{"id":8919,"date":"2021-12-29T17:26:26","date_gmt":"2021-12-29T11:56:26","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/?p=8919"},"modified":"2025-07-24T18:11:58","modified_gmt":"2025-07-24T12:41:58","slug":"ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3","status":"publish","type":"post","link":"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/","title":{"rendered":"NCERT Solutions &#8211; Class 7 Maths Chapter 11 Perimeter and Area Ex 11.3"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_37 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" style=\"display: none;\"><label for=\"item\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input type=\"checkbox\" id=\"item\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1' style='display:block'><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#NCERT_Solutions_Class_7_Chapter_11_-_Perimeter_and_Area_Ex_113\" title=\"NCERT Solutions Class 7 Chapter 11 &#8211; Perimeter and Area Ex 11.3\">NCERT Solutions Class 7 Chapter 11 &#8211; Perimeter and Area Ex 11.3<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#NCERT_Solution_for_Class_7_Maths_Chapter_11_Exercise_113_Questions_Answers\" title=\"NCERT Solution for Class 7 Maths Chapter 11 Exercise 11.3 Questions Answers\">NCERT Solution for Class 7 Maths Chapter 11 Exercise 11.3 Questions Answers<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_1\" title=\"Ex 11.3 Class 7 Maths Question 1.\">Ex 11.3 Class 7 Maths Question 1.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_2\" title=\"Ex 11.3 Class 7 Maths Question 2.\">Ex 11.3 Class 7 Maths Question 2.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_3\" title=\"Ex 11.3 Class 7 Maths Question 3.\">Ex 11.3 Class 7 Maths Question 3.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_4\" title=\"Ex 11.3 Class 7 Maths Question 4.\">Ex 11.3 Class 7 Maths Question 4.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_5\" title=\"Ex 11.3 Class 7 Maths Question 5.\">Ex 11.3 Class 7 Maths Question 5.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_6\" title=\"Ex 11.3 Class 7 Maths Question 6.\">Ex 11.3 Class 7 Maths Question 6.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_7\" title=\"Ex 11.3 Class 7 Maths Question 7.\">Ex 11.3 Class 7 Maths Question 7.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_8\" title=\"Ex 11.3 Class 7 Maths Question 8.\">Ex 11.3 Class 7 Maths Question 8.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_9\" title=\"Ex 11.3 Class 7 Maths Question 9.\">Ex 11.3 Class 7 Maths Question 9.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_10\" title=\"Ex 11.3 Class 7 Maths Question 10.\">Ex 11.3 Class 7 Maths Question 10.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_11\" title=\"Ex 11.3 Class 7 Maths Question 11.\">Ex 11.3 Class 7 Maths Question 11.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_12\" title=\"Ex 11.3 Class 7 Maths Question 12.\">Ex 11.3 Class 7 Maths Question 12.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_13\" title=\"Ex 11.3 Class 7 Maths Question 13.\">Ex 11.3 Class 7 Maths Question 13.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-16\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_14\" title=\"Ex 11.3 Class 7 Maths Question 14.\">Ex 11.3 Class 7 Maths Question 14.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-17\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_15\" title=\"Ex 11.3 Class 7 Maths Question 15.\">Ex 11.3 Class 7 Maths Question 15.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-18\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_16\" title=\"Ex 11.3 Class 7 Maths Question 16.