{"id":77208,"date":"2022-02-12T13:21:42","date_gmt":"2022-02-12T07:51:42","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/?p=77208"},"modified":"2025-05-29T10:24:47","modified_gmt":"2025-05-29T04:54:47","slug":"ncert-solutions-for-class-6-maths-mensuration-exercise-10-3","status":"publish","type":"post","link":"https:\/\/infinitylearn.com\/surge\/ncert-solutions\/class-6\/maths\/ncert-solutions-for-class-6-maths-mensuration-exercise-10-3\/","title":{"rendered":"NCERT Solutions For Class 6 Maths Mensuration Exercise 10.3"},"content":{"rendered":"<h2>NCERT Solutions For Class 6 Maths Mensuration Exercise 10.3<\/h2>\n<p>&nbsp;<\/p>\n<p><strong>NCERT Solutions For Class 6 Maths Chapter 10 Mensuration Ex 10.3<\/strong><\/p>\n<p style=\"text-align: center;\"><strong>Exercise 10.3<\/strong><\/p>\n<p>Ex 10.3 Class 6 Maths Question 1.<br \/>\nFind the areas of the rectangles whose sides are:<br \/>\n(a) 3 cm and 4 cm<br \/>\n(b) 12 m and 21 m<br \/>\n(c) 2 km and 3 km<br \/>\n(d) 2 m and 70 cm<br \/>\nSolution:<br \/>\n(a) Length of the rectangle = 3 cm<br \/>\nBreadth of the rectangle = 4 cm<br \/>\n\u2234 Area of the rectangle = length x breadth = 3 cm x 4 cm<br \/>\n= 12 cm<sup>2<\/sup> or 12 sq cm<\/p>\n<p>(b) Length of the rectangle = 12 m and breadth = 21 m<br \/>\n\u2234 Area of the rectangle = length x breadth = 12 m x 21 m<br \/>\n= 252 m<sup>2<\/sup> or 252 sq m<\/p>\n<p>(c) Length of the rectangle = 2 km and breadth 3 km<br \/>\n\u2234 Area of the rectangle = length x breadth = 2 km x 3 km<br \/>\n= 6 km<sup>2<\/sup> or 6 sq km<\/p>\n<p>(d) Length of the rectangle = 2 m<br \/>\nand breadth = 70 cm or 0.70 m<br \/>\n\u2234 Area of the rectangle = length x breadth = 2 m x 0.70 m<br \/>\n= 1.40 m<sup>2<\/sup> or 1.40 sq m<\/p>\n<p>Ex 10.3 Class 6 Maths Question 2.<br \/>\nFind the areas of the squares whose sides are:<br \/>\n(a) 10 cm<br \/>\n(b) 14 cm<br \/>\n(c) 5 m<br \/>\nSolution:<br \/>\n(a) Side of the square = 10 cm<br \/>\n\u2234 Area of the square = Side x Side = 10 cm x 10 cm = 100 cm<sup>2<\/sup> or 100 sq cm<br \/>\n(b) Side of the square = 14 cm<br \/>\n\u2234 Area of the square = Side x Side = 14 cm x 14 cm = 196 cm<sup>2<\/sup> or 196 sq cm<br \/>\n(c) Side of the square = 5 m<br \/>\n\u2234 Area of the square = Side x Side = 5 m x 5 m = 25 m<sup>2<\/sup> or 25 sq m<\/p>\n<p>Ex 10.3 Class 6 Maths Question 3.<br \/>\nThe length and breadth of three rectangles are as given below:<br \/>\n(a) 9 m and 6 m<br \/>\n(b) 17 m and 3 m<br \/>\n(c) 4 m and 14 m<br \/>\nWhich one has the largest area and which one has the smallest?<br \/>\nSolution:<br \/>\n(a) Length of the rectangle = 9 m<br \/>\nand breadth = 6 m<br \/>\n\u2234 Area of the rectangle = length x breadth<br \/>\n= 9 m x 6 m<br \/>\n= 54 m<sup>2<\/sup> or 54 sq m<\/p>\n<p>(b) Length of the rectangle = 17 m<br \/>\nand breadth = 3m<br \/>\n\u2234 Area of the rectangle<br \/>\n= length x breadth = 17 m x 3 m 51 m<sup>2<\/sup> or 51 sq m<\/p>\n<p>(c) Length of the rectangle = 4 m<br \/>\nand breadth = 14 m<br \/>\nArea of the rectangle = length x breadth<br \/>\n= 4 m x 14 m<br \/>\n= 56 m<sup>2<\/sup> or 56 sq m<br \/>\nRectangle (c) has the largest area, i.e., 56 sq m and Rectangle (b) has the smallest area, i.e., 51 sq m.<\/p>\n<p>Ex 10.3 Class 6 Maths Question 4.<br \/>\nThe area of a rectangular garden 50 m long is 300 sq m. Find the width of the garden.<br \/>\nSolution:<br \/>\nLength of the rectangular garden = 50 m<br \/>\nArea of the rectangular garden = 300 sq m<br \/>\n\u2234 Width = Area \u00f7 Length<br \/>\n= 300 sq m \u00f7 50 m = 6 m<br \/>\nHence width of the garden = 6 m.