{"id":41192,"date":"2022-01-17T18:12:30","date_gmt":"2022-01-17T12:42:30","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/?p=41192"},"modified":"2022-02-08T17:52:12","modified_gmt":"2022-02-08T12:22:12","slug":"mcq-questions-for-class-10-maths-coordinate-geometry-with-answers","status":"publish","type":"post","link":"https:\/\/infinitylearn.com\/surge\/study-materials\/mcq-questions\/class-10-maths\/coordinate-geometry\/answers","title":{"rendered":"MCQ Questions for Class 10 Maths Coordinate Geometry with Answers"},"content":{"rendered":"<h2>Class 10 Maths MCQs Chapter 7 Coordinate Geometry<\/h2>\n<p>1. The distance of the point P(2, 3) from the x-axis is<br \/>\n(a) 2<br \/>\n(b) 3<br \/>\n(c) 1<br \/>\n(d) 5<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: b<br \/>\nExplanation: Reason: The distance from x-axis is equal to its ordinate i.e., 3<\/p>\n<\/details>\n<hr \/>\n<p>2. The distance between the point P(1, 4) and Q(4, 0) is<br \/>\n(a) 4<br \/>\n(b) 5<br \/>\n(c) 6<br \/>\n(d) 3\u221a3<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: b<br \/>\nExplanation: Reason: The required distance = \\(\\sqrt{(4-1)^{2}+(0-4)^{2}}=\\sqrt{9+16}=\\sqrt{25}=5\\)<\/p>\n<\/details>\n<hr \/>\n<p>3. The points (-5, 1), (1, p) and (4, -2) are collinear if<br \/>\nthe value of p is<br \/>\n(a) 3<br \/>\n(b) 2<br \/>\n(c) 1<br \/>\n(d) -1<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: d<br \/>\nExplanation: Reason: The points are collinear if area of \u0394 = 0<br \/>\n= \\(\\frac{1}{2}\\)[-5(p + 2) +l(-2 -1) + 4(1 \u2013 p)] \u2013 0<br \/>\n\u21d2 -5 p -10-3 + 4-4p = 0<br \/>\n\u21d2 -9p = +9<br \/>\n\u2234 p = -1<\/p>\n<\/details>\n<hr \/>\n<p>4. The area of the triangle ABC with the vertices A(-5, 7), B(-4, -5) and C(4, 5) is<br \/>\n(a) 63<br \/>\n(b) 35<br \/>\n(c) 53<br \/>\n(d) 36<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: c<br \/>\nExplanation: Reason: Area of \u0394ABC = \\(\\frac{1}{2}\\) [x<sub>1<\/sub>(y<sub>2<\/sub> \u2013 y<sub>3<\/sub>) + x<sub>2<\/sub>(y<sub>3<\/sub> \u2013 y<sub>1<\/sub>) + x<sub>3<\/sub>(y<sub>1<\/sub> \u2013 y<sub>2<\/sub>)]\n= \\(\\frac{1}{2}\\)[-5(-5 \u2013 5) -4(5 \u2013 7) + 4(7 \u2013 (-5))] = \\(\\frac{1}{2}\\)[-5(-10) -4(-2) + 4(12)]\n= \\(\\frac{1}{2}\\)[50 + 8 + 48] = \\(\\frac{1}{2}\\) \u00d7 106 = 53 sq. units<\/p>\n<\/details>\n<hr \/>\n<p>5. The distance of the point (\u03b1, \u03b2) from the origin is<br \/>\n(a) \u03b1 + \u03b2<br \/>\n(b) \u03b1\u00b2 + \u03b2\u00b2<br \/>\n(c) |\u03b1| + |\u03b2|<br \/>\n(d) \\(\\sqrt{\\alpha^{2}+\\beta^{2}}\\)<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: d<br \/>\nExplanation: Reason: Distance of (\u03b1, \u03b2) from origin (0, 0) = \\(\\sqrt{(\\alpha-0)^{2}+(\\beta-0)^{2}}=\\sqrt{\\alpha^{2}+\\beta^{2}}\\)<\/p>\n<\/details>\n<hr \/>\n<p>6. The area of the triangle whose vertices are A(1, 2), B(-2, 3) and C(-3, -4) is<br \/>\n(a) 11<br \/>\n(b) 22<br \/>\n(c) 33<br \/>\n(d) 21<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: a<br \/>\nExplanation: Reason: Required area= \\(\\frac{1}{2}\\)[1(3 + 4) -2(-4 \u2013 2) -3(2 \u2013 3)]\n= \\(\\frac{1}{2}\\)[7 + 12 + 3]\n= \\(\\frac{1}{2}\\) \u00d7 22 = 