the common difference is 2, find the 7th term.<\/p>\n

Answer:<\/strong> Using<\/p>\n\ud835\udc47<\/mi>7<\/mn><\/msub>=<\/mo>\ud835\udc4e<\/mi>+<\/mo>6<\/mn>\ud835\udc51<\/mi><\/mrow><\/semantics><\/math>\n

T<\/span>7<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>+<\/span><\/span>6<\/span>d<\/span><\/span><\/span>, we get<\/p>\n\ud835\udc47<\/mi>7<\/mn><\/msub>=<\/mo>29<\/mn>\u2212<\/mo>10<\/mn>=<\/mo>19<\/mn><\/mrow><\/semantics><\/math>\n

T<\/span>7<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>29<\/span>\u2212<\/span><\/span>10<\/span>=<\/span><\/span>19<\/span><\/span><\/span>.<\/p>\n

Question:<\/strong> If the first term of an AP is 4 and the 8th term is 22, find the common difference.<\/p>\n

Answer:<\/strong><\/p>\n\ud835\udc51<\/mi>=<\/mo>\ud835\udc47<\/mi>8<\/mn><\/msub>\u2212<\/mo>\ud835\udc4e<\/mi><\/mrow>8<\/mn>\u2212<\/mo>1<\/mn><\/mrow><\/mfrac>=<\/mo>22<\/mn>\u2212<\/mo>4<\/mn><\/mrow>7<\/mn><\/mfrac>=<\/mo>2<\/mn><\/mrow><\/semantics><\/math>\n

d<\/span>=<\/span><\/span>8\u2212<\/span>1<\/span><\/span>T<\/span>8<\/span>\u200b<\/span><\/span>\u2212<\/span>a<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>7<\/span><\/span>22\u2212<\/span>4<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span><\/span><\/span>.<\/p>\n

Question:<\/strong> What is the formula for the nth term of an AP in terms of the first term, common difference, and number of terms?<\/p>\n

Answer:<\/strong><\/p>\n\ud835\udc47<\/mi>\ud835\udc5b<\/mi><\/msub>=<\/mo>\ud835\udc4e<\/mi>+<\/mo>(<\/mo>\ud835\udc5b<\/mi>\u2212<\/mo>1<\/mn>)<\/mo>\ud835\udc51<\/mi><\/mrow><\/semantics><\/math>\n

T<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>+<\/span><\/span>(<\/span>n<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>d<\/span><\/span><\/span>.<\/p>\n

Question:<\/strong> How can you determine if a given sequence of numbers is an AP?<\/p>\n

Answer:<\/strong> Check if the difference between consecutive terms is constant. If it is, the sequence is an AP.<\/p>\n

Question:<\/strong> What is the sum of an AP if its first term is 3, common difference is 4, and it has 10 terms?<\/p>\n

Answer:<\/strong><\/p>\n\ud835\udc46<\/mi>10<\/mn><\/msub>=<\/mo>10<\/mn>2<\/mn><\/mfrac>(<\/mo>2<\/mn>(<\/mo>3<\/mn>)<\/mo>+<\/mo>(<\/mo>10<\/mn>\u2212<\/mo>1<\/mn>)<\/mo>(<\/mo>4<\/mn>)<\/mo>)<\/mo>=<\/mo>245<\/mn><\/mrow><\/semantics><\/math>\n

S<\/span>10<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span><\/span>10<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>(<\/span>2<\/span>(<\/span>3<\/span>)<\/span>+<\/span><\/span>(<\/span>10<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>(<\/span>4<\/span>))<\/span>=<\/span><\/span>245<\/span><\/span><\/span>.<\/p>\n

Also Check: Surface Areas and Volumes Class 10 Extra Questions Maths Chapter 13<\/a><\/strong><\/p>\n

Question:<\/strong> If the sum of first ‘n’ terms of an AP is<\/p>\n\ud835\udc46<\/mi>\ud835\udc5b<\/mi><\/msub><\/mrow><\/semantics><\/math>\n

S<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span>, what is<\/p>\n\ud835\udc46<\/mi>\ud835\udc5b<\/mi><\/msub>\u2212<\/mo>\ud835\udc46<\/mi>\ud835\udc5b<\/mi>\u2212<\/mo>1<\/mn><\/mrow><\/msub><\/mrow><\/semantics><\/math>\n