\">Ex 11.3 Class 7 Maths Question 16.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-19\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Ex_113_Class_7_Maths_Question_17\" title=\"Ex 11.3 Class 7 Maths Question 17.\">Ex 11.3 Class 7 Maths Question 17.<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-20\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#NCERT_Solution_for_Class_7_Maths_Chapter_11_Exercise_113_PDF_Download\" title=\"NCERT Solution for Class 7 Maths Chapter 11 Exercise 11.3 PDF Download\">NCERT Solution for Class 7 Maths Chapter 11 Exercise 11.3 PDF Download<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-21\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#FAQs_on_NCERT_Solution_for_Class_7_Maths_Chapter_11_Exercise_113\" title=\"FAQs on NCERT Solution for Class 7 Maths Chapter 11 Exercise 11.3\">FAQs on NCERT Solution for Class 7 Maths Chapter 11 Exercise 11.3<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-22\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#Where_to_download_NCERT_solution_for_Class_7_Maths_Chapter_11_Exercise_113\" title=\"Where to download NCERT solution for Class 7 Maths Chapter 11 Exercise 11.3?\">Where to download NCERT solution for Class 7 Maths Chapter 11 Exercise 11.3?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-23\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#What_is_the_perimeter_and_area_of_a_parallelogram_in_Class_7\" title=\"What is the perimeter and area of a parallelogram in Class 7?\">What is the perimeter and area of a parallelogram in Class 7?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-24\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#How_do_you_find_the_perimeter_in_Class_7\" title=\"How do you find the perimeter in Class 7?\">How do you find the perimeter in Class 7?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-25\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#What_is_the_name_of_Chapter_11_of_Class_7_Maths\" title=\"What is the name of Chapter 11 of Class 7 Maths?\">What is the name of Chapter 11 of Class 7 Maths?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-26\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#What_is_the_formula_for_a_parallelogram\" title=\"What is the formula for a parallelogram?\">What is the formula for a parallelogram?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-27\" href=\"https:\/\/infinitylearn.com\/surge\/study-materials\/ncert-solutions-class-7-maths-chapter-11-perimeter-and-area-ex-11-3\/#What_is_the_area_of_a_parallelogram_in_Class_7\" title=\"What is the area of a parallelogram in Class 7?\">What is the area of a parallelogram in Class 7?<\/a><\/li><\/ul><\/li><\/ul><\/nav><\/div>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_Class_7_Chapter_11_-_Perimeter_and_Area_Ex_113\"><\/span>NCERT Solutions Class 7 Chapter 11 &#8211; Perimeter and Area Ex 11.3<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>The <strong>NCERT Solution for Class 7 Maths Chapter 11 Exercise 11.3<\/strong> is an essential resource tailored to help students grasp the concepts covered in this segment of the curriculum. These <strong>NCERT solutions<\/strong> are meticulously crafted in alignment with the <a href=\"https:\/\/infinitylearn.com\/cbse-board\/cbse-syllabus\"><strong>CBSE syllabus<\/strong><\/a>, ensuring that every problem is approached with methods that both simplify learning and enhance comprehension. This exercise gets into important mathematical principles that are fundamental at this stage of education, providing detailed step-by-step solutions that aid students in effectively navigating through their <strong>NCERT textbook<\/strong>. By utilizing these <strong>NCERT solutions for class 7<\/strong>, students can confidently tackle the challenges presented in the exercise, reinforcing their mathematical skills and preparing them for more advanced topics. Get <strong>NCERT Solutions for Class 7 Maths<\/strong> Chapter 11 Perimeter and Area on Infinity Learn for free.