11<\/p>\n<\/details>\n<hr \/>\n<p>7. The line segment joining the points (3, -1) and (-6, 5) is trisected. The coordinates of point of trisection are<br \/>\n(a) (3, 3)<br \/>\n(b) (- 3, 3)<br \/>\n(c) (3, \u2013 3)<br \/>\n(d) (-3,-3)<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: b<br \/>\nExplanation: Reason: Since the line segment AB is trisected<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-9881\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/mcq-questions-for-class-10-maths-coordinate-geometry-with-answers-1.png\" alt=\"MCQ Questions for Class 10 Maths Coordinate Geometry with Answers 1\" width=\"840\" height=\"126\" \/><\/p>\n<\/details>\n<hr \/>\n<p>8. The line 3x + y \u2013 9 = 0 divides the line joining the points (1, 3) and (2, 7) internally in the ratio<br \/>\n(a) 3 : 4<br \/>\n(b) 3 : 2<br \/>\n(c) 2 : 3<br \/>\n(d) 4 : 3<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: a<br \/>\nExplanation: Reason: Let the line 3x + y \u2013 9 = 0 divide the line segment joining A(l, 3) ad B(2, 7) in the ratio K : 1 at point C.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-9882\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/mcq-questions-for-class-10-maths-coordinate-geometry-with-answers-2.png\" alt=\"MCQ Questions for Class 10 Maths Coordinate Geometry with Answers 2\" width=\"791\" height=\"215\" \/><\/p>\n<\/details>\n<hr \/>\n<p>9. The distance between A (a + b, a \u2013 b) and B(a \u2013 b, -a \u2013 b) is<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: c<br \/>\nExplanation:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-9883\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/mcq-questions-for-class-10-maths-coordinate-geometry-with-answers-3.png\" alt=\"MCQ Questions for Class 10 Maths Coordinate Geometry with Answers 3\" width=\"649\" height=\"79\" \/><\/p>\n<\/details>\n<hr \/>\n<p>10. If (a\/3, 4) is the mid-point of the segment joining the points P(-6, 5) and R(-2, 3), then the value of \u2018a\u2019 is<br \/>\n(a) 12<br \/>\n(b) -6<br \/>\n(c) -12<br \/>\n(d) -4<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: c<br \/>\nExplaination:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-9884\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/mcq-questions-for-class-10-maths-coordinate-geometry-with-answers-4.png\" alt=\"MCQ Questions for Class 10 Maths Coordinate Geometry with Answers 4\" width=\"769\" height=\"60\" \/><\/p>\n<\/details>\n<hr \/>\n<p>11. If the distance between the points (x, -1) and (3, 2) is 5, then the value of x is<br \/>\n(a) -7 or -1<br \/>\n(b) -7 or 1<br \/>\n(c) 7 or 1<br \/>\n(d) 7 or -1<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: d<br \/>\nExplanation: Reason: We have \\(\\sqrt{(x-3)^{2}+(-1-2)^{2}}=5\\)<br \/>\n\u21d2 (x \u2013 3)\u00b2 + 9 = 25<br \/>\n\u21d2 x\u00b2 \u2013 6x + 9 + 9 = 25<br \/>\n\u21d2 x\u00b2 -6x \u2013 7 = 0<br \/>\n\u21d2 (x \u2013 7)(x + 1) = 0<br \/>\n\u21d2 x = 7 or x = -1<\/p>\n<\/details>\n<hr \/>\n<p>12. The points (1,1), (-2, 7) and (3, -3) are<br \/>\n(a) vertices of an equilateral triangle<br \/>\n(b) collinear<br \/>\n(c) vertices of an isosceles triangle<br \/>\n(d) none of