{"id":30985,"date":"2022-01-30T21:09:19","date_gmt":"2022-01-30T15:39:19","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/?p=30985"},"modified":"2024-03-05T11:24:20","modified_gmt":"2024-03-05T05:54:20","slug":"cbse-previous-year-question-papers-class-10-maths-2018","status":"publish","type":"post","link":"https:\/\/infinitylearn.com\/surge\/cbse\/study-materials\/maths\/previous-year-question-papers-class-10-maths-2018\/","title":{"rendered":"CBSE Previous Year Question Papers Class 10 Maths 2018"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_37 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" style=\"display: none;\"><label for=\"item\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input type=\"checkbox\" id=\"item\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1' style='display:block'><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/infinitylearn.com\/surge\/cbse\/study-materials\/maths\/previous-year-question-papers-class-10-maths-2018\/#CBSE_Previous_Year_Question_Papers_Class_10_Maths_2018\" title=\"CBSE Previous Year Question Papers Class 10 Maths 2018\">CBSE Previous Year Question Papers Class 10 Maths 2018<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/infinitylearn.com\/surge\/cbse\/study-materials\/maths\/previous-year-question-papers-class-10-maths-2018\/#CBSE_Previous_Year_Question_Papers_Class_10_Maths_2018_Set_I\" title=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Set I\">CBSE Previous Year Question Papers Class 10 Maths 2018 Set I<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_Previous_Year_Question_Papers_Class_10_Maths_2018\"><\/span>CBSE Previous Year Question Papers Class 10 Maths 2018<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Time Allowed: 3 hours<br \/>\nMaximum Marks: 80<\/p>\n<p>General Instructions:<\/p>\n<ul>\n<li>All questions are compulsory.<\/li>\n<li>This question paper consists of 30 questions divided into four sections- A, B, C and D.<\/li>\n<li>Section A contains 6 questions of 1 mark each, Section B contains 6 questions of 2 marks each, Section C contains 10 questions of 3 marks each and Section D contains 8 questions of 4 marks each.<\/li>\n<li>There is no overall choice. However, an internal choice has been provided in two questions of 1 mark each, two questions of 2 marks each, four questions of 3 marks each and three questions of 4 marks each. You have to attempt only one of the alternative in all such questions.<\/li>\n<li>Use of calculators is not permitted.<\/li>\n<\/ul>\n<p style=\"text-align: center;\">CBSE Sample Papers Class 10 Maths<\/p>\n<h3><span class=\"ez-toc-section\" id=\"CBSE_Previous_Year_Question_Papers_Class_10_Maths_2018_Set_I\"><\/span>CBSE Previous Year Question Papers Class 10 Maths 2018 Set I<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>Section \u2013 A<\/strong><\/p>\n<p>Question 1.<br \/>\nIf x = 3 is one root of the quadratic equation x<sup>2<\/sup> \u2013 2kx \u2013 6 = 0, then find the value of k. [1]\nSolution:<br \/>\nGiven quadratic equation is, x<sup>2<\/sup> \u2013 2kx \u2013 6 = 0<br \/>\nx = 3 is a root of above equation, then<br \/>\n(3)<sup>2<\/sup> \u2013 2k (3) \u2013 6 = 0<br \/>\n\u21d2 9 \u2013 6k \u2013 6 = 0<br \/>\n\u21d2 3 \u2013 6k = 0<br \/>\n\u21d2 3 = 6k<br \/>\n\u21d2 k = \\(\\frac { 3 }{ 6 }\\) = \\(\\frac { 1 }{ 2 }\\)<br \/>\n\u21d2 k = \\(\\frac { 1 }{ 2 }\\)<\/p>\n<p>Question 2.<br \/>\nWhat is the HCF of the smallest prime number and the smallest composite number? [1]\nSolution:<br \/>\nSmallest prime number = 2<br \/>\nSmallest composite number = 4<br \/>\nPrime factorisation of 2 is 1 \u00d7 2<br \/>\nPrime factorisation of 4 is 1 \u00d7 2<sup>2<\/sup><br \/>\nHCF (2, 4) = 2<\/p>\n<p>Question 3.<br \/>\nFind the distance of a point P(x, y) from the origin. [1]\nSolution:<br \/>\nThe given point is P (x, y).<br \/>\nThe origin is O (0, 0)<br \/>\nThe distance of point P from the origin,<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363766087_917e2d856a_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q3\" width=\"253\" height=\"134\" \/><\/p>\n<p>Question 4.