{"id":59620,"date":"2022-01-28T10:49:11","date_gmt":"2022-01-28T05:19:11","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/?p=59620"},"modified":"2024-02-21T13:32:54","modified_gmt":"2024-02-21T08:02:54","slug":"study-materials-ncert-exemplar-solutions-class-11-physics-chapter-15-waves","status":"publish","type":"post","link":"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/","title":{"rendered":"NCERT Exemplar for Class 11 Physics Chapter 15 &#8211; Waves"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_37 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" style=\"display: none;\"><label for=\"item\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input type=\"checkbox\" id=\"item\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1' style='display:block'><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/#Class_11_Physics_NCERT_Exemplar_Solutions_for_Chapter_15_Waves\" title=\"Class 11 Physics NCERT Exemplar Solutions for Chapter 15 Waves\">Class 11 Physics NCERT Exemplar Solutions for Chapter 15 Waves<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/#Multiple_Choice_Questions_I\" title=\"Multiple Choice Questions I\">Multiple Choice Questions I<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/#Multiple_Choice_Questions_II\" title=\"Multiple Choice Questions II\">Multiple Choice Questions II<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/#Very_Short_Answer\" title=\"Very Short Answer\">Very Short Answer<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/#Short_Answers\" title=\"Short Answers\">Short Answers<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/#Long_Answers\" title=\"Long Answers\">Long Answers<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/#About_Infinity_Learn_Solutions\" title=\"About Infinity Learn Solutions\">About Infinity Learn Solutions<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/#Frequently_Asked_Questions\" title=\"Frequently Asked Questions\">Frequently Asked Questions<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/#Why_should_I_refer_to_these_NCERT_Exemplar_Solutions\" title=\"Why should I refer to these NCERT Exemplar Solutions?\">Why should I refer to these NCERT Exemplar Solutions?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/#How_to_score_full_marks_in_Chapter_15_of_NCERT_Exemplar_Solutions_for_Class_11_Physics\" title=\"How to score full marks in Chapter 15 of NCERT Exemplar Solutions for Class 11 Physics?\">How to score full marks in Chapter 15 of NCERT Exemplar Solutions for Class 11 Physics?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/#How_to_differentiate_the_transverse_and_longitudinal_waves_in_these_NCERT_Exemplar_Solutions\" title=\"How to differentiate the transverse and longitudinal waves in these NCERT Exemplar Solutions?\">How to differentiate the transverse and longitudinal waves in these NCERT Exemplar Solutions?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/#Why_Opt_for_Infinity_Learn\" title=\"Why Opt for Infinity Learn?\">Why Opt for Infinity Learn?<\/a><\/li><\/ul><\/nav><\/div>\n<h2><span style=\"font-size: 18pt;\">Class 11 Physics NCERT Exemplar Solutions for Chapter 15 Waves<\/span><\/h2>\n<h3><span class=\"ez-toc-section\" id=\"Multiple_Choice_Questions_I\"><\/span>Multiple Choice Questions I<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>15.1. Water waves produced by a motorboat sailing in water are<\/strong><\/p>\n<p><strong>a) neither longitudinal nor transverse<\/strong><\/p>\n<p><strong>b) both longitudinal and transverse<\/strong><\/p>\n<p><strong>c) only longitudinal<\/strong><\/p>\n<p><strong>d) only transverse<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answer is b) both longitudinal and transverse<\/p>\n<p><strong>15.2. Sound waves of wavelength \u03bb travelling in a medium with a speed of v m\/s enter into another medium where its speed is 2v m\/s. The wavelength of sound waves in the second medium is<\/strong><\/p>\n<p><strong>a) \u03bb<\/strong><\/p>\n<p><strong>b) \u03bb\/2<\/strong><\/p>\n<p><strong>c) 2 \u03bb<\/strong><\/p>\n<p><strong>d) 4 \u03bb<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answer is c) 2 \u03bb<\/p>\n<p><strong>15.3. Speed of sound wave in air<\/strong><\/p>\n<p><strong>a) is independent of temperature<\/strong><\/p>\n<p><strong>b) increases with pressure<\/strong><\/p>\n<p><strong>c) increases with an increase in humidity<\/strong><\/p>\n<p><strong>d) decreases with an increase in humidity<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answer is c) increases with an increase in humidity<\/p>\n<p><a href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions\/class-11\/\" target=\"_blank\" rel=\"noopener\"><button class=\"favorite styled\" style=\"width: 100%;\" type=\"button\"> <input class=\"more\" type=\"button\" value=\"Also Read!\" \/> <strong>NCERT Solutions for Class 11<\/strong><\/button><\/a><\/p>\n<p><strong>15.4. Change in temperature of the medium changes<\/strong><\/p>\n<p><strong>a) frequency of sound waves<\/strong><\/p>\n<p><strong>b) amplitude of sound waves<\/strong><\/p>\n<p><strong>c) wavelength of sound waves<\/strong><\/p>\n<p><strong>d) loudness of sound waves<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answer is c) wavelength of sound waves<\/p>\n<p><strong>15.5. With the propagation of longitudinal waves through a medium, the quantity transmitted is<\/strong><\/p>\n<p><strong>a) matter<\/strong><\/p>\n<p><strong>b) energy<\/strong><\/p>\n<p><strong>c) energy and matter<\/strong><\/p>\n<p><strong>d) energy, matter, and momentum<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answer is b) energy<\/p>\n<p><strong>15.6. Which of the following statements are true for wave motion?