these<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: b<br \/>\nExplanation: Reason: Let A(1, 1), B(-2, 7) and C(3, 3) are the given points, Then, we have<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-9885\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/mcq-questions-for-class-10-maths-coordinate-geometry-with-answers-5.png\" alt=\"MCQ Questions for Class 10 Maths Coordinate Geometry with Answers 5\" width=\"557\" height=\"162\" \/><\/p>\n<\/details>\n<hr \/>\n<p>13. The coordinates of the centroid of a triangle whose vertices are (0, 6), (8,12) and (8, 0) is<br \/>\n(a) (4, 6)<br \/>\n(b) (16, 6)<br \/>\n(c) (8, 6)<br \/>\n(d) (16\/3, 6)<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: d<br \/>\nExplanation: Reason: The co-ordinates of the centroid of the triangle is<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-9886\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/mcq-questions-for-class-10-maths-coordinate-geometry-with-answers-6.png\" alt=\"MCQ Questions for Class 10 Maths Coordinate Geometry with Answers 6\" width=\"375\" height=\"59\" \/><\/p>\n<\/details>\n<p>&nbsp;<\/p>\n<hr \/>\n<p>14. Two vertices of a triangle are (3, \u2013 5) and (- 7,4). If its centroid is (2, -1), then the third vertex is<br \/>\n(a) (10, 2)<br \/>\n(b) (-10,2)<br \/>\n(c) (10,-2)<br \/>\n(d) (-10,-2)<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: c<br \/>\nExplanation: Reason: Let the coordinates of the third vertex be (x, y)<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-9887\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/mcq-questions-for-class-10-maths-coordinate-geometry-with-answers-7.png\" alt=\"MCQ Questions for Class 10 Maths Coordinate Geometry with Answers 7\" width=\"840\" height=\"145\" \/><\/p>\n<\/details>\n<p>&nbsp;<\/p>\n<hr \/>\n<p>15. The area of the triangle formed by the points A(-1.5, 3), B(6, -2) and C(-3, 4) is<br \/>\n(a) 0<br \/>\n(b) 1<br \/>\n(c) 2<br \/>\n(d) 3\/2<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: a<br \/>\nExplanation: Reason: Area of \u0394ABC = \\(\\frac{1}{2}\\) [-1.5(-2 \u2013 4) + 6(4 \u2013 3) + (-3) (3 + 2)] = \\(\\frac{1}{2}\\) [9 + 6 \u2013 15] = 0. It is a straight line.<\/p>\n<\/details>\n<hr \/>\n<p>16. If the points P(1, 2), B(0, 0) and C(a, b) are collinear, then<br \/>\n(a) 2a = b<br \/>\n(b) a = -b<br \/>\n(c) a = 2b<br \/>\n(d) a = b<\/p>\n<details>\n<summary><span style=\"color: #ff00ff\"><strong>Answer\/ Explanation<\/strong><\/span><\/summary>\n<p>Answer: a<br \/>\nExplanation: Reason: Area of \u0394PBC = 0<br \/>\n\u21d2 \\(\\frac{1}{2}\\)[1(0 \u2013 b) + 0(6 \u2013 1) + a(2 \u2013 0)] = 0<br \/>\n\u21d2 \\(\\frac{1}{2}\\)[-6 + 2a] = 0<br \/>\n\u21d2 -b + 2a = 0<br \/>\n\u2234 2a = b<\/p>\n<\/details>\n<hr \/>\n<p>We hope the given MCQ Questions for Class 10 Maths Coordinate Geometry with Answers will help you. If you have any query regarding CBSE Class 10 Maths Chapter 7 Coordinate Geometry Multiple Choice Questions with Answers, drop a comment below and we will get back to you at the earliest.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Class 10 Maths MCQs Chapter 7 Coordinate Geometry 1. 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