<br \/>\nIn an AP if the common difference (d) = -4 and the seventh term (a<sub>7<\/sub>) is 4, then find the first term. [1]\nSolution:<br \/>\nGiven,<br \/>\nd = -4, a<sub>7<\/sub> = 4<br \/>\na + 6d = 4<br \/>\n\u21d2 a + 6(-4) = 4<br \/>\n\u21d2 a \u2013 24 = 4<br \/>\n\u21d2 a = 4 + 24<br \/>\n\u21d2 a = 28<\/p>\n<p>Question 5.<br \/>\nWhat is the value of (cos<sup>2<\/sup> 67\u00b0 \u2013 sin<sup>2<\/sup> 23\u00b0) ? [1]\nSolution:<br \/>\nWe have, cos<sup>2<\/sup> 67\u00b0 \u2013 sin<sup>2<\/sup> 23\u00b0<br \/>\n= cos<sup>2<\/sup> 67\u00b0 \u2013 cos<sup>2<\/sup> (90\u00b0 \u2013 23\u00b0) [\u2235 sin (90\u00b0 \u2013 \u03b8) = cos \u03b8]\n= cos<sup>2<\/sup> 67\u00b0 \u2013 cos<sup>2<\/sup> 67\u00b0<br \/>\n= 0<\/p>\n<p>Question 6.<br \/>\nGiven \u0394ABC ~ \u0394PQR, if \\(\\frac { AB }{ PQ }\\) = \\(\\frac { 1 }{ 3 }\\), then find \\(\\frac { ar\\triangle ABC }{ ar\\triangle PQR }\\)<br \/>\nSolution:<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363630426_5095aa4ec7_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q6\" width=\"294\" height=\"208\" \/><\/p>\n<p><strong>Section \u2013 B<\/strong><\/p>\n<p>Question 7.<br \/>\nGiven that \u221a2 is irrational, prove that (5 + 3\u221a2) is an irrational number. [2]\nSolution:<br \/>\nGiven, \u221a2 is an irrational number.<br \/>\nLet \u221a2 = m<br \/>\nSuppose, 5 + 3\u221a2 is a rational number.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363630451_cd95527e03_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q7\" width=\"370\" height=\"257\" \/><br \/>\nBut \\(\\frac { a-5b }{ 3b }\\) is rational number, so m is rational number which contradicts the fact that m = \u221a2 is irrational number.<br \/>\nSo, our supposition is wrong.<br \/>\nHence, 5 + 3\u221a2 is also irrational.<br \/>\nHence Proved.<\/p>\n<p>Question 8.<br \/>\nIn fig. 1, ABCD is a rectangle. Find the values of x and y. [2]\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363766242_8fea40aa64_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q8\" width=\"277\" height=\"198\" \/><br \/>\nSolution:<br \/>\nGiven, ABCD is a rectangle.<br \/>\nAB = CD<br \/>\n\u21d2 30 = x + y<br \/>\nor x + y = 30 \u2026(i)<br \/>\nSimilarly, AD = BC<br \/>\n\u21d2 14 = x \u2013 y<br \/>\nor x \u2013 y = 14 \u2026(ii)<br \/>\nOn adding eq. (i) and (ii), we get<br \/>\n2x = 44<br \/>\n\u21d2 x = 22<br \/>\nPutting the value of x in eq. (i), we get<br \/>\n22 + y = 30<br \/>\n\u21d2 y = 30 \u2013 22<br \/>\n\u21d2 y = 8<br \/>\nSo, x = 22, y = 8.<\/p>\n<p>Question 9.<br \/>\nFind the sum of the first 8 multiples of 3. [2]\nSolution:<br \/>\nFirst 8 multiples of 3 are 3, 6, 9,\u2026.. up to 8 terms<br \/>\nWe can observe that the above series is an AP with<br \/>\na = 3, d = 6 \u2013 3 = 3, n = 8<br \/>\nSum of n terms of an A.P is given by,<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363766347_6b3d3f0c4c_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q9\" width=\"231\" height=\"250\" \/><\/p>\n<p>Question 10.<br \/>\nFind the ratio in which P(4, m) divides the line segment joining the points A(2, 3) and B(6, -3). Hence find m. [2]\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363766382_90b4c54e0b_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q10\" width=\"305\" height=\"58\" \/><br \/>\nSolution:<br \/>\nLet P divides line segment AB in the ratio k : 1<br \/>\nCoordinates of P<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363766482_a4e7e2d3f5_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q10.1\" width=\"376\" height=\"527\" \/><\/p>\n<p>Question 11.<br \/>\nTwo different dice are tossed together. Find the probability:<br \/>\n(i) of getting a doublet.