<\/strong><\/p>\n<p><strong>a) mechanical transverse waves can propagate through all mediums<\/strong><\/p>\n<p><strong>b) longitudinal waves can propagate through solids only<\/strong><\/p>\n<p><strong>c) mechanical transverse waves can propagate through solids only<\/strong><\/p>\n<p><strong>d) longitudinal waves can propagate through a vacuum<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answer is c) mechanical transverse waves can propagate through solids only<\/p>\n<p><strong>15.7. A sound wave is passing through the air column in the form of compression and rarefaction. In consecutive compressions and rarefactions,<\/strong><\/p>\n<p><strong>a) density remains constant<\/strong><\/p>\n<p><strong>b) Boyle\u2019s law is obeyed<\/strong><\/p>\n<p><strong>c) bulk modulus of air oscillates<\/strong><\/p>\n<p><strong>d) there is no transfer of heat<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answer is d) there is no transfer of heat<\/p>\n<p><strong>15.8. Equation of a plane progressive wave is given by y = 0.6 sin 2\u03c0(t-x\/2). On reflection from a denser medium, its amplitude becomes 2\/3 of the amplitude of the incident wave<\/strong><\/p>\n<p><strong>a) y = 0.6 sin 2\u03c0(t+x\/2)<\/strong><\/p>\n<p><strong>b) y = -0.4 sin 2\u03c0(t+x\/2)<\/strong><\/p>\n<p><strong>c) y = 0.4 sin 2\u03c0(t+x\/2)<\/strong><\/p>\n<p><strong>d) y = -0.4 sin 2\u03c0(t-x\/2)<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answer is b) y = -0.4 sin 2\u03c0(t+x\/2)<\/p>\n<p><strong>15.9. A string of mass 2.5 kg is under a tension of 200 N. The length of the stretched string is 20.0 m. If the transverse jerk is struck at one end of the string, the disturbance will reach the other end in<\/strong><\/p>\n<p><strong>a) one second<\/strong><\/p>\n<p><strong>b) 0.5 second<\/strong><\/p>\n<p><strong>c) 2 seconds<\/strong><\/p>\n<p><strong>d) data given is insufficient<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answer is b) 0.5 second<\/p>\n<p><strong>15.10. A train whistling at constant frequency is moving towards a station at a constant speed V. The train goes past a stationary observer on the station. The frequency n\u2019 of the sound as heard by the observer is plotted as a function of time t. Identify the expected curve<\/strong><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708213\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-1.png\" alt=\"exemplar-solutions-physics-class-11-chapter-15-1\" width=\"750\" height=\"644\" srcset=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-1.png 750w, https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-1-300x258.png 300w\" sizes=\"(max-width: 750px) 100vw, 750px\" \/><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answer is c)<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708214\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-2.png\" alt=\"exemplar-solutions-physics-class-11-chapter-15-2\" width=\"750\" height=\"500\" srcset=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-2.png 750w, https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-2-300x200.png 300w\" sizes=\"(max-width: 750px) 100vw, 750px\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"Multiple_Choice_Questions_II\"><\/span>Multiple Choice Questions II<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>15.11. A transverse harmonic wave on a string is described by y (x,t) = 3.0 sin (36t + 0.018x + \u03c0\/4) where x and y are in cm and t is in s. The positive direction of x is from left to right<\/strong><\/p>\n<p><strong>a) the wave is travelling from right to left<\/strong><\/p>\n<p><strong>b) the speed of the wave is 20 m\/s<\/strong><\/p>\n<p><strong>c) frequency of the wave is 5.7 Hz<\/strong><\/p>\n<p><strong>d) the least distance between two successive crests in the wave is 2.5 cm<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answers  are<\/p>\n<p>a) the wave is travelling from right to left<\/p>\n<p>b) the speed of the wave is 20 m\/s<\/p>\n<p>c) frequency of the wave is 5.7 Hz<\/p>\n<p><strong>15.12. The displacement of a string is given by y(x,t) = 0.06 sin (2\u03c0x\/3) cos (120\u03c0t) where x and y are in m and t in s. The length of the string is 1.5 m and its mass is 3.0 \u00d7 10<sup>-2<\/sup>kg.<\/strong><\/p>\n<p><strong>a) it represents a progressive wave of frequency 60 Hz<\/strong><\/p>\n<p><strong>b) it represents a stationary wave of frequency 60 Hz<\/strong><\/p>\n<p><strong>c) it is the result of the superposition of two waves of wavelength 3 m, frequency 60 Hz each travelling with a speed of 180 m\/s in the opposite direction<\/strong><\/p>\n<p><strong>d) amplitude of this wave is constant<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answers are<\/p>\n<p>b) it represents a stationary wave of frequency 60 Hz<\/p>\n<p>c) it is the result of the superposition of two waves of wavelength 3 m, frequency 60 Hz each travelling with a speed of 180 m\/s in the opposite direction<\/p>\n<p><strong>15.13. Speed of sound waves in a fluid depends upon<\/strong><\/p>\n<p><strong>a) directly on the density of the medium<\/strong><\/p>\n<p><strong>b) square of bulk modulus of the medium<\/strong><\/p>\n<p><strong>c) inversely on the square root of density<\/strong><\/p>\n<p><strong>d) directly on the square root of bulk modulus of the medium<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answers