{"id":77283,"date":"2022-02-14T19:48:48","date_gmt":"2022-02-14T14:18:48","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/?p=77283"},"modified":"2022-11-17T19:02:11","modified_gmt":"2022-11-17T13:32:11","slug":"study-materials-ncert-solutions-class-6-maths-chapter-3-playing-with-numbers-exercise-3-3","status":"publish","type":"post","link":"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions\/class-6\/maths\/chapter-3-playing-with-numbers-exercise-3-3\/","title":{"rendered":"NCERT Solutions For Class 6 Maths Playing With Numbers Exercise 3.3"},"content":{"rendered":"

NCERT Solutions For Class 6 Maths Playing With Numbers Exercise 3.3<\/span><\/h2>\n

Question 1.<\/span><\/strong><\/p>\n

Using divisibility tests, determine which of the following numbers are divisible by 2, by 3, by 4, by 5, by 6, by 8, by 9, by 10, by 11 (Say, Yes or No)<\/p>\n

\"NCERT<\/p>\n

Solution:<\/span><\/strong><\/p>\n

\"NCERT<\/p>\n

Question 2.<\/strong><\/span><\/p>\n

Using divisibility tests, determine which of the following numbers are divisible by 4; by 8.<\/p>\n

(a) 572
\n(b) 726352
\n(c) 5500
\n(d) 6000
\n(e) 12159
\n(f) 14560
\n(g) 21084
\n(j) 2150
\n(h) 31795072
\n(i) 1700<\/p>\n

Solution:<\/strong><\/span><\/p>\n

(a) Given number = 572
\n(i) Divisibility by 4
\nHere, the number formed by the last two digits of the given number is 72.
\n\"NCERT
\nRemainder 0. Hence, 572 is divisible by 4.<\/p>\n

(ii) Divisibility by 8
\nHere, the number formed by the last three digits of the given number is 572.
\n\"NCERT
\nRemainder 4. Hence, 572 is not divisible by 8.<\/p>\n

(b) Given number = 726352
\n(i) Divisibility by 4
\nHere, the number formed by the last two digits of the given number = 52.
\n\"NCERT
\nRemainder = 0.
\nHence, 726352 is divisible by 4.<\/p>\n

(ii) Divisibility by 8
\nHere, the number formed by the last three digits of the given number = 352
\n\"NCERT
\nRemainder = 0.
\nHence, 726352 is divisible by.<\/p>\n

(c) Given number = 5500
\n(i) Divisibility by 4
\nHere the last two digits of the given number are 0. Hence, 5500 is divisible by 4.
\n(ii) Divisibility by 8
\nHere, the number formed by the last three digits of the given number = 500
\n\"NCERT
\nRemainder = 4. Hence, 5500 is not divisible by 8.<\/p>\n

(d) Given number = 6000
\n(i) Divisibility by 4
\nHere, the last two digits of the given number are 0.
\nHence, 6000 is divisible by 4.<\/p>\n

(ii) Divisibility by 8
\nHere, the last three digits of the given number are 0.
\nHence, 6000 is divisible by 8.<\/p>\n

(e) Given number = 12159
\n(i) Divisibility by 4
\nHere, the number formed by the last two digits of the given number = 59
\n\"NCERT
\nRemainder = 3.
\nHence, 12159 is divisible by 4.<\/p>\n

(ii) Divisibility by 8
\nHere, the number formed by the last three digits of the given number = 159
\n\"NCERT
\nRemainder = 7.
\nHence, 12159 is not divisible by 8.<\/p>\n

(f) Given number = 14560
\n(i) Divisibility by 4
\nHere, the number formed by the last two digits of the given number = 60.
\n\"NCERT
\nRemainder = 0.
\nHence, 14560 is divisible by 8.<\/p>\n

(g) Given number = 21084
\n(i) Divisibility by 4
\nHere, the number formed by the last two digits of the given number = 84.
\n\"NCERT
\nRemainder = 0. Hence, 21084 is divisible by 4.<\/p>\n

(ii) Divisibility by 8
\nHere, the number formed by the last three digits of the given number = 084.
\n\"NCERT
\nRemainder = 4.
\nHence, 21084 is not divisible by 8.<\/p>\n

(h) Given number = 31795072
\n(i) Divisibility by 4
\nHere, the number formed by the last two digits of the given number = 72.
\n\"NCERT
\nRemainder = 0. Hence, 31795072 is divisible by 4.<\/p>\n