<br \/>\n(ii) of getting a sum 10, of the numbers on the two dice. [2]\nSolution:<br \/>\nTotal outcomes on tossing two different dice = 36<br \/>\n(i) A: getting a doublet<br \/>\nA = {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)}<br \/>\nNumber of favourable outcomes of A = 6<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363766517_986e2ffc51_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q11\" width=\"251\" height=\"108\" \/><br \/>\n(ii) B: getting a sum 10.<br \/>\nB = {(4, 6), (5, 5), (6, 4)}<br \/>\nNumber of favourable outcomes of B = 3<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363766512_c1bb910306_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q11.1\" width=\"249\" height=\"109\" \/><\/p>\n<p>Question 12.<br \/>\nAn integer is chosen at random between 1 and 100. Find the probability that it is:<br \/>\n(i) divisible by 8.<br \/>\n(ii) not divisible by 8. [2]\nSolution:<br \/>\nThe total number are 2, 3, 4, \u2026\u2026.. 99<br \/>\n(i) Let E be the event of getting a number divisible by 8.<br \/>\nE = {8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96} = 12<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363766632_f68b074dc3_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q12\" width=\"254\" height=\"110\" \/><br \/>\n(ii) Let E\u2019 be the event of getting a number not divisible by 8.<br \/>\nThen, P(E\u2019) = 1 \u2013 P(E) = 1 \u2013 0.1224 = 0.8756<\/p>\n<p><strong>Section \u2013 C<\/strong><\/p>\n<p>Question 13.<br \/>\nFind HCF and LCM of 404 and 96 and verify that HCF \u00d7 LCM = Product of the two given numbers. [3]\nSolution:<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363630991_a836382f42_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q13\" width=\"204\" height=\"193\" \/><br \/>\nPrime factorization of 404 = 2 \u00d7 2 \u00d7 101<br \/>\nPrime factorization of 96 = 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 3<br \/>\nHCF = 2 \u00d7 2 = 4<br \/>\nAnd LCM = 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 2 \u00d7 3 \u00d7 101 = 9696<br \/>\nHCF = 4, LCM = 9696<br \/>\nVerification:<br \/>\nHCF \u00d7 LCM = Product of the two given numbers<br \/>\n4 \u00d7 9696 = 404 \u00d7 96<br \/>\n38784 = 38784<br \/>\nHence Verified.<\/p>\n<p>Question 14.<br \/>\nFind all zeroes of the polynomial (2x<sup>4<\/sup> \u2013 9x<sup>3<\/sup> + 5x<sup>2<\/sup> + 3x \u2013 1) if two of its zeroes are (2 + \u221a3) and (2 \u2013 \u221a3). [3]\nSolution:<br \/>\nHere, p(x) = 2x<sup>4<\/sup> \u2013 9x<sup>3<\/sup> + 5x<sup>2<\/sup> + 3x \u2013 1<br \/>\nAnd two of its zeroes are (2 + \u221a3) and (2 \u2013 \u221a3).<br \/>\nQuadratic polynomial with zeroes is given by,<br \/>\n{x \u2013 (2 + \u221a3)}. {x \u2013 (2 \u2013 \u221a3)}<br \/>\n\u21d2 (x \u2013 2 \u2013 \u221a3) (x \u2013 2 + \u221a3)<br \/>\n\u21d2 (x \u2013 2)<sup>2<\/sup> \u2013 (\u221a3)<sup>2<\/sup><br \/>\n\u21d2 x<sup>2<\/sup> \u2013 4x + 4 \u2013 3<br \/>\n\u21d2 x<sup>2<\/sup> \u2013 4x + 1 = g(x) (say)<br \/>\nNow, g(x) will be a factor of p(x) so g(x) will be divisible by p(x)<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363766707_da3ce9ac09_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q14\" width=\"313\" height=\"278\" \/><br \/>\nFor other zeroes,<br \/>\n2x<sup>2<\/sup> \u2013 x \u2013 1 = 0<br \/>\n2x<sup>2<\/sup> \u2013 2x + x \u2013 1 = 0<br \/>\nor 2x (x \u2013 1) + 1 (x \u2013 1) = 0<br \/>\n(x \u2013 1) (2a + 1) = 0<br \/>\nx \u2013 1 = 0 and 2x + 1 = 0<br \/>\nx = 1, x = \\(\\frac { -1 }{ 2 }\\)<br \/>\nZeroes of p(x) are<br \/>\n1, \\(\\frac { -1 }{ 2 }\\), 2 + \u221a3 and 2 \u2013 \u221a3.<\/p>\n<p>Question 15.<br \/>\nIf A(-2, 1) and B(a, 0), C(4, b) and D( 1, 2) are the vertices of a parallelogram ABCD, find the values of a and b. Hence find the lengths of its sides. [3]\nOR<br \/>\nIf A(-5, 7), B(-4, -5), C(-1, -6) and D(4, 5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD.<br \/>\nSolution:<br \/>\nGiven ABCD is a parallelogram.