are<\/p>\n<p>c) inversely on the square root of density<\/p>\n<p>d) directly on the square root of bulk modulus of the medium<\/p>\n<p><strong>15.14. During propagation of a plane progressive mechanical wave<\/strong><\/p>\n<p><strong>a) all the particles are vibrating in the same phase<\/strong><\/p>\n<p><strong>b) amplitude of all the particles is equal<\/strong><\/p>\n<p><strong>c) particles of the medium executes SHM<\/strong><\/p>\n<p><strong>d) wave velocity depends upon the nature of the medium<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answers are<\/p>\n<p>b) amplitude of all the particles is equal<\/p>\n<p>c) particles of the medium executes SHM<\/p>\n<p>d) wave velocity depends upon the nature of the medium<\/p>\n<p><strong>15.15. The transverse displacement of a string is given by y(x,t) = 0.06 sin (2\u03c0x\/3) cos (120\u03c0t). All the points on the string between two consecutive nodes vibrate with<\/strong><\/p>\n<p><strong>a) same frequency<\/strong><\/p>\n<p><strong>b) same phase<\/strong><\/p>\n<p><strong>c) same energy<\/strong><\/p>\n<p><strong>d) different amplitude<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answers are<\/p>\n<p>a) same frequency<\/p>\n<p>b) same phase<\/p>\n<p>d) different amplitude<\/p>\n<p><strong>15.16. A train, standing in a station yard, blows a whistle of frequency 400 Hz in still air. The wind starts blowing in the direction from the yard to the station with a speed of 10 m\/s. Given that the speed of sound in still air is 340 m\/s<\/strong><\/p>\n<p><strong>a) the frequency of sound as heard by an observer standing on the platform is 400 Hz<\/strong><\/p>\n<p><strong>b) the speed of sound for the observer standing on the platform is 350 m\/s<\/strong><\/p>\n<p><strong>c) the frequency of sound as heard by the observer standing on the platform will increase<\/strong><\/p>\n<p><strong>d) the frequency of sound as heard by the observer standing on the platform will decrease<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answers are<\/p>\n<p>a) the frequency of sound as heard by an observer standing on the platform is 400 Hz<\/p>\n<p>b) the speed of sound for the observer standing on the platform is 350 m\/s<\/p>\n<p><strong>15.17. Which of the following statements are true for a stationary wave?<\/strong><\/p>\n<p><strong>a) every particle has a fixed amplitude which is different from the amplitude of its nearest particle<\/strong><\/p>\n<p><strong>b) all the particles cross their mean position at the same time<\/strong><\/p>\n<p><strong>c) all the particles are oscillating with the same amplitude<\/strong><\/p>\n<p><strong>d) there is no net transfer of energy across any plane<\/strong><\/p>\n<p><strong>e) there are some particles which are always at rest<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The correct answers are<\/p>\n<p>a) every particle has a fixed amplitude which is different from the amplitude of its nearest particle<\/p>\n<p>b) all the particles cross their mean position at the same time<\/p>\n<p>d) there is no net transfer of energy across any plane<\/p>\n<p>e) there are some particles which are always at rest<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Very_Short_Answer\"><\/span>Very Short Answer<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>15.18. A sonometer wire is vibrating in resonance with a tuning fork. Keeping the tension applied same, the length of the wire is doubled. Under what conditions would the tuning fork still be is resonance with the wire?<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The length of the wire used in a sonometer is twice when it vibrates. Therefore, if the tuning fork resonates at L, the sonometer resonates at 2L. The following equation is used to express the frequency of the sonometer<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708215\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-1.png\" alt=\"exemplar-solutions-class-11-physics-chapter-15-img-1\" width=\"197\" height=\"87\" \/><\/p>\n<p>The velocity of the wave from the sonometer is constant. The resonance between the tuning fork and the wire will remain even after the change in the length of the wire.<\/p>\n<p>Then,<\/p>\n<p>n\/L = constant<\/p>\n<p>Which also means that,<\/p>\n<p>n<sub>1<\/sub>\/L<sub>1<\/sub> = n<sub>2<\/sub>\/L<sub>2<\/sub><\/p>\n<p>n<sub>1<\/sub>\/L<sub>1<\/sub> = n<sub>2<\/sub>\/2L<sub>2<\/sub><\/p>\n<p>n<sub>2<\/sub> = 2n<sub>1<\/sub><\/p>\n<p>Therefore, when the wire length is doubled, the resonance also gets doubled.<\/p>\n<p><strong>15.19. An organ pipe of length L open at both ends is found to vibrate in its first harmonic when sounded with a tuning fork of 480 Hz. What should be the length of a pipe closed at one end, so that it also vibrates in its first harmonic with the same tuning fork?<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708216\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-3.png\" alt=\"exemplar-solutions-physics-class-11-chapter-15-3\" width=\"750\" height=\"775\" srcset=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-3.png 750w, https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-3-290x300.png 290w\" sizes=\"(max-width: 750px) 100vw, 750px\" \/><\/p>\n<p>From the harmonic is open, L = \u03bb\/2<\/p>\n<p>\u03bb = 2L<\/p>\n<p>v\/f<sub>0<\/sub> = 2L<\/p>\n<p>(f<sub>0<\/sub>)<sub>open<\/sub> = v\/2L<\/p>\n<p>where v is the speed of the sound wave in the air.