{"id":89846,"date":"2022-02-14T19:56:35","date_gmt":"2022-02-14T14:26:35","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/?p=89846"},"modified":"2025-02-05T11:20:28","modified_gmt":"2025-02-05T05:50:28","slug":"prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate","status":"publish","type":"post","link":"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/","title":{"rendered":"Prepare M\/50 Solution of Oxalic Acid. With its help, Determine 50 the Molarity and Strength of the Given Solution of Potassium Permanganate"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_37 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" style=\"display: none;\"><label for=\"item\" aria-label=\"Table of Content\"><span style=\"display: flex;align-items: center;width: 35px;height: 30px;justify-content: center;\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/label><input type=\"checkbox\" id=\"item\"><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1' style='display:block'><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#Part_1_Preparing_an_M50_Solution_of_Oxalic_Acid\" title=\"Part 1: Preparing an M\/50 Solution of Oxalic Acid\">Part 1: Preparing an M\/50 Solution of Oxalic Acid<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#What_is_an_M50_Solution\" title=\"What is an M\/50 Solution?\">What is an M\/50 Solution?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#Molecular_Weight_of_Oxalic_Acid_H%E2%82%82C%E2%82%82O%E2%82%842H%E2%82%82O\" title=\"Molecular Weight of Oxalic Acid (H\u2082C\u2082O\u2084.2H\u2082O)\">Molecular Weight of Oxalic Acid (H\u2082C\u2082O\u2084.2H\u2082O)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#Amount_of_Oxalic_Acid_Required\" title=\"Amount of Oxalic Acid Required\">Amount of Oxalic Acid Required<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#Step-by-Step_Preparation\" title=\"Step-by-Step Preparation\">Step-by-Step Preparation<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#Part_2_Determining_the_Molarity_and_Strength_of_a_Given_Potassium_Permanganate_KMnO%E2%82%84_Solution\" title=\"Part 2: Determining the Molarity and Strength of a Given Potassium Permanganate (KMnO\u2084) Solution\">Part 2: Determining the Molarity and Strength of a Given Potassium Permanganate (KMnO\u2084) Solution<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#Principle_of_Titration\" title=\"Principle of Titration\">Principle of Titration<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#Step-by-Step_Titration_Process\" title=\"Step-by-Step Titration Process\">Step-by-Step Titration Process<\/a><ul class='ez-toc-list-level-4'><li class='ez-toc-heading-level-4'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#Apparatus_Required\" title=\"Apparatus Required:\">Apparatus Required:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-4'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#Chemicals_Required\" title=\"Chemicals Required:\">Chemicals Required:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-4'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#Titration_Procedure\" title=\"Titration Procedure:\">Titration Procedure:<\/a><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#Part_3_Calculating_the_Molarity_and_Strength_of_KMnO%E2%82%84_Solution\" title=\"Part 3: Calculating the Molarity and Strength of KMnO\u2084 Solution\">Part 3: Calculating the Molarity and Strength of KMnO\u2084 Solution<\/a><ul class='ez-toc-list-level-3'><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#Using_the_Titration_Formula\" title=\"Using the Titration Formula:\">Using the Titration Formula:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#Finding_the_Strength_of_KMnO%E2%82%84_Solution\" title=\"Finding the Strength of KMnO\u2084 Solution\">Finding the Strength of KMnO\u2084 Solution<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/infinitylearn.com\/surge\/study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/#Conclusion\" title=\"Conclusion\">Conclusion<\/a><\/li><\/ul><\/nav><\/div>\n<p>In this experiment, we will learn:<\/p>\n<ol>\n<li><strong>How to prepare an M\/50 solution of oxalic acid<\/strong> (H\u2082C\u2082O\u2084).