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363766912_3771d4ea9c_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q15\" width=\"338\" height=\"529\" \/><br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363766942_6050e4beb2_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q15.1\" width=\"370\" height=\"505\" \/><br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363631156_d85f12f9a8_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q15.2\" width=\"374\" height=\"561\" \/><br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363766932_255888901c_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q15.3\" width=\"371\" height=\"620\" \/><br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363766977_0f60ce6a06_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q15.4\" width=\"228\" height=\"114\" \/><\/p>\n<p>Question 16.<br \/>\nA plane left 30 minutes late than its scheduled time and in order to reach the destination 1500 km away in time, it had to increase its speed by 100 km\/h from the usual speed. Find its usual speed. [3]\nSolution:<br \/>\nLet the usual speed of plane be x km\/h.<br \/>\nIncreased speed = (x + 100) km\/h.<br \/>\nDistance to cover = 1500 km.<br \/>\nTime taken by plane with usual speed = \\(\\frac { 1500 }{ x }\\) hr<br \/>\nTime taken by plane with increased speed = \\(\\frac { 1500 }{ 100+x }\\)<br \/>\nAccording to the question,<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767022_fd08da94dc_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q16\" width=\"245\" height=\"238\" \/><br \/>\nx<sup>2<\/sup> + 100x = 300000<br \/>\nx<sup>2<\/sup> + 100x \u2013 300000 = 0<br \/>\nx<sup>2<\/sup> + 600x \u2013 500x \u2013 300000 = 0<br \/>\nx(x + 600) \u2013 500(x + 600) = 0<br \/>\n(x + 600) (x \u2013 500) = 0<br \/>\nEither x + 600 = 0 \u21d2 x = -600 (Rejected)<br \/>\nor x \u2013 500 = 0 \u21d2 x = 500<br \/>\nUsual speed of plane = 500 km\/hr.<\/p>\n<p>Question 17.<br \/>\nProve that the area of an equilateral triangle described on one side of the square is equal to half the area of the equilateral triangle described on one of its diagonal. [3]\nOR<br \/>\nIf the area of two similar triangles is equal, prove that they are congruent.<br \/>\nSolution:<br \/>\nLet ABCD be a square with side \u2018a\u2019.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767062_42609c1e8d_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q17\" width=\"372\" height=\"513\" \/><br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767142_c736bd0f2a_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q17.1\" width=\"381\" height=\"635\" \/><br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363631311_71497c0c0f_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q17.2\" width=\"377\" height=\"416\" \/><\/p>\n<p>Question 18.<br \/>\nProve that the lengths of tangents drawn from an external point of a circle are equal. [3]\nSolution:<br \/>\nGiven: A circle with centre O on which two tangents PM and PN are drawn from an external point P.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363631346_910a507db9_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q18\" width=\"291\" height=\"162\" \/><br \/>\nTo Prove: PM = PN<br \/>\nConstruction: Join OM, ON and OP<br \/>\nProof: Since tangent and radius are perpendicular at point of contact,<br \/>\n\u2220OMP = \u2220ONP = 90\u00b0<br \/>\nIn \u0394POM and \u0394PON,<br \/>\nOM = ON (Radii)<br \/>\n\u2220OMP = \u2220ONP<br \/>\nPO = OP (Common)<br \/>\n\u0394OMP = \u0394ONP (RHS cong.)<br \/>\nPM = PN (C.P.C.T)<br \/>\nHence Proved.<\/p>\n<p>Question 19.<br \/>\nIf 4 tan \u03b8 = 3, evaluate \\(\\left( \\frac { 4sin\\theta -cos\\theta +1 }{ 4sin\\theta +cos\\theta -1 } \\right)\\)<br \/>\nor<br \/>\nIf tan 2A = cot (A \u2013 18\u00b0), where 2A is an acute angle, find the value of A.