<\/p>\n<div class=\"card\"><a class=\"btn btn-primary\" href=\"https:\/\/infinitylearn.com\/online-courses-cbse-class-6?utm_source=surge&amp;utm_medium=interlinking\"><br \/>\n<img loading=\"lazy\" class=\" lazyloaded\" style=\"width: 100%; border-radius: 10px;\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2024\/09\/class-6-cbse-foundation-course.png\" alt=\"class 6 hots course\" width=\"1201\" height=\"636\" data-src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2024\/08\/hots.png\" \/><\/a><a class=\"btn btn-primary\" href=\"https:\/\/infinitylearn.com\/online-courses-cbse-class-6?utm_source=surge&amp;utm_medium=interlinking\"><button><strong>Class 6 CBSE Foundation Course<\/strong><\/button><\/a><\/p>\n<div>The Class 6 CBSE Foundation Course is designed to be the most competitive educational program in India, providing an exceptional online learning experience. Our focused batch encompasses all crucial subjects, ensuring comprehensive preparation for students.<\/div>\n<\/div>\n<p>Ex 10.3 Class 6 Maths Question 5.<br \/>\nWhat is the cost of tiling a rectangular plot of land 500 m long and 200 m wide at the rate of \u20b98 per hundred sq m?<br \/>\nSolution:<br \/>\nLength of the rectangular plot = 500 m<br \/>\nand the breadth = 200 m<br \/>\n\u2234 Area of the plot = length x breadth = 500 m x 200 m = 100000 sq m<br \/>\nNow rate of tiling the plot = \u20b98 per 100 sq m<br \/>\nCost of tiling the garden = \u20b9(\\(\\frac { 8 }{ 100 }\\)x 100000 ) = \u20b98000<br \/>\nHence the required cost = \u20b98000<\/p>\n<p>Ex 10.3 Class 6 Maths Question 6.<br \/>\nA table-top measures 2 m by 1 m 50 cm. What is its area in square metres?<br \/>\nSolution:<br \/>\nLength of the table-top = 2 m<br \/>\nand its breadth = 1 m 50 cm or 1.50 m<br \/>\n\u2234 Area of the table-top = length x breadth<br \/>\n= 2 m x 1.50 m<br \/>\n= 3 m<sup>2<\/sup> or 3 sq m<br \/>\nHence, the area of table-top = 3 sq m.<\/p>\n<p>Ex 10.3 Class 6 Maths Question 7.<br \/>\nA room is 4 m long and 3 m 50 cm wide. How many square metres of carpet is needed to cover the floor of the room?<br \/>\nSolution:<br \/>\nLength of the room = 4 m<br \/>\nand its breadth = 3 m 50 cm = 3.5 m<br \/>\nArea of the room = length x breadth<br \/>\n= 4 m x 3.5 m = 14 sq m<br \/>\nHence, the area of the carpet needed = 14 sq m<\/p>\n<p>Ex 10.3 Class 6 Maths Question 8.<br \/>\nA floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted.<br \/>\nSolution:<br \/>\nLength of the floor = 5 m<br \/>\nand its breadth = 4 m<br \/>\n\u2234 Area of the floor = length x breadth<br \/>\n= 5m x 4m = 20sqm<br \/>\nSide of the carpet = 3m<br \/>\n\u2234 Area of the square carpet = side x side = 3m x 3m = 9 sqm<br \/>\n\u2234 Area of the floor which is not carpeted = 20 sq m \u2013 9 sq m<br \/>\n= 11 sq m.<\/p>\n<p>Ex 10.3 Class 6 Maths Question 9.<br \/>\nFive square flower beds each of side 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?<br \/>\nSolution:<br \/>\nSide of the square flower bed = 1 m.<br \/>\n\u2234 Area of 1 square flower bed = 1m x 1m = 1sqm.<br \/>\n\u2234 Area of 5 square flower beds = 1 sq m x 5 = 5 sq m.<br \/>\nNow length of the land = 5 m<br \/>\nand its breadth = 4 m<br \/>\n\u2234 Area of the land = length x breadth =5m x 4m = 20 sq m<br \/>\n\u2234 Area of the remaining part of the land = 20 sq m \u2013 5 sq m<br \/>\n= 15 sq m.<\/p>\n<p>Ex 10.3 Class 6 Maths Question 10.<br \/>\nBy splitting the following figures into rectangles, find their areas (The measures are given in centimetres).<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-74554\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/NCERT-Solutions-For-Class-6-Maths-Chapter-10-Mensuration-Ex-10.-3-Q10-1.png\" alt=\"NCERT Solutions For Class 6 Maths Chapter 10 Mensuration \" width=\"209\" height=\"338\" \/><br \/>\nSolution:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-74555\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/NCERT-Solutions-For-Class-6-Maths-Chapter-10-Mensuration-Ex-10.-3-Q10a-1.png\" alt=\"NCERT Solutions For Class 6 Maths Chapter 10 Mensuration\" width=\"213\" height=\"170\" \/><br \/>\nSplitting the given figure into the rectangles I, II, III and IV, we have<br \/>\nArea of the rectangle I = length x breadth<br \/>\n= 4 cm x 3 cm = 12 sq cm<br \/>\nArea of the rectangle II = length x breadth<br \/>\n= 3 cm x 2 cm = 6 sq cm.