<\/li>\n<li><strong>How to use this solution to determine the molarity and strength of a given <a href=\"https:\/\/infinitylearn.com\/surge\/chemistry\/potassium-permanganate\/\">potassium permanganate (KMnO\u2084) solution<\/a><\/strong> using a titration method.<\/li>\n<\/ol>\n<p>This process is important in <strong><a href=\"https:\/\/infinitylearn.com\/surge\/chemistry\/\">chemistry<\/a><\/strong> as it helps in analyzing unknown solutions through a chemical reaction.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"Part_1_Preparing_an_M50_Solution_of_Oxalic_Acid\"><\/span>Part 1: Preparing an M\/50 Solution of Oxalic Acid<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3><span class=\"ez-toc-section\" id=\"What_is_an_M50_Solution\"><\/span>What is an M\/50 Solution?<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ul>\n<li><strong>Molarity (M)<\/strong> is a measure of concentration, expressed as <strong>moles per liter<\/strong>.<\/li>\n<li>An <strong>M\/50 solution<\/strong> means <strong>1\/50 of a molar solution<\/strong>, which is <strong>0.02 M<\/strong> (since 1\/50 = 0.02).<\/li>\n<\/ul>\n<h3><span class=\"ez-toc-section\" id=\"Molecular_Weight_of_Oxalic_Acid_H%E2%82%82C%E2%82%82O%E2%82%842H%E2%82%82O\"><\/span>Molecular Weight of Oxalic Acid (H\u2082C\u2082O\u2084.2H\u2082O)<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ul>\n<li>Oxalic acid exists as <strong>oxalic acid dihydrate (H\u2082C\u2082O\u2084.2H\u2082O)<\/strong>.<\/li>\n<li>Its <strong>molecular weight<\/strong> is <strong>126 g\/mol<\/strong>.<\/li>\n<\/ul>\n<h3><span class=\"ez-toc-section\" id=\"Amount_of_Oxalic_Acid_Required\"><\/span>Amount of <a href=\"https:\/\/infinitylearn.com\/surge\/oxalic-acid\/\">Oxalic Acid<\/a> Required<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ul>\n<li><strong>Formula for mass calculation:<\/strong><br \/>\n<math display=\"block\" xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mtext>Mass<\/mtext><mo>=<\/mo><mfrac><mrow><mtext>Molecular Weight<\/mtext><mo>\u00d7<\/mo><mtext>Molarity<\/mtext><mo>\u00d7<\/mo><mtext>Volume (in L)<\/mtext><\/mrow><mn>1<\/mn><\/mfrac><\/mrow><annotation encoding=\"application\/x-tex\">\\text{Mass} = \\frac{\\text{Molecular Weight} \\times \\text{Molarity} \\times \\text{Volume (in L)}}{1}<\/annotation><\/semantics><\/math>\n<p><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"mord text\"><span class=\"mord\">Mass<\/span><\/span><span class=\"mrel\">=<\/span><\/span><span class=\"base\"><span class=\"mord\"><span class=\"mfrac\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\">1<span class=\"mord text\">Molecular Weight<\/span><span class=\"mbin\">\u00d7<\/span><span class=\"mord text\">Molarity<\/span><span class=\"mbin\">\u00d7<\/span><span class=\"mord text\">Volume (in L)<\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/li>\n<li>For <strong>M\/50 (0.02 M) solution<\/strong> in <strong>1000 mL (1 liter)<\/strong>:<br \/>\n<math display=\"block\" xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mtext>Mass<\/mtext><mo>=<\/mo><mfrac><mrow><mn>126<\/mn><mo>\u00d7<\/mo><mn>0.02<\/mn><mo>\u00d7<\/mo><mn>1000<\/mn><\/mrow><mn>1000<\/mn><\/mfrac><mo>=<\/mo><mn>2.52<\/mn><mtext> g<\/mtext><\/mrow><annotation encoding=\"application\/x-tex\">\\text{Mass} = \\frac{126 \\times 0.02 \\times 1000}{1000} = 2.52 \\text{ g}<\/annotation><\/semantics><\/math>\n<p><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"mord text\"><span class=\"mord\">Mass<\/span><\/span><span class=\"mrel\">=<\/span><\/span><span class=\"base\"><span class=\"mord\"><span class=\"mfrac\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\">1000126<span class=\"mbin\">\u00d7<\/span>0.02<span class=\"mbin\">\u00d7<\/span>1000<\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><span class=\"mrel\">=<\/span><\/span><span class=\"base\"><span class=\"mord\">2.52<\/span><span class=\"mord text\"><span class=\"mord\"> g<\/span><\/span><\/span><\/span><\/li>\n<\/ul>\n<p>Thus, to prepare <strong>1 liter of M\/50 oxalic acid solution<\/strong>, dissolve <strong>2.52 g of oxalic acid dihydrate<\/strong> in <strong>distilled water<\/strong> and make the volume up to <strong>1000 mL<\/strong>.