S<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>S<\/span>n<\/span>\u2212<\/span>1<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span>?<\/p>\n

Answer:<\/strong><\/p>\n\ud835\udc46<\/mi>\ud835\udc5b<\/mi><\/msub>\u2212<\/mo>\ud835\udc46<\/mi>\ud835\udc5b<\/mi>\u2212<\/mo>1<\/mn><\/mrow><\/msub>=<\/mo>\ud835\udc47<\/mi>\ud835\udc5b<\/mi><\/msub><\/mrow><\/semantics><\/math>\n

S<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>S<\/span>n<\/span>\u2212<\/span>1<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>T<\/span>n<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span>.<\/p>\n

Question:<\/strong> What is the sum of all odd terms in an AP?<\/p>\n

Answer:<\/strong><\/p>\n\ud835\udc46<\/mi>odd<\/mtext><\/msub>=<\/mo>\ud835\udc5b<\/mi>2<\/mn><\/mfrac>(<\/mo>2<\/mn>\ud835\udc4e<\/mi>+<\/mo>(<\/mo>\ud835\udc5b<\/mi>\u2212<\/mo>1<\/mn>)<\/mo>\ud835\udc51<\/mi>)<\/mo><\/mrow><\/semantics><\/math>\n

S<\/span>odd<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>2<\/span><\/span>n<\/span><\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>(<\/span>2<\/span>a<\/span>+<\/span><\/span>(<\/span>n<\/span>\u2212<\/span><\/span>1<\/span>)<\/span>d<\/span>)<\/span><\/span><\/span> where ‘n’ is the number of odd terms.<\/p>\n

Question: How many terms of the AP : 24, 21, 18, . . . must be taken so that their sum is 78?<\/strong><\/p>\n

Answer: <\/strong>Given AP: 24, 21, 18,\u2026<\/p>\n

Here, a = 24, d = 21 \u2013 24 = \u20133, Sn<\/sub> = 78. We need to find n.
\nWe know that;<\/p>\n

Sn<\/sub> = n\/2[2a + (n \u2013 1)d]\n

So, 78 = n\/2 [48 + (n \u2013 1)(-3)]\n

78 = n\/2 [51 \u2013 3n]\n

156 = 51n \u2013 3n2<\/sup><\/p>\n

3n2<\/sup> \u2013 51n + 156 = 0<\/p>\n

n2<\/sup> \u2013 17n + 52 = 0<\/p>\n

n2<\/sup> \u2013 13n \u2013 4n + 52 = 0<\/p>\n

n(n \u2013 13) \u2013 4(n \u2013 13) = 0<\/p>\n

(n \u2013 4) (n \u2013 13) = 0<\/p>\n

n = 4 or 13
\nBoth values of n are admissible. So, the number of terms is either 4 or 13.<\/p>\n

Question:<\/strong> If the 3rd term of an AP is 8 and the 6th term is 20, find the 10th term.<\/p>\n

Answer:<\/strong> Using<\/p>\n\ud835\udc47<\/mi>3<\/mn><\/msub>=<\/mo>\ud835\udc4e<\/mi>+<\/mo>2<\/mn>\ud835\udc51<\/mi><\/mrow><\/semantics><\/math>\n

T<\/span>3<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>+<\/span><\/span>2<\/span>d<\/span><\/span><\/span> and<\/p>\n\ud835\udc47<\/mi>6<\/mn><\/msub>=<\/mo>\ud835\udc4e<\/mi>+<\/mo>5<\/mn>\ud835\udc51<\/mi><\/mrow><\/semantics><\/math>\n

T<\/span>6<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>+<\/span><\/span>5<\/span>d<\/span><\/span><\/span>, we find<\/p>\n\ud835\udc47<\/mi>10<\/mn><\/msub>=<\/mo>34<\/mn><\/mrow><\/semantics><\/math>\n

T<\/span>10<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>34<\/span><\/span><\/span>.<\/p>\n

Question:<\/strong> What is the 30th term of an AP if the 10th term is 20 and the common difference is 3?<\/p>\n

