{"id":8545,"date":"2022-01-29T23:49:29","date_gmt":"2022-01-29T18:19:29","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/?p=8545"},"modified":"2022-04-25T23:41:16","modified_gmt":"2022-04-25T18:11:16","slug":"ncert-solutions-for-class-7-maths-chapter-2-fractions-and-decimals-ex-2-5","status":"publish","type":"post","link":"https:\/\/infinitylearn.com\/surge\/fractions\/ncert-solutions\/class-7\/maths\/chapter-2\/fractions-and-decimals\/ex-2-5\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5"},"content":{"rendered":"

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5<\/h2>\n

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.5<\/strong>
\nEx 2.5 Class 7 Maths Question 1.
\nWhich is greater?
\n(i) 0.5 or 0.05
\n(ii) 0.7 or 0.5
\n(iii) 7 or 0.7
\n(iv) 1.37 or 1.49
\n(v) 2.03 or 2.30
\n(vi) 0.8 or 0.88
\nSolution:
\n(i) 0.5 or 0.05
\nComparing the tenths place, we get 5 > 0
\n\u2234 0.5 > 0.05<\/p>\n

(ii) 0.7 or 0.5
\nComparing the tenths place, we get 7 > 5
\n\u2234 0.7 > 0.5<\/p>\n

(iii) 7 or 0.7
\nComparing the one\u2019s place, we get 7 > 0
\n\u2234 7 > 0.7<\/p>\n

(iv) 1.37 or 1.49
\nComparing the tenths place, we get 3 < 4
\n\u2234 1.37 < 1.49 or 1.49 > 1.37<\/p>\n

(v) 2.03 or 2.30
\nComparing the tenths place, we get 0 < 3
\n\u2234 2.03 < 2.30 or 2.30 > 2.03<\/p>\n

(vi) 0.8 or 0.88 \u21d2 0.80 or 0.88
\nSince tenths place is same.
\nComparing the hundredth place, we get 0 < 8
\n\u2234 0.80 < 0.88 or 0.88 > 0.80<\/p>\n

Ex 2.5 Class 7 Maths Question 2.
\nExpress as rupees using decimals:
\n(i) 7 paise
\n(ii) 7 rupees 7 paise
\n(iii) 77 rupees 77 paise
\n(iv) 50 paise
\n(v) 235 paise
\nSolution:
\n(i) Since 1 rupee = 100 paise and 1 paise = \\(\\frac{1}{100}\\) rupees
\n7 paise =\\(\\frac{7}{100}\\) rupees = 0.07 rupees<\/p>\n

(ii) 7 rupees 7 paise = 7 rupees + \\(\\frac{7}{100}\\) rupees
\n= 7.07 rupees<\/p>\n

(iii) 77 rupees 77 paise = 77 rupees + \\(\\frac{77}{100}\\) rupees
\n= 77.77 rupees<\/p>\n

(iv) 50 paise = \\(\\frac{50}{100}\\) rupees = 0.50 rupees<\/p>\n

(v) 235 paise = \\(\\frac{235}{100}\\) rupees = 2.35 rupees<\/p>\n

Ex 2.5 Class 7 Maths Question 3.
\n(i) Express 5 cm in metre and kilometre
\n(ii) Express 35 mm in cm, m and km.
\nSolution:
\n(i) 1 metre = 100 cm
\n1 kilometre = 1000 metre = 100 \u00d7 1000 cm
\n= 100000 cm
\n\u2234 5 cm = \\(\\frac{5}{100}\\) metre = 0.05 metre
\n5 cm = \\(\\frac{5}{100000}\\) km = 0.00005 km
\nHence, 5 cm = 0.05 m and 0.00005 km<\/p>\n

(ii) 1 cm = 10 mm and 1 km = 100000 cm
\n\u2234 35 mm = \\(\\frac{35}{10}\\) cm = 3.5 cm,
\n35 mm = \\(\\frac{35}{1000}\\) m = 0.035 m
\n35 mm = \\(\\frac{35}{1000000}\\) km = 0.000035 km
\nHence, 35 mm = 3.5 cm, 0.035 m and 0.000035 km.<\/p>\n

Ex 2.5 Class 7 Maths Question 4.
\nExpress in kg:
\n(i) 200 g
\n(ii) 3470 g
\n(iii) 4 kg 8 g
\nSolution:
\n(i) 200g = \\(\\frac{200}{1000}\\) kg [\u2235 1 kg = 1000g]\n= 0.2 kg
\n(ii) 3470 g = \\(\\frac{3470}{10000}\\) = 3.47 kg [\u2235 1 kg = 1000 g]\n(iii) 4 kg 8 g = 4 kg + \\(\\frac{8}{10000}\\)kg [\u2235 1 kg = 1000 g]\n= 4 kg + 0.008 kg = 4.008 kg<\/p>\n