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solution_for_Class_7_Maths_Chapter_11_Exercise_113_Questions_Answers\"><\/span>NCERT Solution for Class 7 Maths Chapter 11 Exercise 11.3 Questions Answers<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>Here are all Class 7 maths chapter 11 exercise 11.3 questions with simple and easy solutions<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Ex_113_Class_7_Maths_Question_1\"><\/span>Ex 11.3 Class 7 Maths Question 1.<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Find the circumference of the circles with the following radius. (Take \u03c0 =\\(\\frac{22}{7}\\))<br \/>\n(a) 14 cm<br \/>\n(b) 28 mm<br \/>\n(c) 21 cm<br \/>\nSolution:<br \/>\n(a) Given: Radius (r) = 14 cm<br \/>\n\u2234 Circumference = 2\u03c0r = 2 \u00d7 \\(\\frac{22}{7}\\) \u00d7 14<br \/>\n= 88 cm<br \/>\n(b) Given: Radius (r) = 28 mm<br \/>\n\u2234 Circumference = 2\u03c0r = 2 \u00d7 \\(\\frac{22}{7}\\) \u00d7 28<br \/>\n= 176 mm<br \/>\n(c) Given: Radius (r) = 21 cm<br \/>\n\u2234 Circumference = 2\u03c0r = 2 \u00d7 \\(\\frac{22}{7}\\) \u00d7 21<br \/>\n= 132 cm<\/p>\n<h3>Ex 11.3 Class 7 Maths Question 2.<\/h3>\n<p>Find the area of the following circles, given that (Take \u03c0 =\\(\\frac{22}{7}\\))<br \/>\n(a) radius = 14 mm<br \/>\n(b) diameter = 49 m<br \/>\n(c) radius = 5 cm<br \/>\nSolution:<br \/>\n(a) Here, r = 14 mm<br \/>\n\u2234 Area of the circle = \u03c0r<sup>2<\/sup><br \/>\n= \u03c0 \u00d7 14 \u00d7 14 = \\(\\frac{22}{7}\\) \u00d7 14 \u00d7 14<br \/>\n(b) Here, diameter = 49 m 49<br \/>\n<img loading=\"lazy\" class=\"size-full wp-image-74165 alignleft\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.3-1.png\" alt=\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.3 1\" width=\"322\" height=\"149\" \/><\/p>\n<p>(c) Here, radius = 5 cm<br \/>\n<img loading=\"lazy\" class=\"size-full wp-image-74179 alignleft\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.3-2.png\" alt=\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.3 2\" width=\"289\" height=\"86\" \/><\/p>\n<h3>Ex 11.3 Class 7 Maths Question 3.<\/h3>\n<p>If the circumference of a circular sheet is 154 m, find its radius. Also find the area of the sheet. (Take \u03c0 =\\(\\frac{22}{7}\\))<br \/>\nSolution:<br \/>\nGiven: Circumference = 154 m<br \/>\n\u2234 2\u03c0r = 154<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-74168\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.3-3.png\" alt=\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.3 3\" width=\"333\" height=\"184\" \/><\/p>\n<h3>Ex 11.3 Class 7 Maths Question 4.<\/h3>\n<p>A gardener wants to fence a circular garden of diameter 21 m. Find the length of the rope he needs to purchase, if he makes 2 rounds offence. Also find the cost of the rope, if it costs \u20b9 4 per metre. (Take \u03c0 =\\(\\frac{22}{7}\\))<br \/>\n<img loading=\"lazy\" class=\"size-full wp-image-74169 aligncenter\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.3-4.png\" alt=\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.3 4\" width=\"118\" height=\"109\" \/><br \/>\nSolution:<br \/>\nDiameter of the circular garden = 21 m<br \/>\n\u2234 Radius = \\(\\frac{21}{2}\\) m<br \/>\n\u2234 Circumference = 2\u03c0r = \\(2 \\times \\frac{22}{7} \\times \\frac{21}{2}\\)<br \/>\n= 66 m<br \/>\nLength of rope needed for 2 rounds<br \/>\n= 2 \u00d7 66 m = 132 m<br \/>\nCost of the rope = \u20b94 \u00d7 132 = \u20b9 528<\/p>\n<h3>Ex 11.3 Class 7 Maths Question 5.