<br \/>\nArea of the rectangle III = length x breadth<br \/>\n= 4 cm x 1 cm = 4 sq cm<br \/>\nArea of the rectangle IV = length x breadth<br \/>\n= 3 cm x 2 cm = 6 sq cm<br \/>\n\u2234 Total area of the whole figure<br \/>\n= 12 sq cm + 6 sq cm + 4 sq cm + 6 sq cm<br \/>\n= 28 sq cm.<\/p>\n<p>(b) Splitting the given figure into the rectangles I, II and III, we get<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-74557\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/NCERT-Solutions-For-Class-6-Maths-Chapter-10-Mensuration-Ex-10.-3-Q10b.png\" alt=\"NCERT Solutions For Class 6 Maths Chapter 10 Mensuration\" width=\"177\" height=\"139\" \/><br \/>\nArea of the rectangle I<br \/>\n= 12 cm x 2 cm = 24 sq cm<br \/>\nArea of the rectangle II<br \/>\n= 8 cm x 2 cm = 16 sq cm<br \/>\nArea of rectangle III<br \/>\n= 3 cm x 1 cm = 3 sq cm<br \/>\n\u2234 Total area of the given figure = 3 sq cm + 3 sq cm + 3 sq cm = 9 sq cm.<\/p>\n<p>Ex 10.3 Class 6 Maths Question 11.<br \/>\nSplit the following shapes into rectangles and find their areas (The measures are given in centimetres).<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-74558\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/NCERT-Solutions-For-Class-6-Maths-Chapter-10-Mensuration-Ex-10.-3-Q11.png\" alt=\"NCERT Solutions For Class 6 Maths Chapter 10 Mensuration\" width=\"267\" height=\"385\" \/><br \/>\nSolution:<br \/>\n(a) Splitting the given figure into the rectangles I and II, we get<br \/>\nArea of the rectangle I<br \/>\n= 12 cm x 2 cm = 24 sq cm<br \/>\nArea of the rectangle II<br \/>\n= 8 cm x 2 cm = 16 sq cm<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-74561\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/NCERT-Solutions-For-Class-6-Maths-Chapter-10-Mensuration-Ex-10.-3-Q11a-2.png\" alt=\"NCERT Solutions For Class 6 Maths Chapter 10 Mensuration\" width=\"178\" height=\"216\" \/><br \/>\n\u2234 Total area of the whole figure = 24 sq cm + 16 sq cm = 40 sq cm.<\/p>\n<p>(b) Splitting the given figure into the rectangles I, II and III, we get<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-74562\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2022\/01\/NCERT-Solutions-For-Class-6-Maths-Chapter-10-Mensuration-Ex-10.-3-Q11b.png\" alt=\"NCERT Solutions For Class 6 Maths Chapter 10 Mensuration\" width=\"186\" height=\"184\" \/><br \/>\nArea of the rectangle I<br \/>\n= 7 cm x 7 cm = 49 sq cm<br \/>\nArea of the rectangle II<br \/>\n= 21 cm x 7 cm = 147 sq cm<br \/>\nArea of the rectangle III<br \/>\n= 7 cm x 7 cm = 49 sq cm<br \/>\n\u2234 Total area of the whole figure<br \/>\n= 49 sq cm + 147 sq cm + 49 sq cm<br \/>\n= 245 sq cm.<\/p>\n<p>Ex 10.3 Class 6 Maths Question 12.<br \/>\nHow many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively:<br \/>\n(a) 100 cm and 144 cm<br \/>\n(b) 70 cm and 36 cm<br \/>\nSolution:<br \/>\nLength of one tile = 12 cm<br \/>\nBreadth of the tile = 5 cm<br \/>\n\u2234 Area of 1 tile = length x breadth = 12 cm x 5 cm = 60 sq cm<\/p>\n<p>(a) Length of the rectangular region = 144 cm<br \/>\nBreadth of the region = 100 cm<br \/>\n\u2234 Area of the rectangular region = length x breadth = 144 cm x 100 cm<br \/>\n= 14400 sq cm<br \/>\n\u2234 Number of tiles needed to cover the whole rectangular region<br \/>\n= 14400 sq cm \u00f7 60 sq cm<br \/>\n= 240 tiles<\/p>\n<p>(b) Length of the rectangular region = 70 cm<br \/>\nBreadth of the region = 36 cm<br \/>\n\u2234 Area of the rectangular region = length x breadth = 70 cm x 36 cm = 2520 sq cm<br \/>\n\u2234 Number of tiles needed to cover the whole rectangular region<br \/>\n= 2520 sq cm \u00f7 60 sq cm<br \/>\n= 42 tiles.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions For Class 6 Maths Mensuration Exercise 10.3 &nbsp; NCERT Solutions For Class 6 Maths Chapter 10 Mensuration Ex [&hellip;]<\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"\"Get NCERT Solutions For Class 6 Maths Mensuration Exercise 10.3 on Infinity 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