<br \/>\nSolution:<br \/>\nGiven, 4 tan \u03b8 = 3<br \/>\n\u21d2 tan \u03b8 = \\(\\frac { 3 }{ 4 }\\) (= \\(\\frac { P }{ B }\\))<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363631421_00a9e30d6f_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q19\" width=\"338\" height=\"506\" \/><br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767227_2dd9208c8b_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q19.1\" width=\"318\" height=\"410\" \/><br \/>\nOR<br \/>\nGiven, tan 2A = cot (A \u2013 18\u00b0)<br \/>\n\u21d2 cot (90\u00b0 \u2013 2A) = cot (A \u2013 18\u00b0)<br \/>\n[\u2235 tan \u03b8 = cot (90\u00b0 \u2013 \u03b8)]\n\u21d2 90\u00b0 \u2013 2A = A \u2013 18\u00b0<br \/>\n\u21d2 90\u00b0 + 18\u00b0 = A + 2A<br \/>\n\u21d2 108\u00b0 = 3A<br \/>\n\u21d2 A = 36\u00b0<\/p>\n<p>Question 20.<br \/>\nFind the area of the shaded region in Fig. 2, where arcs are drawn with centres A, B, C and D intersect in pairs at mid-points P, Q, R and S of the sides AB, BC, CD and DA respectively of a square ABCD of side 12 cm. [Use \u03c0 = 3.14] [3]\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767257_a2650617b1_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q20\" width=\"255\" height=\"291\" \/><br \/>\nSolution:<br \/>\nGiven, ABCD is a square of side 12 cm.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363631526_4673463d1a_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q20.1\" width=\"248\" height=\"249\" \/><br \/>\nP, Q, R and S are the midpoints of sides AB, BC, CD and AD respectively.<br \/>\nArea of shaded region = Area of square \u2013 4 \u00d7 Area of quadrant<br \/>\n= a<sup>2<\/sup> \u2013 4 \u00d7 \\(\\frac { 1 }{ 4 }\\) \u03c0r<sup>2<\/sup><br \/>\n= (12)<sup>2<\/sup> \u2013 3.14 \u00d7 (6)<sup>2<\/sup><br \/>\n= 144 \u2013 3.14 \u00d7 36<br \/>\n= 144 \u2013 113.04<br \/>\n= 30.96 cm<sup>2<\/sup><\/p>\n<p>Question 21.<br \/>\nA wooden article was made by scooping out a hemisphere form each end of a solid cylinder, as shown in Fig. 3. If the height of the cylinder is 10 cm and its base is of radius 3.5 cm. Find the total surface area of the article. [3]\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767357_e9947d6161_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q21\" width=\"129\" height=\"218\" \/><br \/>\nOR<br \/>\nA heap of rice is in the form of a cone of base diameter 24 m and height 3.5 m. Find the volume of the rice. How much canvas cloth is required to just cover the heap?<br \/>\nSolution:<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767412_0de9cf3c07_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q21.1\" width=\"137\" height=\"215\" \/><br \/>\nGiven, Radius (r) of cylinder = Radius of hemisphere = 3.5 cm.<br \/>\nTotal SA of article = CSA of cylinder + 2 \u00d7 CSA of hemisphere<br \/>\nHeight of cylinder, h = 10 cm<br \/>\nTSA = 2\u03c0rh + 2 \u00d7 2\u03c0r<sup>2<\/sup><br \/>\n= 2\u03c0rh + 4\u03c0r<sup>2<\/sup><br \/>\n= 2\u03c0rh (h + 2r)<br \/>\n= 2 \u00d7 \\(\\frac { 22 }{ 7 }\\) \u00d7 3.5 (10 + 2 \u00d7 3.5)<br \/>\n= 2 \u00d7 22 \u00d7 0.5 \u00d7 (10 + 7)<br \/>\n= 2 \u00d7 11 \u00d7 17<br \/>\n= 374 cm<sup>2<\/sup><br \/>\nOR<br \/>\nBase diameter of cone = 24 m.<br \/>\nRadius r = 12 m<br \/>\nHeight of cone, h = 3.5 m<br \/>\nVolume of rice in conical heap = \\(\\frac { 1 }{ 3 }\\) \u03c0r<sup>2<\/sup>h<br \/>\n= \\(\\frac { 1 }{ 3 }\\) \u00d7 \\(\\frac { 22 }{ 7 }\\) \u00d7 12 \u00d7 12 \u00d7 3.5 = 528 cm<sup>3<\/sup><br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363631636_38b65e0a2b_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q21.2\" width=\"370\" height=\"355\" \/><\/p>\n<p>Question 22.<br \/>\nThe table below shows the salaries of 280 persons: [3]\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363631676_9e4e0b1bff_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q22\" width=\"339\" height=\"248\" \/><br \/>\nCalculate the median salary of the data.<br \/>\nSolution:<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363631701_2b14791a97_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q22.1\" width=\"363\" height=\"295\" \/><br \/>\n\\(\\frac { N }{ 2 }\\) = \\(\\frac { 280 }{ 2 }\\) = 140<br \/>\nThe cumulative frequency just greater than 140 is 182.<br \/>\nMedian class is 10 -15.