Ex 2.5 Class 7 Maths Question 5.
\nWrite the following decimal numbers in the expanded form:
\n(i) 20.03
\n(ii) 2.03
\n(iii) 200.03
\n(iv) 2.034
\nSolution:
\n(i) 20.03 = 2 \u00d7 10 + 0 \u00d7 1 + 0 \u00d7 \\(\\frac{1}{10}\\) + 3 \u00d7 \\(\\frac{1}{100}\\)
\n(ii) 2.03 = 2 \u00d7 1 + 0 \u00d7 \\(\\frac{1}{10}\\) + 3 \u00d7 \\(\\frac{1}{100}\\)
\n(iii) 200.03 = 2 \u00d7 100 + 0 \u00d7 10 + 0 \u00d7 1 + 0 \u00d7 \\(\\frac{1}{10}\\) +3 \u00d7 \\(\\frac{1}{100}\\)
\n(iv) 2.034 = 2 \u00d7 1 + 0 \u00d7 \\(\\frac{1}{10}\\) + 3 \u00d7 \\(\\frac{1}{10}\\) + 4 \u00d7 \\(\\frac{1}{1000}\\)<\/p>\n

Ex 2.5 Class 7 Maths Question 6.
\nWrite the place value of 2 in the following decimal numbers:
\n(i) 2.56
\n(ii) 21.37
\n(iii) 10.25
\n(iv) 9.42
\n(v) 63.352
\nSolution:
\n(i) Place value of 2 in 2.56 = 2 \u00d7 1 = 2 i.e. ones
\n(ii) Place value of 2 in 21.37 = 2 \u00d7 10 = 20 i.e. tens
\n(iii) Place value of 2 in 10.25 = \\(\\frac{2}{10}\\) = 0.2 i.e. tenths
\n(iv) Place value of 2 in 9.42 = \\(\\frac{2}{100}\\) = 0.02 i.e. hundredths
\n(v) Place value of 2 in 63.352 = \\(\\frac{2}{1000}\\) = 0.002 i.e. thousandths.<\/p>\n

Ex 2.5 Class 7 Maths Question 7.
\nDinesh went from place A to place B and from there to place C. A is 7.5 km from B and B is 12.7 km from C. Ayub went from place A to place D and from there to place C. D is 9.3 km from A and C is 11.8 km from D. Who travelled more and by how much?
\nSolution:
\nDistance travelled by Dinesh from A to C
\n= AB + BC
\n= 7.5 km +- 12.7 km
\n= 20.2 km
\n\"NCERT
\nDistance travelled by Ayub from A to C
\n= AD + DC
\n= 9.3 km + 11.8 km = 21.1 km
\nSince 21.1 km > 20.2 km.
\nHence, Ayub travelled more distance.<\/p>\n

Ex 2.5 Class 7 Maths Question 8.
\nShyama bought 5 kg 300 g apples and 3 kg 250 g mangoes. Sarala bought 4 kg 800 g oranges and 4 kg 150 g bananas. Who bought more fruits?
\nSolution:
\nFruits bought by Shyama
\n= 5 kg 300 g apples + 3 kg 250 g mangoes
\n= 5.300 kg apples + 3.250 kg mangoes
\n= 8.550 kg of fruits
\nFruits bought by Sarala
\n= 4 kg 800 g oranges +- 4 kg 150 g bananas
\n= 4.800 kg oranges + 4.150 kg bananas
\n= 8.950 kg of fruits
\nSince 8.950 kg > 8.550 kg
\nHence, Sarala bought more fruits.<\/p>\n

Ex 2.5 Class 7 Maths Question 9.
\nHow much less is 28 km than 42.6 km?
\nSolution:
\nSince 28 km < 42.6 km
\n\"NCERT
\nHence, 28 km is less than 42.6 km by 14.6 km.<\/p>\n

\"NCERT<\/p>\n

\"NCERT<\/p>\n

\"NCERT<\/p>\n

\"NCERT<\/p>\n

\"NCERT<\/p>\n

\"NCERT<\/p>\n

\"NCERT<\/p>\n

\"NCERT<\/p>\n

\"NCERT<\/p>\n

\"NCERT<\/p>\n

\"NCERT<\/p>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 NCERT Solutions for Class 7 Maths Chapter […]<\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"NCERT Solutions","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"Get NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 on infinity learn.","custom_permalink":"fractions\/ncert-solutions\/class-7\/maths\/chapter-2\/fractions-and-decimals\/ex-2-5\/"},"categories":[93,13,19,21],"tags":[],"table_tags":[],"acf":[],"yoast_head":"\nNCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 - Infinity Learn by Sri Chaitanya<\/title>\n<meta name=\"description\" content=\"Get NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 on infinity learn.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/infinitylearn.com\/surge\/fractions\/ncert-solutions\/class-7\/maths\/chapter-2\/fractions-and-decimals\/ex-2-5\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Ex 2.5 - 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