<\/p>\n<p>When the harmonic is closed, L\u2019 = \u03bb\/4<\/p>\n<p>\u03bb = 4L\u2019<\/p>\n<p>(f<sub>0<\/sub>)<sub>closed<\/sub> = v\/4L\u2019<\/p>\n<p>v\/2L = v\/4L\u2019<\/p>\n<p>L\u2019 = L\/2<\/p>\n<p><strong>15.20. A tuning fork A, marked 512 Hz, produces 5 beats per second, where sounded with another unmarked tuning fork B. If B is loaded with wax the number of beats is again 5 per second. What is the frequency of the tuning fork B when not loaded?<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>When the tuning fork B is loaded with the wax, the frequency of the tuning fork becomes less than its original frequency. When the tuning fork is marked 512 Hz, let\u2019s assume that the tuning fork B is marked to 517 Hz because it produces 5 beats per second and when it is loaded, the frequency is less than 512 Hz. So it can be said that when the tuning fork is not loaded, the frequency remains the same that is 517 Hz.<\/p>\n<p><strong>15.21. The displacement of an elastic wave is given by the function y = 3 sin \u03c9t + 4 cos \u03c9t where y is in cm and t is in second. Calculate the resultant amplitude.<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>Given,<\/p>\n<p>y = 3 sin \u03c9t + 4 cos \u03c9t<\/p>\n<p>Let\u2019s consider<\/p>\n<p>3 = a cos \u03c6<\/p>\n<p>4 = a sin \u03c6<\/p>\n<p>Then<\/p>\n<p>y = a cos \u03c6 \u03c9t + a sin \u03c6 \u03c9t<\/p>\n<p>y = a sin (\u03c9t + \u03c6)<\/p>\n<p>tan \u03c6 = 4\/3<\/p>\n<p>\u03c6 = tan<sup>-1<\/sup> 4\/3<\/p>\n<p>When the above equation is squared, we het<\/p>\n<p>a<sup>2<\/sup> = 25<\/p>\n<p>a = 5<\/p>\n<p>Therefore, the new amplitude is 5 cm.<\/p>\n<p><strong>15.22. A sitar wire is replaced by another wire of same length and material but of three times earlier radius. If the tension in the wire remains the same, by what factor will the frequency change?<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The frequency of the stretched wire is given as:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708217\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-2.png\" alt=\"exemplar-solutions-class-11-physics-chapter-15-img-2\" width=\"132\" height=\"74\" \/><\/p>\n<p>Given that,<\/p>\n<p>No.of harmonic n, length L, and tension T are the same in both the cases.<\/p>\n<p>Therefore,<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708218\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-3.png\" alt=\"exemplar-solutions-class-11-physics-chapter-15-img-3\" width=\"254\" height=\"77\" \/><\/p>\n<p>Substituting the values of mass per unit length, we get<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708219\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-4.png\" alt=\"exemplar-solutions-class-11-physics-chapter-15-img-4\" width=\"249\" height=\"74\" \/><\/p>\n<p>Solving the above the equation, we get v<sub>2<\/sub> = 1\/3 v<sub>1<\/sub><\/p>\n<p>Therefore, the frequency of sitar is reduced by 1\/2 of its actual value.<\/p>\n<p><strong>15.23. At what temperatures will the speed of sound in air be 3 times its value at 0<sup>o<\/sup>C?<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>We know that,<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708220\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-5.png\" alt=\"exemplar-solutions-class-11-physics-chapter-15-img-5\" width=\"107\" height=\"46\" \/><\/p>\n<p>Given that,<\/p>\n<p>v<sub>T<\/sub> = 3v<sub>0<\/sub><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708221\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-6.png\" alt=\"exemplar-solutions-class-11-physics-chapter-15-img-6\" width=\"349\" height=\"64\" srcset=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-6.png 349w, https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-6-300x55.png 300w\" sizes=\"(max-width: 349px) 100vw, 349px\" \/><\/p>\n<p>T = 2457 \u2013 273 = 2184<sup>o<\/sup>C<\/p>\n<p><strong>15.24. When two waves of almost equal frequencies n<sub>1<\/sub> and n<sub>2<\/sub> reach at a point simultaneously, what is the time interval between successive maxima?<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>It is given that the two frequencies are almost equal, that is n<sub>1<\/sub> = n<sub>2<\/sub>.<\/p>\n<p>For the formation of the beats, the frequencies must be n<sub>2<\/sub> &gt; n<sub>1<\/sub>.<\/p>\n<p>The no.of frequencies per second in maxima = n = n<sub>2<\/sub> \u2013 n<sub>1<\/sub><\/p>\n<p>Therefore, the time period of the maxima = 1\/n = 1\/n<sub>2<\/sub> \u2013 n<sub>1<\/sub> second.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Short_Answers\"><\/span>Short Answers<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>15.25. A steel wire has a length of 12 m and a mass of 2.10 kg. What will be the speed of a transverse wave on this wire when a tension of 2.06 \u00d7 10<sup>4<\/sup> N is applied?<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>Length, l = 12 m<\/p>\n<p>Total mass, M = 2.10 kg<\/p>\n<p>m = M\/l = 2.1\/12<\/p>\n<p>Tension, T = 2.06 \u00d7 10<sup>4<\/sup> N<\/p>\n<p>Therefore, v is given as<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708222\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-7.png\" alt=\"exemplar-solutions-class-11-physics-chapter-15-img-7\" width=\"415\" height=\"76\" srcset=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-7.png 415w, https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-7-300x55.png 300w\" sizes=\"(max-width: 415px) 100vw, 415px\" \/><\/p>\n<p>v = 343.0 m\/s<\/p>\n<p><strong>15.26. A pipe of 20 cm long is closed at one end. Which harmonic mode of the pipe is resonantly excited by a source of 1237.5 Hz?