<\/h3>\n<p>From a circular sheet of radius 4 cm, a circle of radius 3 cm is removed. Find the area of the remaining sheet. (Take \u03c0 = 3.14)<br \/>\nSolution:<br \/>\nRadius of the circular sheet = 4 cm<br \/>\n\u2234 Area = \u03c0r<sup>2<\/sup> = \u03c0 \u00d7 4 \u00d7 4 = 16\u03c0 cm<sup>2<\/sup><br \/>\nRadius of the circle to be removed = 3 cm<br \/>\n\u2234 Area of sheet removed = \u03c0r<sup>2<\/sup> = 9\u03c0 cm<sup>2<\/sup><br \/>\nArea of the remaining sheet<br \/>\n= (16\u03c0 \u2013 9\u03c0) cm2 = 7\u03c0 cm<sup>2<\/sup><br \/>\n= 7 \u00d7 3.14 cm<sup>2<\/sup> = 21.98 cm<sup>2<\/sup><br \/>\nHence, the required area = 21.98 cm<sup>2<\/sup>.<\/p>\n<h3>Ex 11.3 Class 7 Maths Question 6.<\/h3>\n<p>Saima wants to put a lace on the edge of a circular table cover of diameter 1.5 m. Find the length of the lace required and also find its cost if one metre of the lace costs \u20b9 15. (Take \u03c0 = 3.14)<br \/>\nSolution:<br \/>\nDiameter of the table cover = 1.5 m<br \/>\n\u2234 Radius = \\(\\frac{1.5}{2}\\) = 0.75 m<br \/>\n\u2234 Length of the lace = 2\u03c0r = 2 \u00d7 3.14 \u00d7 0.75<br \/>\n= 4.710 m<br \/>\nCost of the lace = \u20b9 15 \u00d7 4.710 = \u20b9 70.65<\/p>\n<h3>Ex 11.3 Class 7 Maths Question 7.<\/h3>\n<p>Find the perimeter of the given figure, which is a semicircle including its diameter.<br \/>\n<img loading=\"lazy\" class=\"size-full wp-image-74170 aligncenter\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.3-5.png\" alt=\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.3 5\" width=\"159\" height=\"97\" \/><br \/>\nSolution:<br \/>\nGiven: Diameter = 10 cm<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-74172\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.3-6.png\" alt=\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.3 6\" width=\"340\" height=\"336\" \/><br \/>\nHence, the required perimeter<br \/>\n= 25.7 cm. (approx.)<\/p>\n<h3>Ex 11.3 Class 7 Maths Question 8.<\/h3>\n<p>Find the cost of polishing a circular table-top of diameter 1.6 m, if the rate of polishing is \u20b9 15 m<sup>2<\/sup>. (Take \u03c0 = 3.14)<br \/>\nSolution:<br \/>\nGiven:<br \/>\nDiameter = 1.6 m<br \/>\n\u2234 Radius = \\(\\frac{1.6}{2}\\) = 0.8 m<br \/>\nArea of the table-top = \u03c0r<sup>2<\/sup><br \/>\n= 3.14 \u00d7 0.8 \u00d7 0.8 m<sup>2<\/sup><br \/>\n= 2.0096 m<sup>2<\/sup><br \/>\n\u2234 Cost of polishing = \u20b9 15 \u00d7 2.0096<br \/>\n= \u20b9 30.14 (approx.)<\/p>\n<h3>Ex 11.3 Class 7 Maths Question 9.<\/h3>\n<p>Shazli took a wire of length 44 cm and bent it into the shape of a circle. Find the radius of that circle. Also find its area. If the same wire is bent into the shape of a square, what will be the length of each of its sides? Which figure encloses more area, the circle or the square? (Take \u03c0 =\\(\\frac{22}{7}\\))<br \/>\nSolution:<br \/>\nLength of the wire to be bent into a circle = 44 cm<br \/>\n2\u03c0r = 44<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-74173\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.3-7.png\" alt=\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.3 7\" width=\"281\" height=\"184\" \/><br \/>\nNow, the length of the wire is bent into a square.<br \/>\nHere perimeter of square<br \/>\n= Circumference of line k<br \/>\nLength of each side of the square<br \/>\n\\(=\\frac{\\text { Perimeter }}{4}=\\frac{44}{4}=11 \\mathrm{cm}\\)<br \/>\nArea of the square = (Side)<sup>2<\/sup> = (11)<sup>2<\/sup> = 121 cm<sup>2<\/sup><br \/>\nSince, 154 cm<sup>2<\/sup> &gt;121 cm<sup>2<\/sup><br \/>\nThus, the circle encloses more area.