<br \/>\nl = 10, h = 5, N = 280, c.f. = 49 and f = 133<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363631716_1aa75933e0_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q22.2\" width=\"253\" height=\"321\" \/><\/p>\n<p><strong>Section \u2013 D<\/strong><\/p>\n<p>Question 23.<br \/>\nA motorboat whose speed is 18 km\/hr in still water takes 1 hr more to go 24 km upstream than to return downstream to the same spot. Find the speed of the stream. [4]\nOR<br \/>\nA train travels at a certain average speed for a distance of 63 km and then travels at a distance of 72 km at an average speed of 6 km\/hr more than its original speed. If it takes 3 hours to complete the total journey, what is the original average speed?<br \/>\nSolution:<br \/>\nGiven, speed of motorboat instil<br \/>\nwater = 18 km\/hr.<br \/>\nLet speed of stream = x km\/hr.<br \/>\nSpeed of boat downstream = (18 + x) km\/hr.<br \/>\nAnd speed of boat upstream = (18 \u2013 x) km\/hr.<br \/>\nTime of the upstream journey = \\(\\frac { 24 }{ 18-x }\\)<br \/>\nTime of the downstream journey = \\(\\frac { 24 }{ 18+x }\\)<br \/>\nAccording to the question,<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767567_f9259c9969_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q23\" width=\"310\" height=\"273\" \/><br \/>\n\u21d2 x<sup>2<\/sup> + 48x \u2013 324 = 0<br \/>\n\u21d2 x<sup>2<\/sup> + 54x \u2013 6x \u2013 324 = 0<br \/>\n\u21d2 x(x + 54) \u2013 6(x + 54) = 0<br \/>\n\u21d2 (x + 54)(x \u2013 6) = 0<br \/>\nEither x + 54 = 0 \u21d2 x = -54<br \/>\nRejected, as speed cannot be negative<br \/>\nor x \u2013 6 = 0 \u21d2 x = 6<br \/>\nThus, the speed of the stream is 6 km\/hr.<br \/>\nOR<br \/>\nLet the original average speed of train be x km\/hr.<br \/>\nIncreased speed of train = (x + 6) km\/hr.<br \/>\nTime taken to cover 63 km with average speed = \\(\\frac { 63 }{ x }\\) hr.<br \/>\nTime taken to cover 72 km with increased speed = \\(\\frac { 72 }{ x+6 }\\)<br \/>\nAccording to the question,<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363631811_70d4a145d9_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q23.1\" width=\"183\" height=\"176\" \/><br \/>\n\u21d2 135x + 378 = 3(x<sup>2<\/sup> + 6x)<br \/>\n\u21d2 135x + 378 = 3x<sup>2<\/sup> + 18x<br \/>\n\u21d2 3x<sup>2<\/sup> + 18x \u2013 135x \u2013 378 = 0<br \/>\n\u21d2 3x<sup>2<\/sup> \u2013 117x \u2013 378 = 0<br \/>\n\u21d2 3(x<sup>2<\/sup> \u2013 39x \u2013 126) = 0<br \/>\n\u21d2 x<sup>2<\/sup> \u2013 39x \u2013 126 = 0<br \/>\n\u21d2 x<sup>2<\/sup> \u2013 42x + 3x \u2013 126 \u2013 0<br \/>\n\u21d2 x(x \u2013 42) + 3(x \u2013 42) = 0<br \/>\n\u21d2 (x \u2013 42) (x + 3) = 0<br \/>\nEither x \u2013 42 = 0 \u21d2 x = 42<br \/>\nor x + 3 = 0 \u21d2 x = -3<br \/>\nRejected (as speed cannot be negative)<br \/>\nThus, average speed of train is 42 km\/hr.<\/p>\n<p>Question 24.<br \/>\nThe sum of four consecutive numbers in an AP is 32 and the ratio of the product of the first and the last term to the product of two middle terms is 7:15. Find the numbers. [4]\nSolution:<br \/>\nLet the first term of AP be a and d be a common difference.<br \/>\nLet your consecutive term of an AP be a \u2013 3d, a \u2013 d, a + d and a + 3d<br \/>\nAccording to the question,<br \/>\na \u2013 3d + a \u2013 d + a + d + a + 3d = 32<br \/>\n\u21d2 4a = 32<br \/>\n\u21d2 a = 8 \u2026(i)<br \/>\nAlso,<br \/>\n(a \u2013 3d) (a + 3d) : (a \u2013 d) (a + d) = 7 : 15<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767627_c20e3365c6_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q24\" width=\"300\" height=\"344\" \/><br \/>\nFor d = 2, four terms of AP are,<br \/>\na \u2013 3d = 8 \u2013 3 (2) = 2<br \/>\na \u2013 d = 8 \u2013 2 = 6<br \/>\na + d = 8 + 2 = 10<br \/>\na + 3d = 8 + 3(2) = 14<br \/>\nFor d = -2, four term are<br \/>\na \u2013 3d = 8 \u2013 3(-2) = 14<br \/>\na \u2013 d = 8 \u2013 (-2) = 10<br \/>\na + d = 8 + (-2) = 6<br \/>\na + 3d = 8 + 3 (-2) = 2<br \/>\nThus, the four terms of AP series are 2, 6, 10, 14 or 14, 10, 6, 2.