<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708223\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-4.png\" alt=\"exemplar-solutions-physics-class-11-chapter-15-4\" width=\"750\" height=\"453\" srcset=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-4.png 750w, https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-4-300x181.png 300w\" sizes=\"(max-width: 750px) 100vw, 750px\" \/><\/p>\n<p>Given,<\/p>\n<p>Length, l = 20 cm =0.2 m<\/p>\n<p>v = 1237.5 Hz<\/p>\n<p>Assuming that velocity of sound in air = 330 m\/s<\/p>\n<p>l = \u03bb\/4<\/p>\n<p>\u03bb = 4l<\/p>\n<p>We know that,<\/p>\n<p>v1= v\/ \u03bb = v\/4l<\/p>\n<p>v<sub>1<\/sub> = 412.5 Hz<\/p>\n<p>v\/v<sub>1<\/sub> = 1237.5\/412.5 = 3\/1<\/p>\n<p>Therefore, the third harmonic will have 1237.5 Hz frequency.<\/p>\n<p><strong>15.27. A train standing at the outer signal of a railway station blows a whistle of frequency 400 Hz still air. The train beings to move with a speed of 10 m\/s towards the platform. What is the frequency of the sound for an observer standing on the platform?<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>v<sub>0<\/sub> = 400 Hz<\/p>\n<p>v<sub>z<\/sub> = 10 m\/s<\/p>\n<p>Velocity of sound in air, v<sub>a<\/sub> = 330 m\/s<\/p>\n<p>v\u2019 is the frequency heard by the observer standing on the platform<\/p>\n<p>v\u2019 = (330)(400)\/320 = 412.5 Hz<\/p>\n<p><strong>15.28. The wave pattern on a stretched string is shown in the figure. Interpret what kind of wave this is and find its wavelength.<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>When particles at t = T\/4 and 3T\/4 are at rest on a stationary wave at its mean position.<\/p>\n<p>When the wave is at x = 10, 20, 30, 40 cm, the nodes in the graph have a distance with the successive node is \u03bb\/2.<\/p>\n<p>\u03bb\/2 = 30 \u2013 20 = 20<\/p>\n<p>\u03bb = 20 cm<\/p>\n<p><strong>15.29. The pattern of standing waves formed on a stretched string at two instants of time is shown in the figure. The velocity of two waves superimposing to form stationary waves is 360 m\/s, and their frequencies are 256 Hz.<\/strong><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708224\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-6.png\" alt=\"exemplar-solutions-physics-class-11-chapter-15-6\" width=\"750\" height=\"350\" srcset=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-6.png 750w, https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-6-300x140.png 300w\" sizes=\"(max-width: 750px) 100vw, 750px\" \/><\/p>\n<p><strong>a) calculate the time at which the second curve is plotted<\/strong><\/p>\n<p><strong>b) mark nodes and antinodes on the curve<\/strong><\/p>\n<p><strong>c) calculate the distance between A\u2019 and C\u2019<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>The frequency of the wave, v = 256 Hz<\/p>\n<p>T = 1\/v = 1\/256 sec = 0.00390<\/p>\n<p>T = 3.9 \u00d7 10<sup>-3<\/sup> sec<\/p>\n<p>a) When the particle\u2019s mean position changes after T\/4, the time is calculated as<\/p>\n<p>t = T\/4 = (3.9 10<sup>-3<\/sup>)\/4 = 0.975 \u00d7 10<sup>-3<\/sup> sec<\/p>\n<p>t = 9.8 \u00d7 10<sup>-4<\/sup> sec<\/p>\n<p>b) Nodes: A, B, C, D, E<\/p>\n<p>Antinode: A\u2019, C\u2019<\/p>\n<p>c) The distance between A\u2019 and C\u2019 is<\/p>\n<p>\u03bb = v\/f = 360\/256 = 1.41 m<\/p>\n<p><strong>15.30. A tuning fork vibrating with a frequency of 512 Hz is kept close to the open end of a tube filled with water. The water level in the tube is gradually lowered. When the water level is 17 cm below the open end, the maximum intensity of sound is heard. If the room temperature is 20<sup>o<\/sup>C, calculate<\/strong><\/p>\n<p><strong>a) speed of sound in air at room temperature<\/strong><\/p>\n<p><strong>b) speed of sound in air at 0<sup>o<\/sup>C<\/strong><\/p>\n<p><strong>c) if the water in the tube is replaced with mercury, will there be any difference in your observations?<\/strong><\/p>\n<p><strong><img loading=\"lazy\" class=\"alignnone size-full wp-image-708226\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-7.png\" alt=\"exemplar-solutions-physics-class-11-chapter-15-7\" width=\"750\" height=\"544\" srcset=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-7.png 750w, https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-7-300x218.png 300w\" sizes=\"(max-width: 750px) 100vw, 750px\" \/><\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p><strong><img loading=\"lazy\" class=\"alignnone size-full wp-image-708227\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-8.png\" alt=\"exemplar-solutions-physics-class-11-chapter-15-8\" width=\"750\" height=\"668\" srcset=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-8.png 750w, https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-8-300x267.png 300w\" sizes=\"(max-width: 750px) 100vw, 750px\" \/><\/strong><\/p>\n<p>Given,<\/p>\n<p>The frequency of the tuning fork, f = 512 Hz<\/p>\n<p>a) When the first maxima is considered, the length in the air column is, l = \u03bb\/4<\/p>\n<p>\u03bb = 4l<\/p>\n<p>Speed of sound, v = f \u03bb = 348.16 m\/s<\/p>\n<p>b) We know that,<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708220\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-5.png\" alt=\"exemplar-solutions-class-11-physics-chapter-15-img-5\" width=\"107\" height=\"46\" \/><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708228\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-9.png\" alt=\"exemplar-solutions-class-11-physics-chapter-15-img-9\" width=\"430\" height=\"80\" srcset=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-9.png 430w, https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-9-300x56.png 300w\" sizes=\"(max-width: 430px) 100vw, 430px\" \/><\/p>\n<p><strong>15.31. Show that when a string fixed at its two ends vibrates in 1 loop, 2 loops, 3 loops, and 4 loops, the frequencies are in the ratio 1:2:3:4.