<\/p>\n
1. What will be the fraction of molecules having energy equal to or greater than activation energy, Ea? Answer: d<\/p>\n<\/details>\n 2. Answer: c<\/p>\n<\/details>\n 3. Which among the following is a false statement? Answer: c<\/p>\n<\/details>\n 4. Which of the following statements about the catalyst is true? Answer: a<\/p>\n<\/details>\n 5. An endothermic reaction with high activation energy for the forward reaction is given by the diagram.<\/p>\n Answer: c<\/p>\n<\/details>\n 6. For the reaction N2<\/sub> + 3H2<\/sub> \u2192 2NH3<\/sub> if \\(\\frac{\\Delta\\left[\\mathrm{NH}_{3}\\right]}{\\Delta t}\\) = 2 \u00d7 10-4<\/sup> mol L-1<\/sup>s-1<\/sup>, the value of \\(\\frac{-\\Delta\\left[\\mathrm{H}_{2}\\right]}{\\Delta t}\\) would be Answer: b<\/p>\n<\/details>\n 7. The rate of a certain hypothetical reaction Answer: d<\/p>\n<\/details>\n 8. In the formation of S02 by contact process; Answer: d<\/p>\n<\/details>\n 9. For a chemical reaction A\u2192B, it is found that the rate of reaction doubles when the concentration of A is increased four times. The order of reaction is Answer: c<\/p>\n<\/details>\n 10. The half life of the first order reaction having rate constant K = 1.7 x 10-5<\/sup>s-1<\/sup> is Answer: c<\/p>\n<\/details>\n We hope the given Chemistry MCQs for Class 12 with Answers Chapter 4 Chemical Kinetics will help you. If you have any query regarding CBSE Class 12 Chemistry Chemical Kinetics MCQs Pdf, drop a comment below and we will get back to you at the earliest.<\/p>\n","protected":false},"excerpt":{"rendered":" Chemical Kinetics Class 12 Chemistry MCQs Pdf 1. What will be the fraction of molecules having energy equal to […]<\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"Get Chemistry MCQs for Class 12 with Answers Chapter 4 Chemical Kinetics on Infinity Learn.","custom_permalink":"study-material\/cbse-notes\/class-12\/chemistry\/chemistry-mcqs-for-class-12-with-answers-chapter-4-chemical-kinetics\/"},"categories":[92,93,21],"tags":[],"table_tags":[],"acf":[],"yoast_head":"\n
\n(a) K
\n(b) A
\n(c) Ae-Ea\/Rt<\/sup>
\n(d) e-Ea\/Rt<\/sup><\/p>\nAnswer<\/strong><\/span><\/summary>\n
\n
\nWhat type of reaction is this?
\n(a) Second order
\n(b) Unimolecular
\n(c) Pseudo-unimolecular
\n(d) Third order<\/p>\nAnswer<\/strong><\/span><\/summary>\n
\n
\n(a) Rate of zero order reaction is independent of initial concentration of reactant.
\n(b) Half life of a third order reaction is inversely proportional to square of initial concentration of the reactant.
\n(c) Molecularity of a reaction may be zero or fraction.
\n(d) For a first order reaction, \\(t_{1 \/ 2}=\\frac{0.693}{\\mathrm{K}}\\)<\/p>\nAnswer<\/strong><\/span><\/summary>\n
\n
\n(a) A catalyst accelerates the rate of reaction by bringing down the activation energy.
\n(b) A catalyst does not participate in reaction mechanism.
\n(c) A catalyst makes the reaction feasible by making \u2206G more negative.
\n(d) A catalyst makes equilibrium constant more favourable for forward reaction.<\/p>\nAnswer<\/strong><\/span><\/summary>\n
\nAnswer<\/strong><\/span><\/summary>\n
\n
\n(a) 1 \u00d7 10-4<\/sup> mol L-1<\/sup>s-1<\/sup>
\n(b) 3 \u00d7 10-4<\/sup> mol L-1<\/sup>s-1<\/sup>
\n(c) 4 \u00d7 10-4<\/sup> mol L-1<\/sup>s-1<\/sup>
\n(d) 6 \u00d7 10-4<\/sup> mol L-1<\/sup>s-1<\/sup><\/p>\nAnswer<\/strong><\/span><\/summary>\n
\n
\nA + B + C \u2192 products
\nis given by r = \\(\\frac{-d[\\mathbf{A}]}{d t} \\mathbf{K}[\\mathbf{A}]^{1 \/ 2}[\\mathbf{B}]^{1 \/ 3}[\\mathbf{C}]^{1 \/ 4}\\). The order of the reaction is
\n(a) 13\/11
\n(b) 13\/14
\n(c) 12\/13
\n(d) 13\/12<\/p>\nAnswer<\/strong><\/span><\/summary>\n
\n
\n2SO2<\/sub> + O2<\/sub> \u2192 2SO3<\/sub>, the rate of reaction was measured as \\(\\frac{-d\\left[\\mathrm{O}_{2}\\right]}{d t}\\) = 2.5 \u00d7 10-4<\/sup> mol L-1<\/sup>s-1<\/sup>. at
\nThe rate of formation of of S03 will be
\n(a) -5.0 \u00d7 10-4<\/sup> mol L-1<\/sup>s-1<\/sup>
\n(b) -1.25 \u00d7 10-4<\/sup> mol L-1<\/sup>s-1<\/sup>
\n(c) 3.75 \u00d7 10-4<\/sup> mol L-1<\/sup>s-1<\/sup>
\n(d) 5.00 \u00d7 10-4<\/sup> mol L-1<\/sup>s-1<\/sup><\/p>\nAnswer<\/strong><\/span><\/summary>\n
\n
\n(a) Two
\n(b) One
\n(c) Half
\n(d) Zero<\/p>\nAnswer<\/strong><\/span><\/summary>\n
\n
\n(a) 12.1 h
\n(b) 9.7 h
\n(c) 11.3 h
\n(d) 1.8 h<\/p>\nAnswer<\/strong><\/span><\/summary>\n
\n