<\/p>\n<p>Question 25.<br \/>\nIn an equilateral \u2206ABC, D is a point on side BC such that BD = \\(\\frac { 1 }{ 3 }\\) BC. Prove that 9(AD)<sup>2<\/sup> = 7(AB)<sup>2<\/sup>. [4]\nOR<br \/>\nProve that, in a right triangle, the square on the hypotenuse is equal to the sum of the squares on the other two sides.<br \/>\nSolution:<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363631876_116da060c4_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q25\" width=\"198\" height=\"209\" \/><br \/>\nGiven, ABC is an equilateral triangle and D is a point on BC such that BD = \\(\\frac { 1 }{ 3 }\\) BC.<br \/>\nTo prove: 9AD<sup>2<\/sup> = 7AB<sup>2<\/sup><br \/>\nConstruction : Draw AE \u22a5 BC<br \/>\nProof: BD = \\(\\frac { 1 }{ 3 }\\) BC \u2026(i) (Given)<br \/>\nAE \u22a5 BC<br \/>\nWe know that perpendicular from a vertex of equilateral triangle to the base divides base in two equal parts.<br \/>\nBE = EC = \\(\\frac { 1 }{ 2 }\\) BC \u2026(ii)<br \/>\nIn \u2206AEB,<br \/>\nAD<sup>2<\/sup> = AE<sup>2<\/sup> + DE<sup>2<\/sup> (Pythagoras theorem)<br \/>\nor AE<sup>2<\/sup> = AD<sup>2<\/sup> \u2013 DE<sup>2<\/sup> \u2026(iii)<br \/>\nSimilarly, In \u2206AEB,<br \/>\nAB<sup>2<\/sup> = AE<sup>2<\/sup> + BE<sup>2<\/sup><br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767732_349f869ba9_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q25.1\" width=\"345\" height=\"417\" \/><br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767797_c20cb84351_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q25.2\" width=\"373\" height=\"247\" \/><br \/>\nOR<br \/>\nGiven: \u2206ABC is a right angle triangle, right-angled at A.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767812_db527957c2_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q25.3\" width=\"225\" height=\"169\" \/><br \/>\nTo prove : BC<sup>2<\/sup> = AB<sup>2<\/sup> + AC<sup>2<\/sup><br \/>\nConstruction : Draw AD \u22a5 BC.<br \/>\nProof: In \u2206ADB and \u2206BAC,<br \/>\n\u2220B = \u2220B (Common)<br \/>\n\u2220ADB = \u2220BAC (Each 90\u00b0)<br \/>\n\u2206ADB ~ \u2206BAC (By AA similarity axiom)<br \/>\n\\(\\frac { AB }{ BC }\\) = \\(\\frac { BD }{ AB }\\) (CPCT)<br \/>\nAB<sup>2<\/sup> = BC \u00d7 BD<br \/>\nSimilarly,<br \/>\n\u2206ADC ~ \u2206CAB<br \/>\n\\(\\frac { AC }{ BC }\\) = \\(\\frac { DC }{ AC }\\)<br \/>\nAC<sup>2<\/sup> = BC \u00d7 DC \u2026(ii)<br \/>\nOn adding equation (i) and (ii)<br \/>\nAB<sup>2<\/sup> + AC<sup>2<\/sup> = BC \u00d7 BD + BC \u00d7 CD = BC (BD + CD) = BC \u00d7 BC<br \/>\nAB<sup>2<\/sup> + AC<sup>2<\/sup> = BC<sup>2<\/sup><br \/>\nBC<sup>2<\/sup> = AB<sup>2<\/sup> + AC<sup>2<\/sup><br \/>\nHence Proved.<\/p>\n<p>Question 26.<br \/>\nDraw a triangle ABC with BC = 6 cm, AB = 5 cm and \u2220ABC = 60\u00b0. Then construct a triangle whose sides are \\(\\frac { 3 }{ 4 }\\) of the corresponding sides of the \u2206ABC. [4]\nSolution:<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767827_9c2213fb15_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q26\" width=\"269\" height=\"302\" \/><\/p>\n<ol>\n<li>Draw a line segment BC = 6 cm.<\/li>\n<li>Construct \u2220XBC = 60\u00b0.<\/li>\n<li>With B as centre and radius equal to 5 cm, draw an arc intersecting XB at A.<\/li>\n<li>Join AC. Thus, \u2206ABC is obtained.<\/li>\n<li>Draw an acute angle \u2220CBY below of B.<\/li>\n<li>Mark 4-equal parts on BY as B<sub>1<\/sub>, B<sub>2<\/sub>, B<sub>3<\/sub> and B<sub>4<\/sub><\/li>\n<li>Join B<sub>4<\/sub> to C.<\/li>\n<li>From By draw a line parallel to B<sub>4<\/sub>C intersecting BC at C\u2019.<\/li>\n<li>Draw another line parallel to CA from C\u2019, intersecting AB at A\u2019.<\/li>\n<li>\u2206A\u2019BC\u2019 is required triangle which is similar to \u2206ABC such that BC\u2019 = \\(\\frac { 3 }{ 4 }\\) BC.<\/li>\n<\/ol>\n<p>Question 27.