<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>When n = 1, f1 = v\/2L which is known as the fundamental frequency.<\/p>\n<p>When n = 2, f2 = 2(v\/2L) which is known as the first overtone.<\/p>\n<p>When n = 3, f3 = 3(v\/2L) which is known as second overtone.<\/p>\n<p>When n = 4, f4 = 4(v\/2L) which is known as third overtone.<\/p>\n<p>In all the cases, the tone is equal to the fundamental frequency.<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708230\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-9.png\" alt=\"exemplar-solutions-physics-class-11-chapter-15-9\" width=\"750\" height=\"990\" srcset=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-9.png 750w, https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-9-227x300.png 227w\" sizes=\"(max-width: 750px) 100vw, 750px\" \/><\/p>\n<h3><span class=\"ez-toc-section\" id=\"Long_Answers\"><\/span>Long Answers<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p><strong>15.32. The earth has a radius of 6400 km. The inner core of the 1000 km radius is solid. Outside it, there is a region from 1000 km to a radius of 3500 km which is in a molten state. Then again from 3500 km to 6400 km the earth is solid. Only longitudinal (P) waves can travel inside a liquid. Assume that the P wave has a speed of 8 km\/s in solid parts and of 5 km\/s in liquid parts of the earth. An earthquake occurs at someplace close to the surface of the earth. Calculate the time after which it will be recorded in a seismometer at a diametrically opposite point on the earth if wave travels along diameter?<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708231\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-10.png\" alt=\"exemplar-solutions-physics-class-11-chapter-15-10\" width=\"750\" height=\"652\" srcset=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-10.png 750w, https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-physics-class-11-chapter-15-10-300x261.png 300w\" sizes=\"(max-width: 750px) 100vw, 750px\" \/><\/p>\n<p>Given,<\/p>\n<p>r1 = 1000 km<\/p>\n<p>r2 = 3500 km<\/p>\n<p>r3 = 6400 km<\/p>\n<p>d1 = 1000 km<\/p>\n<p>d2 = 3500 \u2013 1000 = 2500 km<\/p>\n<p>d3 = 6400 \u2013 3500 = 2900 km<\/p>\n<p>The solid distance is given as:<\/p>\n<p>2(d1 + d3) = 2(1000 + 2900)<\/p>\n<p>Time taken by the wave during the production of an earthquake is<\/p>\n<p>(3900)(2)\/8 sec<\/p>\n<p>Liquid distance = 2d2 = (2)(2500)<\/p>\n<p>Time taken by the seismic wave in the liquid part is<\/p>\n<p>(2)(2500)\/5<\/p>\n<p>Therefore, total time taken = time taken by the wave during the production of an earthquake + time taken by the seismic wave in the liquid part<\/p>\n<p>= 32 minutes 55 seconds<\/p>\n<p><strong>15.33. If c is r.m.s speed of molecules in a gas and v is the speed of sound waves in the gas, show that c\/v is constant and independent of temperature for all diatomic gases.<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>We know following is the equation for molecules:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708233\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-10.png\" alt=\"exemplar-solutions-class-11-physics-chapter-15-img-10\" width=\"126\" height=\"94\" \/><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708234\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-11.png\" alt=\"exemplar-solutions-class-11-physics-chapter-15-img-11\" width=\"136\" height=\"82\" \/><\/p>\n<p>p\/\u03c1 = PT\/M<\/p>\n<p>Where, M is the molar mass of the gas<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708235\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-12.png\" alt=\"exemplar-solutions-class-11-physics-chapter-15-img-12\" width=\"228\" height=\"89\" \/><\/p>\n<p>c\/v is given as:<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708236\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-13.png\" alt=\"exemplar-solutions-class-11-physics-chapter-15-img-13\" width=\"197\" height=\"105\" \/><\/p>\n<p>Therefore,<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-708238\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/exemplar-solutions-class-11-physics-chapter-15-img-14.png\" alt=\"exemplar-solutions-class-11-physics-chapter-15-img-14\" width=\"298\" height=\"86\" \/><\/p>\n<p><strong>15.34. Given below are some functions of x and t to represent the displacement of an elastic wave.<\/strong><\/p>\n<p><strong>a) y = 5 cos (4x) sin (20t)<\/strong><\/p>\n<p><strong>b) y = 4 sin (5x-t\/2) + 3 cos (5x-t\/2)<\/strong><\/p>\n<p><strong>c) y = 10 cos [(252-250)\u03c0t] cos [(252+250) \u03c0t]<\/strong><\/p>\n<p><strong>d) y = 100 cos (100 \u03c0t + 0.5x)<\/strong><\/p>\n<p><strong>State which of these represent<\/strong><\/p>\n<p><strong>a) a travelling wave along -x direction<\/strong><\/p>\n<p><strong>b) a stationary wave<\/strong><\/p>\n<p><strong>c) beats<\/strong><\/p>\n<p><strong>d) a travelling wave along +x direction<\/strong><\/p>\n<p><strong>Give reasons for your answers<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>a) When a wave travels in (-x) direction, it must have +kx which is given as:<\/p>\n<p><strong>d) y = 100 cos (100 \u03c0t + 0.5x)<\/strong><\/p>\n<p>b) When a stationary wave is there then,<\/p>\n<p><strong>a) y = 5 cos (4x) sin (20t)<\/strong><\/p>\n<p>c) When beats are involved<\/p>\n<p><strong>c) y = 10 cos [(252-250)\u03c0t] cos [(252+250) \u03c0t]<\/strong><\/p>\n<p>d) a travelling wave along +x direction is<\/p>\n<p><strong>b) y = 4 sin (5x-t\/2) + 3 cos (5x-t\/2)<\/strong><\/p>\n<p><strong>15.35. In the given progressive waves y = 5 sin (100 \u03c0t \u2013 0.4 \u03c0x) where y and x are in m, t is in s. What is the<\/strong><\/p>\n<p><strong>a) amplitude<\/strong><\/p>\n<p><strong>b) wavelength<\/strong><\/p>\n<p><strong>c) frequency<\/strong><\/p>\n<p><strong>d) wave velocity<\/strong><\/p>\n<p><strong>e) particle velocity amplitude<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>Given,<\/p>\n<p>The wave is travelling in +x direction<\/p>\n<p>The equation is<\/p>\n<p>y = 5 sin (100 \u03c0t \u2013 0.4 \u03c0x)<\/p>\n<p>a) amplitude, a = 5 m<\/p>\n<p>b) wavelength, \u03bb = 2\u03c0\/ \u03bb = 5 m<\/p>\n<p>c) frequency, v = 50 Hz<\/p>\n<p>d) wave velocity, v = 250 m\/s<\/p>\n<p>e) particle velocity amplitude = 500 \u03c0 m\/s<\/p>\n<p><strong>15.36. For the harmonic travelling wave y = 2 cos 2 \u03c0(10t-0.0080x+3.5) where x and y are in cm and t is second. What is the phase difference between the oscillatory motion at two points separated by a distance of<\/strong><\/p>\n<p><strong>a) 4 m<\/strong><\/p>\n<p><strong>b) 0.5 m<\/strong><\/p>\n<p><strong>c) \u03bb\/2<\/strong><\/p>\n<p><strong>d) 3 \u03bb\/4<\/strong><\/p>\n<p><strong>e) what is the phase difference between the oscillation of a particle located at x = 100 cm at t = Ts and t = 5s?<\/strong><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>Given,<\/p>\n<p>y = 2 cos 2 \u03c0(10t-0.0080x+3.5)<\/p>\n<p>a = 2<\/p>\n<p>\u03c9 = 20 \u03c0<\/p>\n<p>k = 0.016 \u03c0<\/p>\n<p>\u03c6 = 7 \u03c0<\/p>\n<p>a) path difference, p = 4m = 400 cm<\/p>\n<p>Substituting the values, we get phase difference = 6.4 \u03c0rad<\/p>\n<p>b) path difference, p = 0.5 m = 50 cm<\/p>\n<p>Substituting the values, we get phase difference = 0.8 \u03c0 rad<\/p>\n<p>c) path difference, p = \u03bb\/2<\/p>\n<p>Substituting the values, we get phase difference = \u03c0 rad<\/p>\n<p>d) path difference, p = 3 \u03bb\/4<\/p>\n<p>Substituting the values, we get phase difference = 98 \u03c0 rad<\/p>\n<h3><span class=\"ez-toc-section\" id=\"About_Infinity_Learn_Solutions\"><\/span>About Infinity Learn Solutions<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Infinity Learn mission is to create world-class learning content for students. We are focussed on raising the students learning abilities. These Solutions have been structured very carefully to give several benefits to the students that utilize these study materials. That is why, these are crafted by subject matter experts to focus on concept and its explanation.For any type of support related to the <a href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/\"><strong>NCERT Exemplar Solutions for Class 11<\/strong><\/a> given here, students can approach our support team who will help clear all their doubts. Students can also check out Infinite Learn for a more efficient learning experience.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"Frequently_Asked_Questions\"><\/span>Frequently Asked Questions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\t\t<section class=\"sc_fs_faq sc_card \">\n\t\t\t<div>\n\t\t\t\t<h2><span class=\"ez-toc-section\" id=\"Why_should_I_refer_to_these_NCERT_Exemplar_Solutions\"><\/span>Why should I refer to these NCERT Exemplar Solutions?<span class=\"ez-toc-section-end\"><\/span><\/h2>\t\t\t\t<div>\n\t\t\t\t\t\t\t\t\t\t<p>\n\t\t\t\t\t\tThe NCERT Exemplar Solutions of this Chapter by infinite learn are made with the main aim of helping students to focus on the important concepts. Each and every detail is explained with utmost care to enhance the conceptual knowledge among students. The solutions consists of various shortcut techniques which can be used to remember the concepts effectively. Students use the solutions while answering the textbook questions and understand the method of answering them without any difficulty.\t\t\t\t\t<\/p>\n\t\t\t\t<\/div>\n\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t<section class=\"sc_fs_faq sc_card \">\n\t\t\t<div>\n\t\t\t\t<h2><span class=\"ez-toc-section\" id=\"How_to_score_full_marks_in_Chapter_15_of_NCERT_Exemplar_Solutions_for_Class_11_Physics\"><\/span>How to score full marks in Chapter 15 of NCERT Exemplar Solutions for Class 11 Physics?<span class=\"ez-toc-section-end\"><\/span><\/h2>\t\t\t\t<div>\n\t\t\t\t\t\t\t\t\t\t<p>\n\t\t\t\t\t\tThe NCERT Exemplar Solutions of this Chapter is prepared by our highly experienced faculty after doing vast research on each concept. During solving of textbook questions, students can use these solutions to get an overall idea about the topics covered in this chapter. The solutions are provided in both online and offline mode as per the needs of students. The PDF format of solutions are available at Infinite learn which can be downloaded and used by the students to get their doubts cleared instantly.\t\t\t\t\t<\/p>\n\t\t\t\t<\/div>\n\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t<section class=\"sc_fs_faq sc_card \">\n\t\t\t<div>\n\t\t\t\t<h2><span class=\"ez-toc-section\" id=\"How_to_differentiate_the_transverse_and_longitudinal_waves_in_these_NCERT_Exemplar_Solutions\"><\/span>How to differentiate the transverse and longitudinal waves in these NCERT Exemplar Solutions?