{"id":8796,"date":"2022-01-25T11:23:07","date_gmt":"2022-01-25T05:53:07","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/?p=8796"},"modified":"2025-05-29T10:19:13","modified_gmt":"2025-05-29T04:49:13","slug":"ncert-solutions-for-class-7-maths-chapter-8-comparing-quantities-ex-8-3","status":"publish","type":"post","link":"https:\/\/infinitylearn.com\/surge\/ncert\/ncert-solutions\/maths\/ncert-solutions-for-class-7-maths-chapter-8-comparing-quantities-ex-8-3\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3"},"content":{"rendered":"

NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3<\/h2>\n

NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.3<\/strong>
\nEx 8.3 Class 7 Maths Question 1.
\nTell what is the profit or loss in the following transactions. Also find profit per cent or loss per cent in each case.
\n(a) Gardening shears bought for \u20b9 250 and sold for \u20b9 325.
\n(b) A refrigerator bought for \u20b9 12,000 and sold at \u20b9 13,500.
\n(c) A cupboard bought for \u20b9 2,500 and sold at \u20b9 3,000.
\n(d) A skirt bought for \u20b9 250 and sold at \u20b9 150.
\nSolution:
\n(a) Here, CP = \u20b9 250
\nSP = \u20b9 325
\nSince SP > CP
\n\u2234 Profit = SP \u2013 CP
\n= \u20b9 325 \u2013 \u20b9 250 = \u20b9 75
\n\"NCERT
\nHence, the required profit = \u20b9 75
\nand Profit per cent = 30%<\/p>\n

(b) Here, CP = \u20b9 12,000
\nSP = \u20b9 13,500
\nSince SP > CP
\n\u2234 Profit = SP \u2013 CP
\n= \u20b9 13,500 \u2013 \u20b9 12,000 = \u20b9 1,500
\n\"NCERT
\nHence, the required profit = \u20b9 1500 \u00d7 100
\nprofit % = \\(12 \\frac{1}{2}\\)%<\/p>\n

(c) Here, CP = \u20b9 2500
\nSP = \u20b9 3000
\nSince SP > CP
\n\u2234 Profit = SP \u2013 CP
\n= \u20b9 3000 \u2013 \u20b9 2500 = \u20b9 500
\n\"NCERT
\nHence, the required profit = \u20b9 500 and profit% = 20%<\/p>\n

(d) Here, CP = \u20b9 250
\nSP = \u20b9 150
\nHere CP > SP
\n\u2234 Loss = CP \u2013 SP
\n= \u20b9 250 \u2013 \u20b9 150 = \u20b9 100
\n\"NCERT
\nHence, the required loss = \u20b9 100 and loss% = 40%<\/p>\n

Ex 8.3 Class 7 Maths Question 2.
\nConvert each part of the ratio to Percentage:
\n(a) 3:1
\n(b) 2:3:5
\n(c) 1 : 4
\n(d) 1:2:5
\nSolution:
\n(a) 3 : 1
\nSum of the ratio parts = 3 + 1 = 4
\n\"NCERT<\/p>\n

(b) 2 : 3 : 5
\nSum of the ratio parts = 2 + 3 + 5 = 10
\n\"NCERT<\/p>\n

(c) 1 : 4
\nSum of the ratio parts =1 + 4 = 5
\n\"NCERT<\/p>\n

(d) 1 : 2 : 5
\nSum of the ratio parts = 1 + 2 + 5 = 8
\n\"NCERT<\/p>\n

Ex 8.3 Class 7 Maths Question 3.
\nThe population of a city decreased from 25,000 to 24,500. Find the Percentage decrease.
\nSolution:
\nInitial population = 25,000
\nDecreased population = 24,500
\nDecrease in population
\n= 25,000 \u2013 24,500 = 500
\nPercentage of decrease = \\(\\frac{500 \\times 100}{25000}\\) = 2%
\nHence the Percentage of decrease in population = 2%.<\/p>\n

Ex 8.3 Class 7 Maths Question 4.
\nArun bought a car for \u20b9 3,50,000. The next year, the price went upto \u20b9 3,70,000. What was the Percentage of price increase?
\nSolution:
\nOriginal price of the car = \u20b9 3,50,000
\nPrice increased next year = \u20b9 3,70,000
\nIncrease in price = \u20b9 3,70,000 \u2013 \u20b9 3,50,000
\n= \u20b9 20,000
\n\u2234 Percentage of the increase in the price
\n\"NCERT
\nHence, the Percentage of increase in price = \\(5 \\frac{5}{7} \\%\\)<\/p>\n