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363632086_3444c36483_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q27\" width=\"323\" height=\"57\" \/><br \/>\nSolution:<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767882_1ecb72c088_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q27.1\" width=\"371\" height=\"240\" \/><br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363767892_8a23b70546_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q27.2\" width=\"262\" height=\"148\" \/><\/p>\n<p>Question 28.<br \/>\nThe diameters of the lower and upper ends of a bucket in the form of a frustum of a cone are 10 cm and 30 cm respectively. If its height is 24 cm, find:<br \/>\n(i) The area of the metal sheet used to make the bucket.<br \/>\n(ii) Why we should avoid the bucket made by ordinary plastic? [Use \u03c0 = 3.14] [4]\nSolution:<br \/>\nGiven, Height of frustum, h = 24 cm.<br \/>\nDiameter of lower end = 10 cm<br \/>\nRadius of lower end, r = 5 cm.<br \/>\nDiameter of upper end = 30 cm<br \/>\nRadius of upper end, R = 15 cm.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363766007_ba06bc5e7e_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q28\" width=\"285\" height=\"192\" \/><br \/>\n(i) Area of metal sheet used to make the bucket = CSA of frustum + Area of base<br \/>\n= \u03c0l(R + r) + \u03c0r<sup>2<\/sup><br \/>\n= \u03c0[26 (15 + 5) + (5)<sup>2<\/sup>]\n= 3.14 (26 \u00d7 20 + 25)<br \/>\n= 3.14 (520 + 25)<br \/>\n= 3.14 \u00d7 545<br \/>\n= 1711.3 cm<sup>2<\/sup><br \/>\n(ii) We should avoid the bucket made by ordinary plastic because plastic is harmful to the environment and to protect the environment its use should be avoided.<\/p>\n<p>Question 29.<br \/>\nAs observed from the top of a 100 m high lighthouse from the sea-level, the angles of depres\u00acsion of two ships are 30\u00b0 and 45\u00b0. If one ship is exactly behind the other on the same side of the lighthouse, find the distance between the two ships. [Use \u221a3 = 1.732] [4]\nSolution:<br \/>\nLet AB be the lighthouse and two ships are at C and D.<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363630231_147c263edc_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q29\" width=\"376\" height=\"593\" \/><br \/>\nDistance between two ships = y \u2013 x<br \/>\n= 100\u221a3 \u2013 100 [from equation (i) and (ii)]\n= 100 (\u221a3 \u2013 1)<br \/>\n= 100(1.732 \u2013 1)<br \/>\n= 100 (0.732)<br \/>\n= 73.2 m<\/p>\n<p>Question 30.<br \/>\nThe mean of the following distribution is 18. Find the frequency f of the class 19-21. [4]\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363765667_5715513261_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q30\" width=\"532\" height=\"65\" \/><br \/>\nOR<br \/>\nThe following distribution gave the daily income of 50 workers of a factory:<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363630171_679336b5e4_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q30.1\" width=\"529\" height=\"62\" \/><br \/>\nConvert the distribution above to a less than type cumulative frequency distribution and draw its ogive.<br \/>\nSolution:<br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363630126_568ef06a4d_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q30.2\" width=\"391\" height=\"543\" \/><br \/>\n<img loading=\"lazy\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/48363765732_c998c6a2c6_o.png\" alt=\"CBSE Previous Year Question Papers Class 10 Maths 2018 Q30.3\" width=\"372\" height=\"479\" \/><\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>CBSE Previous Year Question Papers Class 10 Maths 2018 Time Allowed: 3 hours Maximum Marks: 80 General Instructions: All questions [&hellip;]<\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"Get CBSE Previous Year Question Papers Class 10 Maths 2018 at Infinity Learn","custom_permalink":"cbse\/study-materials\/maths\/previous-year-question-papers-class-10-maths-2018\/"},"categories":[13,21],"tags":[],"table_tags":[],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v17.9 - 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