<\/p>\n<h3>Ex 11.3 Class 7 Maths Question 10.<\/h3>\n<p>From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1 cm are removed, (as shown in the given figure below). Find the area of the remaining sheet. (Take \u03c0 = \\(\\frac{22}{7}\\))<br \/>\n<img loading=\"lazy\" class=\"size-full wp-image-74174 aligncenter\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.3-8.png\" alt=\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.3 8\" width=\"122\" height=\"123\" \/><br \/>\nSolution:<br \/>\nRadius of the circular sheet = 14 cm<br \/>\n\u2234 Area = \u03c0r<sup>2<\/sup> = \\(\\frac{22}{7}\\) \u00d7 14 \u00d7 14 cm<sup>2<\/sup><br \/>\n= 616 cm<sup>2<\/sup><br \/>\nArea of 2 small circles = 2 \u00d7 \u03c0r<sup>2<\/sup><br \/>\n= 2 \u00d7 \\(\\frac{22}{7}\\) \u00d7 3.5 \u00d7 3.5 cm<sup>2<\/sup><br \/>\n= 77.0 cm<sup>2<\/sup><br \/>\nArea of the rectangle = l \u00d7 b<br \/>\n= 3 \u00d7 1 cm<sup>2<\/sup> = 3 cm<sup>2<\/sup><br \/>\nArea of the remaining sheet after removing the 2 circles and 1 rectangle<br \/>\n= 616 cm<sup>2<\/sup> \u2013 (77 + 3) cm<sup>2<\/sup><br \/>\n= 616 cm<sup>2<\/sup> \u2013 80 cm<sup>2<\/sup> = 536 cm<sup>2<\/sup><\/p>\n<h3>Ex 11.3 Class 7 Maths Question 11.<\/h3>\n<p>A circle of radius 2 cm is cut out from a square piece of an aluminium sheet of side 6 cm. What is the area of the left over aluminium sheet? (Take \u03c0 = 3.14)<br \/>\nSolution:<br \/>\nSide os the square sheet = 6 m<br \/>\n\u2234 Area of the sheet = (Side)<sup>2<\/sup> = (6)<sup>2<\/sup> = 36 cm<sup>2<\/sup><br \/>\nRadius of the circle = 2 cm<br \/>\n\u2234 Area of the circle to be cut out = \u03c0r<sup>2<br \/>\n<\/sup>= \\(=\\frac{22}{7} \\times 2 \\times 2=\\frac{88}{7} \\mathrm{cm}^{2}\\)<br \/>\nArea of the left over sheet<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-74175\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.3-9.png\" alt=\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.3 9\" width=\"223\" height=\"120\" \/><\/p>\n<h3>Ex 11.3 Class 7 Maths Question 12.<\/h3>\n<p>The circumference of a circle is 31.4 cm. Find the radius and the area of the circle. (Take \u03c0 = 3.14)<br \/>\nSolution:<br \/>\nCircumference of the circle = 31.4 cm<br \/>\n2\u03c0r = 31.4<br \/>\n\u2234 \\(r=\\frac{31.4}{2 \\times 3.14}\\) = 5cm<br \/>\nArea of the circle = 7\u03c0r<sup>2<\/sup> = 3.14 \u00d7 5 \u00d7 5 = 78.5 cm<sup>2<\/sup><br \/>\nHence, the required radius = 5 cm and area = 78.5 cm<sup>2<\/sup>.<\/p>\n<h3>Ex 11.3 Class 7 Maths Question 13.<\/h3>\n<p>A circular flower bed is surrounded by a path 4 m wide. The diameter of the flower bed is 66 m. What is the area of this path? (Take \u03c0 = 3.14)<br \/>\n<img loading=\"lazy\" class=\"size-full wp-image-74176 aligncenter\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.3-10.png\" alt=\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.3 10\" width=\"163\" height=\"161\" \/><br \/>\nSolution:<br \/>\nDiameter of the flower bed = 66 m .<br \/>\n\u2234 Radius = \\(\\frac{66}{2}\\) = 33 m<br \/>\nLet r<sub>1<\/sub> = 33 m<br \/>\nWidth of the path = 4 m<br \/>\nRadius of the flower bed included path<br \/>\n= 33 m + 4 m = 37m<br \/>\nLet r<sub>2<\/sub> = 37m<br \/>\nArea of the circular path = \\(\\pi\\left(r_{2}^{2}-r_{1}^{2}\\right)\\)<br \/>\n= 3.14 (37<sup>2<\/sup>\u2013 33<sup>2<\/sup>)<br \/>\n= 3.14 \u00d7 (37 + 33) (37 \u2013 33) [Y a<sup>2<\/sup> \u2013 b<sup>2<\/sup> = (a + b)(a-b)]\n= 3.14 \u00d7 70 \u00d7 4 = 879.20 m<sup>2<\/sup><br \/>\nHence, the required area = 879.20 m<sup>2<\/sup><\/p>\n<h3><span class=\"ez-toc-section\" id=\"Ex_113_Class_7_Maths_Question_14\"><\/span>Ex 11.3 Class 7 Maths Question 14.