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Step-by-Step_Preparation\"><\/span>Step-by-Step Preparation<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<ol>\n<li><strong>Weigh 2.52 g of oxalic acid dihydrate<\/strong> using a digital balance.<\/li>\n<li><strong>Dissolve it in about 500 mL of distilled water<\/strong> in a beaker.<\/li>\n<li><strong>Stir well until fully dissolved.<\/strong><\/li>\n<li><strong>Transfer the solution into a 1-liter volumetric flask.<\/strong><\/li>\n<li><strong>Add distilled water up to the 1000 mL mark<\/strong>.<\/li>\n<li><strong>Shake the flask gently<\/strong> to mix the solution properly.<\/li>\n<li>The <strong>M\/50 oxalic acid solution<\/strong> is now ready for use.<\/li>\n<\/ol>\n<h2><span class=\"ez-toc-section\" id=\"Part_2_Determining_the_Molarity_and_Strength_of_a_Given_Potassium_Permanganate_KMnO%E2%82%84_Solution\"><\/span>Part 2: Determining the Molarity and Strength of a Given Potassium Permanganate (KMnO\u2084) Solution<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>We will use <strong>titration<\/strong> to find out the molarity of KMnO\u2084 using the prepared oxalic acid solution.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Principle_of_Titration\"><\/span>Principle of Titration<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Potassium permanganate (KMnO\u2084) is a <strong>strong oxidizing agent<\/strong>, and oxalic acid (H\u2082C\u2082O\u2084) is a <strong>reducing agent<\/strong>. In <strong>acidic medium (H\u2082SO\u2084)<\/strong>, they react as follows:<\/p>\n<p>&nbsp;<\/p>\n<math display=\"block\" xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mn>2<\/mn><mi>M<\/mi><mi>n<\/mi><msubsup><mi>O<\/mi><mn>4<\/mn><mo>\u2212<\/mo><\/msubsup><mo>+<\/mo><mn>5<\/mn><msub><mi>C<\/mi><mn>2<\/mn><\/msub><msubsup><mi>O<\/mi><mn>4<\/mn><mrow><mn>2<\/mn><mo>\u2212<\/mo><\/mrow><\/msubsup><mo>+<\/mo><mn>16<\/mn><msup><mi>H<\/mi><mo>+<\/mo><\/msup><mo>\u2192<\/mo><mn>2<\/mn><mi>M<\/mi><msup><mi>n<\/mi><mrow><mn>2<\/mn><mo>+<\/mo><\/mrow><\/msup><mo>+<\/mo><mn>10<\/mn><mi>C<\/mi><msub><mi>O<\/mi><mn>2<\/mn><\/msub><mo>+<\/mo><mn>8<\/mn><msub><mi>H<\/mi><mn>2<\/mn><\/msub><mi>O<\/mi><\/mrow><annotation encoding=\"application\/x-tex\">2MnO_4^- + 5C_2O_4^{2-} + 16H^+ \u2192 2Mn^{2+} + 10CO_2 + 8H_2O<\/annotation><\/semantics><\/math>\n<p><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"mord\">2<\/span><span class=\"mord mathnormal\">M<\/span><span class=\"mord mathnormal\">n<\/span><span class=\"mord\"><span class=\"mord mathnormal\">O<\/span><span class=\"msupsub\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">4<\/span><\/span><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mbin mtight\">\u2212<\/span><\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><span class=\"mbin\">+<\/span><\/span><span class=\"base\"><span class=\"mord\">5<\/span><span class=\"mord\"><span class=\"mord mathnormal\">C<\/span><span class=\"msupsub\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">2<\/span><\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><span class=\"mord\"><span class=\"mord mathnormal\">O<\/span><span class=\"msupsub\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">4<\/span><\/span><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">2\u2212<\/span><\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><span class=\"mbin\">+<\/span><\/span><span class=\"base\"><span class=\"mord\">16<\/span><span class=\"mord\"><span class=\"mord mathnormal\">H<\/span><span class=\"msupsub\"><span class=\"vlist-t\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mbin mtight\">+<\/span><\/span><\/span><\/span><\/span><\/span><\/span><span class=\"mrel\">\u2192<\/span><\/span><span class=\"base\"><span class=\"mord\">2<\/span><span class=\"mord mathnormal\">M<\/span><span class=\"mord\"><span class=\"mord mathnormal\">n<\/span><span class=\"msupsub\"><span class=\"vlist-t\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">2+<\/span><\/span><\/span><\/span><\/span><\/span><\/span><span class=\"mbin\">+<\/span><\/span><span class=\"base\"><span class=\"mord\">10<\/span><span class=\"mord mathnormal\">C<\/span><span class=\"mord\"><span class=\"mord mathnormal\">O<\/span><span class=\"msupsub\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">2<\/span><\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><span class=\"mbin\">+<\/span><\/span><span class=\"base\"><span class=\"mord\">8<\/span><span class=\"mord\"><span class=\"mord mathnormal\">H<\/span><span class=\"msupsub\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">2<\/span><\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><span class=\"mord mathnormal\">O<\/span><\/span><\/span><\/p>\n<p>This means <strong>2 moles of KMnO\u2084 react with 5 moles of oxalic acid<\/strong>.