Answer:<\/strong><\/p>\n\ud835\udc47<\/mi>30<\/mn><\/msub>=<\/mo>20<\/mn>+<\/mo>20<\/mn>(<\/mo>3<\/mn>)<\/mo>=<\/mo>80<\/mn><\/mrow><\/semantics><\/math>\n

T<\/span>30<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>20<\/span>+<\/span><\/span>20<\/span>(<\/span>3<\/span>)<\/span>=<\/span><\/span>80<\/span><\/span><\/span>.<\/p>\n

Question:<\/strong> How can you find the common difference if given the first and third terms of an AP?<\/p>\n

Answer:<\/strong><\/p>\n\ud835\udc51<\/mi>=<\/mo>\ud835\udc47<\/mi>3<\/mn><\/msub>\u2212<\/mo>\ud835\udc4e<\/mi><\/mrow><\/semantics><\/math>\n

d<\/span>=<\/span><\/span>T<\/span>3<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>a<\/span><\/span><\/span>.<\/p>\n

Question:<\/strong> If the sum of the first 5 terms of an AP is 60 and the sum of the first 10 terms is 210, find the sum of the next 5 terms.<\/p>\n

Answer:<\/strong><\/p>\n\ud835\udc46<\/mi>10<\/mn><\/msub>\u2212<\/mo>\ud835\udc46<\/mi>5<\/mn><\/msub>=<\/mo>210<\/mn>\u2212<\/mo>60<\/mn>=<\/mo>150<\/mn><\/mrow><\/semantics><\/math>\n

S<\/span>10<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>\u2212<\/span><\/span>S<\/span>5<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>210<\/span>\u2212<\/span><\/span>60<\/span>=<\/span><\/span>150<\/span><\/span><\/span>.<\/p>\n

Question:<\/strong> What is the 12th term of an AP if the 15th term is 55 and the common difference is 3?<\/p>\n

Answer:<\/strong><\/p>\n\ud835\udc47<\/mi>12<\/mn><\/msub>=<\/mo>55<\/mn>\u2212<\/mo>3<\/mn>(<\/mo>15<\/mn>\u2212<\/mo>12<\/mn>)<\/mo>=<\/mo>46<\/mn><\/mrow><\/semantics><\/math>\n

T<\/span>12<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>55<\/span>\u2212<\/span><\/span>3<\/span>(<\/span>15<\/span>\u2212<\/span><\/span>12<\/span>)<\/span>=<\/span><\/span>46<\/span><\/span><\/span>.<\/p>\n

Question:<\/strong> If the 4th term of an AP is 9 and the 7th term is 15, find the first term and common difference.<\/p>\n

Answer:<\/strong> Using<\/p>\n\ud835\udc47<\/mi>4<\/mn><\/msub>=<\/mo>\ud835\udc4e<\/mi>+<\/mo>3<\/mn>\ud835\udc51<\/mi><\/mrow><\/semantics><\/math>\n

T<\/span>4<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>+<\/span><\/span>3<\/span>d<\/span><\/span><\/span> and<\/p>\n\ud835\udc47<\/mi>7<\/mn><\/msub>=<\/mo>\ud835\udc4e<\/mi>+<\/mo>6<\/mn>\ud835\udc51<\/mi><\/mrow><\/semantics><\/math>\n

T<\/span>7<\/span><\/span><\/span>\u200b<\/span><\/span><\/span><\/span><\/span>=<\/span><\/span>a<\/span>+<\/span><\/span>6<\/span>d<\/span><\/span><\/span>, we find<\/p>\n\ud835\udc4e<\/mi>=<\/mo>3<\/mn><\/mrow><\/semantics><\/math>\n

a<\/span>=<\/span><\/span>3<\/span><\/span><\/span> and<\/p>\n\ud835\udc51<\/mi>=<\/mo>2<\/mn><\/mrow><\/semantics><\/math>\n

d<\/span>=<\/span><\/span>2<\/span><\/span><\/span>.<\/p>\n","protected":false},"excerpt":{"rendered":"

Important questions for Class 10 Maths Chapter 5 on Arithmetic Progression are available here to help students get ready for […]<\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"Arithmetic Progressions Class 10","_yoast_wpseo_title":"Important Questions For Class 10 Chapter 5 With Solutions - Arithmetic Progression","_yoast_wpseo_metadesc":"Get Arithmetic Progressions Class 10 Extra Questions Maths Chapter. 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