<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>A circular flower garden has an area of 314 m<sup>2<\/sup>. A sprinkler at the centre of the garden can cover an area that has a radius of 12 m. Will the sprinkler can water the entire garden?<br \/>\n[Take \u03c0 = 3.14]\nSolution:<br \/>\nArea of the flower garden = 314 m<sup>2<\/sup><br \/>\nRadius of the circular portion covered by the sprinkler = 12 m<br \/>\n\u2234 Area = 7\u03c0r<sup>2<\/sup> = 3.14 \u00d7 12 \u00d7 12<br \/>\n= 3.14 \u00d7 144 m<sup>2<\/sup> = 452.16 m<sup>2<\/sup><br \/>\nSince 452.16 m<sup>2<\/sup> &gt; 314 m<sup>2<\/sup><br \/>\nYes, the sprinkler will water the entire garden.<\/p>\n<h3>Ex 11.3 Class 7 Maths Question 15.<\/h3>\n<p>Find the circumference of the inner and the outer circles, shown in the given figure. (Take \u03c0 = 3.14)<br \/>\n<img loading=\"lazy\" class=\"size-full wp-image-74183 aligncenter\" src=\"https:\/\/infinitylearn.com\/surge\/wp-content\/uploads\/2021\/12\/NCERT-Solutions-for-Class-7-Maths-Chapter-11-Perimeter-and-Area-Ex-11.3-11.png\" alt=\"NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex 11.3 11\" width=\"153\" height=\"150\" \/><br \/>\nSolution:<br \/>\nRadius of the outer circle = 19 m<br \/>\n\u2234 Circumference of the outer circle = 2\u03c0r<br \/>\n= 2 \u00d7 3.14 \u00d7 19 = 3.14 \u00d7 38 m<br \/>\n= 119.32 m<br \/>\nRadius of the inner circle<br \/>\n= 19m \u2013 10m = 9m<br \/>\n\u2234 Circumference = 2\u03c0r = 2 \u00d7 3.14 \u00d7 9<br \/>\n= 56.52 m<br \/>\nHere the required circumferences are 56.52 m and 119.32 m.<\/p>\n<h3>Ex 11.3 Class 7 Maths Question 16.<\/h3>\n<p>How many times a wheel of radius 28 cm must rotate to go 352 m? (Take \u03c0 = \\(\\frac{22}{7}\\))<br \/>\nSolution:<br \/>\nRadius of the wheel = 28 cm<br \/>\n\u2234 Circumference = 2\u03c0r = 2 \u00d7 \\(\\frac{22}{7}\\) \u00d7 28 = 176 cm<br \/>\nNumber of rotations made by the wheel in going 352 m or 35200 cm<br \/>\n\\(=\\frac{35200}{176}=200\\)<br \/>\nHence, the required number of rotation = 200.<\/p>\n<h3>Ex 11.3 Class 7 Maths Question 17.<\/h3>\n<p>The minute hand of a circular clock is 15 cm long. How far does the tip of the minute hand move in 1 hour? (Take \u03c0 = 3.14)<br \/>\nSolution:<br \/>\nLength of minute hand = 15 cm<br \/>\n\u2234 Radius = 15 cm<br \/>\nCircumference = 2\u03c0r<br \/>\n= 2 \u00d7 3.14 \u00d7 15 cm = 94.2 cm<br \/>\nSince the minute hand covers the distance in 1 hour equal to the circumference of the circle. Here the required distance covered by the minute hand = 94.2 cm.<\/p>\n<p><strong>Also Check:<\/strong><\/p>\n<ul>\n<li><strong>Class 7 Maths NCERT Solutions Exercise 11.1<\/strong><\/li>\n<li><strong>Class 7 Maths NCERT Solutions Exercise 11.2<\/strong><\/li>\n<li><strong>Class 7 Maths NCERT Solutions Exercise 11.3<\/strong><\/li>\n<li><strong>Class 7 Maths NCERT Solutions Exercise 11.4<\/strong><\/li>\n<\/ul>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solution_for_Class_7_Maths_Chapter_11_Exercise_113_PDF_Download\"><\/span>NCERT Solution for Class 7 Maths Chapter 11 Exercise 11.3 PDF Download<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>You can easily get the NCERT Solution for Class 7 Maths Chapter 11 Exercise 11.3 in PDF format. It&#8217;s great because you can download it and use it whenever you want, which makes studying and reviewing easier. This NCERT solutions PDF has detailed explanations and step-by-step solutions to help you understand better and prepare for exams. It&#8217;s a valuable resource that can boost your math skills.