<\/p>\n<h3><span class=\"ez-toc-section\" id=\"Step-by-Step_Titration_Process\"><\/span>Step-by-Step Titration Process<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<h4><span class=\"ez-toc-section\" id=\"Apparatus_Required\"><\/span><strong>Apparatus Required:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h4>\n<ul>\n<li>Burette<\/li>\n<li>Pipette (10 mL)<\/li>\n<li>Conical flask<\/li>\n<li>Measuring cylinder<\/li>\n<li>Funnel<\/li>\n<li>Distilled water<\/li>\n<li>Beaker<\/li>\n<li>Sulfuric acid (H\u2082SO\u2084)<\/li>\n<\/ul>\n<h4><span class=\"ez-toc-section\" id=\"Chemicals_Required\"><\/span>Chemicals Required:<span class=\"ez-toc-section-end\"><\/span><\/h4>\n<ul>\n<li><strong>M\/50 Oxalic acid solution (prepared earlier)<\/strong><\/li>\n<li><strong>Potassium permanganate (KMnO\u2084) solution (unknown molarity)<\/strong><\/li>\n<li><strong>Dilute sulfuric acid (H\u2082SO\u2084) for acidic medium<\/strong><\/li>\n<\/ul>\n<h4><span class=\"ez-toc-section\" id=\"Titration_Procedure\"><\/span>Titration Procedure:<span class=\"ez-toc-section-end\"><\/span><\/h4>\n<ol>\n<li><strong>Rinse the burette<\/strong> with distilled water and then with the KMnO\u2084 solution.<\/li>\n<li><strong>Fill the burette<\/strong> with <strong>KMnO\u2084 solution<\/strong> and note the initial reading.<\/li>\n<li><strong>Pipette 10 mL of M\/50 oxalic acid solution<\/strong> into a clean <strong>conical flask<\/strong>.<\/li>\n<li><strong>Add about 10 mL of dilute sulfuric acid<\/strong> to the flask to maintain an acidic medium.<\/li>\n<li><strong>Heat the solution to about 60\u00b0C<\/strong> (warm solutions react better).<\/li>\n<li><strong>Slowly add KMnO\u2084 solution<\/strong> from the burette while <strong>swirling the flask<\/strong>.<\/li>\n<li>The <strong>KMnO\u2084 solution is purple<\/strong>, but when it reacts with oxalic acid, it becomes <strong>colorless<\/strong>.<\/li>\n<li>The <strong>end point<\/strong> is reached when a <strong>light pink color remains<\/strong> for <strong>30 seconds<\/strong>.<\/li>\n<li><strong>Note the final burette reading<\/strong>.<\/li>\n<li><strong>Repeat the titration<\/strong> 2-3 times to get consistent readings.<\/li>\n<\/ol>\n<h2><span class=\"ez-toc-section\" id=\"Part_3_Calculating_the_Molarity_and_Strength_of_KMnO%E2%82%84_Solution\"><\/span>Part 3: Calculating the Molarity and Strength of KMnO\u2084 Solution<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h3><span class=\"ez-toc-section\" id=\"Using_the_Titration_Formula\"><\/span>Using the Titration Formula:<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>&nbsp;<\/p>\n<math display=\"block\" xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><msub><mi>N<\/mi><mn>1<\/mn><\/msub><msub><mi>V<\/mi><mn>1<\/mn><\/msub><mo>=<\/mo><msub><mi>N<\/mi><mn>2<\/mn><\/msub><msub><mi>V<\/mi><mn>2<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">N_1V_1 = N_2V_2<\/annotation><\/semantics><\/math>\n<p><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"mord\"><span class=\"mord mathnormal\">N<\/span><span class=\"msupsub\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">1<\/span><\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><span class=\"mord\"><span class=\"mord mathnormal\">V<\/span><span class=\"msupsub\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">1<\/span><\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><span class=\"mrel\">=<\/span><\/span><span class=\"base\"><span class=\"mord\"><span class=\"mord mathnormal\">N<\/span><span class=\"msupsub\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">2<\/span><\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><span class=\"mord\"><span class=\"mord mathnormal\">V<\/span><span