(ii) Divisibility by 8
\nHere, the number formed by the last three digits of the given number = 072.
\n\"NCERT
\nRemainder = 0. Hence, 31795072 is divisible by 8.<\/p>\n

(i) Given number = 1700
\n(i) Divisibility by 4
\nHere, the last two digits of the given number is 0. Hence, 1700 is divisible by 4.
\n(ii) Divisibility by 8
\nHere, the number formed by the last three digits of the given number = 700
\n\"NCERT
\nRemainder = 4. Hence, 1700 is not divisible by 8.
\n(j) Given number = 2150
\n(i) Divisibility by 4
\nHere, the number formed by the last two digits of the given number = 50.
\n\"NCERT
\nRemainder = 2. Hence, 2150 is not divisible by 4.<\/p>\n

(ii) Divisibility by 8
\nHere, the number formed by the last three digits of the given number = 150
\n\"NCERT
\nRemainder = 6. Hence, 2150 is not divisible by 8.<\/p>\n

Question 3.
\nUsing divisibility tests, determine which of the following numbers are divisible by 6:
\n(a) 297144
\n(b) 1258
\n(c) 4335
\n(d) 61233
\n(e) 901352
\n(f) 438750
\n(g) 1790184
\n(h) 12583
\n(i) 639210
\n(j) 17852
\nSolution:
\nWe know that a number is divisible by 6 if it is also divisible by both 2 and 3.
\n(a) Given number = 297144
\nThe given number 297144 has an even digit at one’s place.
\nSo, it is divisible by 2.
\nThe sum of all the digits of 297144 = 2 + 9 + 7 + 1 + 4 + 4 = 27
\nwhich is divisible by 3.
\nHence, the given number 297144 is divisible by 6.<\/p>\n

(b) Given number = 1258
\nThe given number 1258 has an even digit i.e., 8 at its one place.
\nSo, it is divisible by 2.
\nThe sum of all digits of 1258 = l + 2 + 5 + 8 = 16 which is not divisible by 3.
\nHence, the given number 1258 is not divisible by 6.<\/p>\n

(c) Given number = 4335
\nThe digit at one’s place of the given number is not even.
\nSo, it is not divisible by 2.
\nThe sum of all the digits of 4335 = 4 + 3 + 3 + 5 = 15 which is divisible by 3.
\nSince the given number 4335 is not divisible by both 2 and 3 therefore, it is not divisible by 6.<\/p>\n

(d) Given number = 61233
\nThe digit at ones place of the given number is not even.
\nSo, it is not divisible by 2.
\nThe sum of the digits of the given number 61233 = 6 + 1 + 2 + 3 + 3 = 15 which is divisible by 3.
\nSince, the given number is not divisible by both 2 and 3, it is not divisible by 6.<\/p>\n

(e) Given number = 901352
\nThe digit at ones place of the given number is even.
\nSo, it is divisible by 2.
\nThe sum of all the digits of the given number 901352 = 9 + 0 + 1 + 3 + 5 + 2 = 20 which is not divisible by 3.
\nSince, the given number is not divisible by both 2 and 3 hence, it is not divisible by 6.<\/p>\n

(f) Given number = 438750
\nThe digit at ones place of the given number is 0. So, it is divisible by 2.
\nThe sum of all the digits of the given number 438750
\n=4 + 3 + 8 + 7 + 5 + 0 = 27 which is divisible by 3.
\nHence, the given number is divisible by 6.<\/p>\n

(g) Given number = 1790184
\nThe digit at ones place of the given number is even.
\nSo, it is divisible by 2.
\nThe sum of all the digits of the given number 1790184
\n= 1 + 7 + 9 + 0 + 1 + 8 + 4 = 30 which is divisible by 3.
\nHence, the given number is divisible by 6.<\/p>\n

(h) Given number = 12583
\nThe digit to ones place of the given number is odd.
\nSo, it is not divisible by 2.
\nSum of all the digits of the given number 12583
\n= 1 + 2 + 5 + 8 + 3 = 19
\nwhich is not divisible by 3.
\nHence, the given number is not divisible by 6.<\/p>\n

(i) Given number = 639210
\nThe digit at ones place of the given number is 0.
\nSo, it is divisible by 2.
\nThe sum of all the digits of the given number 639210
\n= 6 + 3 + 9 + 2 + 1 + 0 = 21 which is divisible by 3.
\nHence, the given number is divisible by 6.<\/p>\n

(j) Given number = 17852
\nThe digit at ones place of the given number is even.
\nSo, it is divisible by 2.
\nThe sum of all the digits of the given number 17852
\n= 1 + 7 + 8 + 5 + 2 = 23 which is not divisible by 3.
\nHence, the given number is not divisible by 6.<\/p>\n