<\/p>\n<p><button><strong>NCERT Solutions for Class 7 Maths Chapter-wise PDF<\/strong><\/button><\/p>\n<ul>\n<li><strong>Chapter 1 Integers<\/strong><\/li>\n<li><strong>Chapter 2 Fractions and Decimals<\/strong><\/li>\n<li><strong>Chapter 3 Data Handling<\/strong><\/li>\n<li><strong>Chapter 4 Simple Equations<\/strong><\/li>\n<li><strong>Chapter 5 Lines and Angles<\/strong><\/li>\n<li><strong>Chapter 6 The Triangles and Its Properties<\/strong><\/li>\n<li><strong>Chapter 7 Congruence of Triangles<\/strong><\/li>\n<li><strong>Chapter 8 Comparing Quantities<\/strong><\/li>\n<li><strong>Chapter 9 Rational Numbers<\/strong><\/li>\n<li><strong>Chapter 10 Practical Geometry<\/strong><\/li>\n<li><strong>Chapter 11 Perimeter and Area<\/strong><\/li>\n<li><strong>Chapter 12 Algebraic Expressions<\/strong><\/li>\n<li><strong>Chapter 13 Exponents and Powers<\/strong><\/li>\n<li><strong>Chapter 14 Symmetry<\/strong><\/li>\n<li><strong>Chapter 15 Visualizing Solid Shapes<\/strong><\/li>\n<\/ul>\n<h2><span class=\"ez-toc-section\" id=\"FAQs_on_NCERT_Solution_for_Class_7_Maths_Chapter_11_Exercise_113\"><\/span>FAQs on NCERT Solution for Class 7 Maths Chapter 11 Exercise 11.3<span class=\"ez-toc-section-end\"><\/span><\/h2>\n\t\t<section class=\"sc_fs_faq sc_card \">\n\t\t\t<div>\n\t\t\t\t<h3><span class=\"ez-toc-section\" id=\"Where_to_download_NCERT_solution_for_Class_7_Maths_Chapter_11_Exercise_113\"><\/span>Where to download NCERT solution for Class 7 Maths Chapter 11 Exercise 11.3?<span class=\"ez-toc-section-end\"><\/span><\/h3>\t\t\t\t<div>\n\t\t\t\t\t\t\t\t\t\t<p>\n\t\t\t\t\t\tWhere to download NCERT solution for Class 7 Maths Chapter 11 Exercise 11.3?\t\t\t\t\t<\/p>\n\t\t\t\t<\/div>\n\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t<section class=\"sc_fs_faq sc_card \">\n\t\t\t<div>\n\t\t\t\t<h3><span class=\"ez-toc-section\" id=\"What_is_the_perimeter_and_area_of_a_parallelogram_in_Class_7\"><\/span>What is the perimeter and area of a parallelogram in Class 7?<span class=\"ez-toc-section-end\"><\/span><\/h3>\t\t\t\t<div>\n\t\t\t\t\t\t\t\t\t\t<p>\n\t\t\t\t\t\tWhat is the perimeter and area of a parallelogram in Class 7?\t\t\t\t\t<\/p>\n\t\t\t\t<\/div>\n\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t<section class=\"sc_fs_faq sc_card \">\n\t\t\t<div>\n\t\t\t\t<h3><span class=\"ez-toc-section\" id=\"How_do_you_find_the_perimeter_in_Class_7\"><\/span>How do you find the perimeter in Class 7?<span class=\"ez-toc-section-end\"><\/span><\/h3>\t\t\t\t<div>\n\t\t\t\t\t\t\t\t\t\t<p>\n\t\t\t\t\t\tTo find the perimeter in Class 7, add up the lengths of all the sides of the given shape or figure. For example, in a rectangle, you add the lengths of all four sides.\t\t\t\t\t<\/p>\n\t\t\t\t<\/div>\n\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t<section class=\"sc_fs_faq sc_card \">\n\t\t\t<div>\n\t\t\t\t<h3><span class=\"ez-toc-section\" id=\"What_is_the_name_of_Chapter_11_of_Class_7_Maths\"><\/span>What is the name of Chapter 11 of Class 7 Maths?<span class=\"ez-toc-section-end\"><\/span><\/h3>\t\t\t\t<div>\n\t\t\t\t\t\t\t\t\t\t<p>\n\t\t\t\t\t\tChapter 11 of Class 7 Maths is titled Perimeter and Area, focusing on concepts related to calculating the perimeter and area of various geometric shapes. \t\t\t\t\t<\/p>\n\t\t\t\t<\/div>\n\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t<section class=\"sc_fs_faq sc_card \">\n\t\t\t<div>\n\t\t\t\t<h3><span class=\"ez-toc-section\" id=\"What_is_the_formula_for_a_parallelogram\"><\/span>What is the formula for a parallelogram?