Ex 8.3 Class 7 Maths Question 5.
\nI buy a TV for \u20b9 10,000 and sell it at a profit of 20%. How much money do I get for it?
\nSolution:
\nHere, CP = \u20b9 10,000
\nProfit = 20%
\nSP = ?
\n\"NCERT
\nHence, the required money got by me = \u20b9 12,000.<\/p>\n

Ex 8.3 Class 7 Maths Question 6.
\nJuhi sells a washing machine for \u20b9 13,500. She loses 20% in the bargain. What was the price at which she bought it?
\nSolution:
\nSP of the washing machine = \u20b9 13,500
\nLoss = 20%
\nCP = ?
\n\"NCERT
\nHence, the cost price of the machine = \u20b9 16875.<\/p>\n

Ex 8.3 Class 7 Maths Question 7.
\n(i) Chalk contains calcium, carbon and oxygen in the ratio 10 : 3 : 12. Find the Percentage of carbon in chalk.
\n(ii) If in a stick of chalk, carbon is 3 g, what is the weight of the chalk stick?
\nSolution:
\n(i) Sum of the ratio parts = 10 + 3 + 12 = 25
\n\u2234 Percentage of carbon in chalk
\n= \\(=\\frac{3}{25} \\times 100 \\%=12 \\%\\)
\nHence, the Percentage of carbon in chalk = 12%<\/p>\n

(ii) Weight of carbon = 3 g
\n\u2234 Weight of chalk = \\(=\\frac{3}{3}\\) \u00d7 25 g = 25 g
\nHence, the weight of chalk = 25 g<\/p>\n

Ex 8.3 Class 7 Maths Question 8.
\nAmina buys a book for \u20b9 275 and sells it at a loss of 15%. How much does she sell it for?
\nSolution:
\nCP of book = \u20b9 275
\nLoss = 15%
\n\"NCERT
\nHence, the required selling price = \u20b9 233.75<\/p>\n

Ex 8.3 Class 7 Maths Question 9.
\nFind the amount to be paid at the end of 3 years in each case.
\n(a) Principal = \u20b9 1200 at 12% p.a.
\n(b) Principal = \u20b9 7500 at 5% p.a.
\nSolution:
\n(a) Given: Principal = \u20b9 1200
\nRate of interest = 12% p.a., T = 3 years
\n\u2234 Interest = \\(\\frac{\\mathrm{P} \\times \\mathrm{R} \\times \\mathrm{T}}{100}=\\frac{1200 \\times 12 \\times 3}{100}\\)
\nAmount = Principal + Interest
\n= \u20b9 1200 + \u20b9 432 = \u20b9 1632
\nHence, the required amount = \u20b9 1632<\/p>\n

(b) Given: Principal = \u20b9 7500
\nRate = 5% p.a.
\nTime = 3 years
\n\u2234 Interest = \\(\\frac{\\mathrm{P} \\times \\mathrm{R} \\times \\mathrm{T}}{100}=\\frac{7500 \\times 5 \\times 3}{100}\\)
\n= \u20b91125
\nAmount = Principal + Interest
\n= \u20b9 7500 + 11125 = \u20b9 8625
\nHence, the required amount = \u20b9 8625.<\/p>\n

Ex 8.3 Class 7 Maths Question 10.
\nWhat rate gives \u20b9 280 as interest on a sum of \u20b9 56,000 in 2 years?
\nSolution:
\nGiven: Principal = \u20b9 56,000
\nInterest = \u20b9280
\nTime = 2 years
\nRate = ?
\n\"NCERT
\nHence, the required rate = 0.25%<\/p>\n

Ex 8.3 Class 7 Maths Question 11.
\nIf Meena gives an interest of \u20b9 45 for one year at 9% rate p.a. What is the sum she has borrowed?
\nSolution:
\nGiven: Interest = \u20b9 45
\nTime = 1 year
\nRate = 9% p.a.
\n\"NCERT
\nHence, the required sum = \u20b9 500.<\/p>\n

 <\/p>\n","protected":false},"excerpt":{"rendered":"

NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 NCERT Solutions for Class 7 Maths Chapter 8 […]<\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"get NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 at infinity learn","custom_permalink":"ncert\/ncert-solutions\/maths\/ncert-solutions-for-class-7-maths-chapter-8-comparing-quantities-ex-8-3\/"},"categories":[13,19],"tags":[],"table_tags":[],"acf":[],"yoast_head":"\nNCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 - Infinity Learn by Sri Chaitanya<\/title>\n<meta name=\"description\" content=\"get NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 at infinity learn\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/infinitylearn.com\/surge\/ncert\/ncert-solutions\/maths\/ncert-solutions-for-class-7-maths-chapter-8-comparing-quantities-ex-8-3\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"NCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Ex 8.3 - 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