<span class=\"ez-toc-section-end\"><\/span><\/h2>\t\t\t\t<div>\n\t\t\t\t\t\t\t\t\t\t<p>\n\t\t\t\t\t\tThe waves and its properties are the major concepts which is included in Chapter 15. From this, students can differentiate longitudinal and transverse as how the question is present in NCERT textbook. Students can also download the NCERT Exemplar Solutions from Infinite learn in order to clearly understand the concepts, which are important according to the second term CBSE Syllabus for Class 11.\t\t\t\t\t<\/p>\n\t\t\t\t<\/div>\n\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t<section class=\"sc_fs_faq sc_card \">\n\t\t\t<div>\n\t\t\t\t<h2><span class=\"ez-toc-section\" id=\"Why_Opt_for_Infinity_Learn\"><\/span>Why Opt for Infinity Learn?<span class=\"ez-toc-section-end\"><\/span><\/h2>\t\t\t\t<div>\n\t\t\t\t\t\t\t\t\t\t<p>\n\t\t\t\t\t\tIn this chapter Infinity Learn provides videos, notes, NCERT text book solutions, other practice book solutions and assignments that help you learn the concepts and to memorise the concepts for entrance exams and board exams. Most important, Infinity learn provide instant doubt support by subject experts.\t\t\t\t\t<\/p>\n\t\t\t\t<\/div>\n\t\t\t<\/div>\n\t\t<\/section>\n\t\t\n<script type=\"application\/ld+json\">\n\t{\n\t\t\"@context\": \"https:\/\/schema.org\",\n\t\t\"@type\": \"FAQPage\",\n\t\t\"mainEntity\": [\n\t\t\t\t\t{\n\t\t\t\t\"@type\": \"Question\",\n\t\t\t\t\"name\": \"Why should I refer to these NCERT Exemplar Solutions?\",\n\t\t\t\t\"acceptedAnswer\": {\n\t\t\t\t\t\"@type\": \"Answer\",\n\t\t\t\t\t\"text\": \"The NCERT Exemplar Solutions of this Chapter by infinite learn are made with the main aim of helping students to focus on the important concepts. Each and every detail is explained with utmost care to enhance the conceptual knowledge among students. The solutions consists of various shortcut techniques which can be used to remember the concepts effectively. Students use the solutions while answering the textbook questions and understand the method of answering them without any difficulty.\"\n\t\t\t\t\t\t\t\t\t}\n\t\t\t}\n\t\t\t,\t\t\t\t{\n\t\t\t\t\"@type\": \"Question\",\n\t\t\t\t\"name\": \"How to score full marks in Chapter 15 of NCERT Exemplar Solutions for Class 11 Physics?\",\n\t\t\t\t\"acceptedAnswer\": {\n\t\t\t\t\t\"@type\": \"Answer\",\n\t\t\t\t\t\"text\": \"The NCERT Exemplar Solutions of this Chapter is prepared by our highly experienced faculty after doing vast research on each concept. During solving of textbook questions, students can use these solutions to get an overall idea about the topics covered in this chapter. The solutions are provided in both online and offline mode as per the needs of students. The PDF format of solutions are available at Infinite learn which can be downloaded and used by the students to get their doubts cleared instantly.\"\n\t\t\t\t\t\t\t\t\t}\n\t\t\t}\n\t\t\t,\t\t\t\t{\n\t\t\t\t\"@type\": \"Question\",\n\t\t\t\t\"name\": \"How to differentiate the transverse and longitudinal waves in these NCERT Exemplar Solutions?\",\n\t\t\t\t\"acceptedAnswer\": {\n\t\t\t\t\t\"@type\": \"Answer\",\n\t\t\t\t\t\"text\": \"The waves and its properties are the major concepts which is included in Chapter 15. From this, students can differentiate longitudinal and transverse as how the question is present in NCERT textbook. Students can also download the NCERT Exemplar Solutions from Infinite learn in order to clearly understand the concepts, which are important according to the second term CBSE Syllabus for Class 11.\"\n\t\t\t\t\t\t\t\t\t}\n\t\t\t}\n\t\t\t,\t\t\t\t{\n\t\t\t\t\"@type\": \"Question\",\n\t\t\t\t\"name\": \"Why Opt for Infinity Learn?\",\n\t\t\t\t\"acceptedAnswer\": {\n\t\t\t\t\t\"@type\": \"Answer\",\n\t\t\t\t\t\"text\": \"In this chapter Infinity Learn provides videos, notes, NCERT text book solutions, other practice book solutions and assignments that help you learn the concepts and to memorise the concepts for entrance exams and board exams. Most important, Infinity learn provide instant doubt support by subject experts.\"\n\t\t\t\t\t\t\t\t\t}\n\t\t\t}\n\t\t\t\t\t\t]\n\t}\n<\/script>\n\n<p>Now you can find answer to all your subject queries &amp; prepare for your Exams on our <a href=\"https:\/\/play.google.com\/store\/apps\/details?id=com.infinitylearn.learn&amp;referrer=utm_source%3Dsurge%26utm_medium%3Dbutton%26utm_campaign%3Dsurge\"><strong>Educational App &#8211; Infinity Learn<\/strong><\/a>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Class 11 Physics NCERT Exemplar Solutions for Chapter 15 Waves Multiple Choice Questions I 15.1. Water waves produced by a [&hellip;]<\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"NCERT Exemplar for Class 11 Physics Chapter 15","_yoast_wpseo_title":"NCERT Exemplar for Class 11 Physics Chapter 15 - Waves","_yoast_wpseo_metadesc":"Get NCERT Exemplar for Class 11 Physics Chapter 15 - Waves at infinity learn","custom_permalink":"study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/"},"categories":[107,105,114],"tags":[],"table_tags":[],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v17.9 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Exemplar for Class 11 Physics Chapter 15 - Waves<\/title>\n<meta name=\"description\" content=\"Get NCERT Exemplar for Class 11 Physics Chapter 15 - Waves at infinity learn\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-exemplar-solutions\/class-11\/physics\/chapter-15-waves\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Exemplar for Class 11 Physics Chapter 15 - 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