<span class=\"ez-toc-section-end\"><\/span><\/h3>\t\t\t\t<div>\n\t\t\t\t\t\t\t\t\t\t<p>\n\t\t\t\t\t\tThe formula for the area of a parallelogram is base multiplied by height, while the formula for the perimeter involves adding the lengths of all four sides of the parallelogram.\t\t\t\t\t<\/p>\n\t\t\t\t<\/div>\n\t\t\t<\/div>\n\t\t<\/section>\n\t\t\t\t<section class=\"sc_fs_faq sc_card \">\n\t\t\t<div>\n\t\t\t\t<h3><span class=\"ez-toc-section\" id=\"What_is_the_area_of_a_parallelogram_in_Class_7\"><\/span>What is the area of a parallelogram in Class 7?<span class=\"ez-toc-section-end\"><\/span><\/h3>\t\t\t\t<div>\n\t\t\t\t\t\t\t\t\t\t<p>\n\t\t\t\t\t\tIn Class 7, the area of a parallelogram is calculated by multiplying the base and the height of the parallelogram, providing the measure of space enclosed within its boundaries.\t\t\t\t\t<\/p>\n\t\t\t\t<\/div>\n\t\t\t<\/div>\n\t\t<\/section>\n\t\t\n<script type=\"application\/ld+json\">\n\t{\n\t\t\"@context\": \"https:\/\/schema.org\",\n\t\t\"@type\": \"FAQPage\",\n\t\t\"mainEntity\": [\n\t\t\t\t\t{\n\t\t\t\t\"@type\": \"Question\",\n\t\t\t\t\"name\": \"Where to download NCERT solution for Class 7 Maths Chapter 11 Exercise 11.3?\",\n\t\t\t\t\"acceptedAnswer\": {\n\t\t\t\t\t\"@type\": \"Answer\",\n\t\t\t\t\t\"text\": \"Where to download NCERT solution for Class 7 Maths Chapter 11 Exercise 11.3?\"\n\t\t\t\t\t\t\t\t\t}\n\t\t\t}\n\t\t\t,\t\t\t\t{\n\t\t\t\t\"@type\": \"Question\",\n\t\t\t\t\"name\": \"What is the perimeter and area of a parallelogram in Class 7?\",\n\t\t\t\t\"acceptedAnswer\": {\n\t\t\t\t\t\"@type\": \"Answer\",\n\t\t\t\t\t\"text\": \"What is the perimeter and area of a parallelogram in Class 7?\"\n\t\t\t\t\t\t\t\t\t}\n\t\t\t}\n\t\t\t,\t\t\t\t{\n\t\t\t\t\"@type\": \"Question\",\n\t\t\t\t\"name\": \"How do you find the perimeter in Class 7?\",\n\t\t\t\t\"acceptedAnswer\": {\n\t\t\t\t\t\"@type\": \"Answer\",\n\t\t\t\t\t\"text\": \"To find the perimeter in Class 7, add up the lengths of all the sides of the given shape or figure. For example, in a rectangle, you add the lengths of all four sides.\"\n\t\t\t\t\t\t\t\t\t}\n\t\t\t}\n\t\t\t,\t\t\t\t{\n\t\t\t\t\"@type\": \"Question\",\n\t\t\t\t\"name\": \"What is the name of Chapter 11 of Class 7 Maths?\",\n\t\t\t\t\"acceptedAnswer\": {\n\t\t\t\t\t\"@type\": \"Answer\",\n\t\t\t\t\t\"text\": \"Chapter 11 of Class 7 Maths is titled Perimeter and Area, focusing on concepts related to calculating the perimeter and area of various geometric shapes.\"\n\t\t\t\t\t\t\t\t\t}\n\t\t\t}\n\t\t\t,\t\t\t\t{\n\t\t\t\t\"@type\": \"Question\",\n\t\t\t\t\"name\": \"What is the formula for a parallelogram?\",\n\t\t\t\t\"acceptedAnswer\": {\n\t\t\t\t\t\"@type\": \"Answer\",\n\t\t\t\t\t\"text\": \"The formula for the area of a parallelogram is base multiplied by height, while the formula for the perimeter involves adding the lengths of all four sides of the parallelogram.\"\n\t\t\t\t\t\t\t\t\t}\n\t\t\t}\n\t\t\t,\t\t\t\t{\n\t\t\t\t\"@type\": \"Question\",\n\t\t\t\t\"name\": \"What is the area of a parallelogram in Class 7?\",\n\t\t\t\t\"acceptedAnswer\": {\n\t\t\t\t\t\"@type\": \"Answer\",\n\t\t\t\t\t\"text\": \"In Class 7, the area of a parallelogram is calculated by multiplying the base and the height of the parallelogram, providing the measure of space enclosed within its boundaries.\"\n\t\t\t\t\t\t\t\t\t}\n\t\t\t}\n\t\t\t\t\t\t]\n\t}\n<\/script>\n\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions Class 7 Chapter 11 &#8211; Perimeter and Area Ex 11.3 The NCERT Solution for Class 7 Maths Chapter [&hellip;]<\/p>\n","protected":false},"author":31,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"NCERT Solution for Class 7 Maths Chapter 11 Exercise 11.3","_yoast_wpseo_title":"NCERT Solutions - 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