Question 4.
\nUsing divisibility tests, determine which of the following numbers are divisible by 11:
\n(a) 5445
\n(b) 10824
\n(c) 7138965
\n(d) 70169308
\n(e) 10000001.
\nSol. We know that a number is divisible by 11 if the difference between the sum of the digits at odd places (from the right) and the sum of the digits at even places (from the right) of the number is either 0 or divisible by 11.
\n(a) Given number = 5445
\nSum of the digits at odd places = 5 + 4 = 9
\nSum of the digits at even places = 4 + 5 = 9
\nDifference = 9 \u2013 9 = 0
\nHence, the given number is divisible by 11.<\/p>\n

(b) Given number = 10824
\nSum of the digits at odd places = 4 + 8 + 1 = 13
\nSum of the digits at even places = 2 + 0 = 2
\nDifference = 13 \u2013 2 = 11
\nwhich is divisible by 11.
\nHence, the given number is divisible by 11.<\/p>\n

(c) Given number = 7138965
\nSum of the digits at odd places = 5 + 9 + 3 + 7 = 24
\nSum of the digits at even places = 6 + 8 + 1 = 15
\nDifference = 24 \u2013 15 = 9
\nwhich is not divisible by 11.
\nHence, the given number is not divisible by 11.<\/p>\n

(d) Given number = 70169308
\nSum of all the digits at odd places = 8 + 3 + 6 + 0 = 17
\nSum of all the digits at even places = 0 + 9 + 1 + 7 = 17
\nDifference = 17-17 = 0
\nHence, the given number is divisible by 11.<\/p>\n

(e) Given number = 10000001
\nSum of all the digits at odd places = 1 + 0 + 0 + 0 = 1
\nSum of all the digits at even places = 0 + 0 + 0 + 1 = 1
\nDifference = 1 \u2013 1 = 0
\nHence, the given number is divisible by 11.<\/p>\n

Question 5.
\nWrite the smallest digit and the greatest digit in the blank space of each of the following numbers so that the number formed is divisible by 3.
\n(a) ____ 6724
\n(b) 4765 ____ 2
\nSolution:
\nWe know that number is divisible by 3 if the sum of all the digits of the number is also divisible by 3.
\n(a) ___ 6724
\nSum of the digits = 4 + 2 + 7 + 6 = 19
\nThe smallest digit to be placed is blank space = 2
\nThen the sum = 19 + 2 = 21 which is divisible by 3.
\nThe greatest digit to be placed in blank space = 8
\nThen, the sum = 19 + 8 = 27 which is divisible by 3
\nHence, the required digits are 2 and 8.<\/p>\n

(b) 4765 ____ 2.
\nSum of digits = 2 + 5 + 6 + 7 + 4 = 24
\nThe smallest digits to be place in blank space = 0
\nThen, sum = 24 + 0 = 24
\nwhich is divisible by 3.
\nThe greatest digit to be placed in blank space = 9.
\nThen, the sum = 24 + 9 = 33 which is divisible by 3.
\nHence, the required digits are 0 and 9.<\/p>\n

Question 6.
\nWrite a digit in the blank space of each of the following numbers so that the numbers formed is divisible by 11.
\n(a) 92 ___ 389
\n(b) 8 ___ 9484
\nSolution:
\n(a) 92 ___ 389
\nSum of the digits at odd places = 9 + 3 + 2 = 14
\nSum of the digits at even places = 8 + ( ) + 9 = 17
\nDifference = 17 + ( ) \u2013 14 = () + 3
\nFor the given number to be divisible by 11
\n( ) + 3 = 11
\n\u2234 ( ) = 11 \u2013 3 = 8
\nSo, the missing digit = 8
\nHence, the required number is 928389.<\/p>\n

(b) 8 ___ 9484
\nSum of the digits at odd places = 4 + 4 + ( ) = 8 + ( )
\nSum of the digits at even places = 8 + 9 + 8 = 25
\n\u2234 Difference = 25 \u2013 [8 + ( )]\n= 25 \u2013 8 \u2013 ( ) = 17 \u2013 ( )
\nFor the given number to be divisible by 11
\n17 \u2013 0 = 11
\n\u2234 17 \u2013 11 = 6
\nSo, the missing digit = 6
\nHence, the required number = 869484.<\/p>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

NCERT Solutions For Class 6 Maths Playing With Numbers Exercise 3.3 Question 1. 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