class=\"msupsub\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">2<\/span><\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<p>Where:<\/p>\n<ul>\n<li><strong>N\u2081<\/strong> = Normality of oxalic acid (M\/50 = <strong>0.02 N<\/strong>)<\/li>\n<li><strong>V\u2081<\/strong> = Volume of oxalic acid used (<strong>10 mL<\/strong>)<\/li>\n<li><strong>N\u2082<\/strong> = Normality of KMnO\u2084 (to be found)<\/li>\n<li><strong>V\u2082<\/strong> = Volume of KMnO\u2084 used (from burette)<\/li>\n<\/ul>\n<p>&nbsp;<\/p>\n<math display=\"block\" xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mn>0.02<\/mn><mo>\u00d7<\/mo><mn>10<\/mn><mo>=<\/mo><msub><mi>N<\/mi><mn>2<\/mn><\/msub><mo>\u00d7<\/mo><msub><mi>V<\/mi><mn>2<\/mn><\/msub><\/mrow><annotation encoding=\"application\/x-tex\">0.02 \\times 10 = N_2 \\times V_2<\/annotation><\/semantics><\/math>\n<p><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"mord\">0.02<\/span><span class=\"mbin\">\u00d7<\/span><\/span><span class=\"base\"><span class=\"mord\">10<\/span><span class=\"mrel\">=<\/span><\/span><span class=\"base\"><span class=\"mord\"><span class=\"mord mathnormal\">N<\/span><span class=\"msupsub\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">2<\/span><\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><span class=\"mbin\">\u00d7<\/span><\/span><span class=\"base\"><span class=\"mord\"><span class=\"mord mathnormal\">V<\/span><span class=\"msupsub\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">2<\/span><\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<math display=\"block\" xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><msub><mi>N<\/mi><mn>2<\/mn><\/msub><mo>=<\/mo><mfrac><mrow><mn>0.02<\/mn><mo>\u00d7<\/mo><mn>10<\/mn><\/mrow><msub><mi>V<\/mi><mn>2<\/mn><\/msub><\/mfrac><\/mrow><annotation encoding=\"application\/x-tex\">N_2 = \\frac{0.02 \\times 10}{V_2}<\/annotation><\/semantics><\/math>\n<p><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"mord\"><span class=\"mord mathnormal\">N<\/span><span class=\"msupsub\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">2<\/span><\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><span class=\"mrel\">=<\/span><\/span><span class=\"base\"><span class=\"mord\"><span class=\"mfrac\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\"><span class=\"mord mathnormal\">V<\/span><span class=\"msupsub\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">2<\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span>0.02<span class=\"mbin\">\u00d7<\/span>10<\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<p>Now, <strong>Molarity (M) of KMnO\u2084<\/strong> is:<\/p>\n<p>&nbsp;<\/p>\n<math display=\"block\" xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mi>M<\/mi><mo>=<\/mo><mfrac><mi>N<\/mi><mn>5<\/mn><\/mfrac><\/mrow><annotation encoding=\"application\/x-tex\">M = \\frac{N}{5}<\/annotation><\/semantics><\/math>\n<p><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"mord mathnormal\">M<\/span><span class=\"mrel\">=<\/span><\/span><span class=\"base\"><span class=\"mord\"><span class=\"mfrac\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\">5<span class=\"mord mathnormal\">N<\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<p>(Since <strong>KMnO\u2084 undergoes a 5-electron change<\/strong>)<\/p>\n<p>After substituting <strong>N\u2082<\/strong>, we get:<\/p>\n<p>&nbsp;<\/p>\n<math display=\"block\" xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mi>M<\/mi><mo>=<\/mo><mfrac><mrow><mn>0.02<\/mn><mo>\u00d7<\/mo><mn>10<\/mn><\/mrow><mrow><mn>5<\/mn><mo>\u00d7<\/mo><msub><mi>V<\/mi><mn>2<\/mn><\/msub><\/mrow><\/mfrac><\/mrow><annotation encoding=\"application\/x-tex\">M = \\frac{0.02 \\times 10}{5 \\times V_2}<\/annotation><\/semantics><\/math>\n<p><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"mord mathnormal\">M<\/span><span class=\"mrel\">=<\/span><\/span><span class=\"base\"><span class=\"mord\"><span class=\"mfrac\"><span class=\"vlist-t vlist-t2\"><span class=\"vlist-r\"><span class=\"vlist\">5<span class=\"mbin\">\u00d7<\/span><span class=\"mord mathnormal\">V<\/span><span class=\"msupsub\"><span class=\"sizing reset-size6 size3 mtight\"><span class=\"mord mtight\">2<\/span><\/span><span class=\"vlist-s\">\u200b<\/span><\/span>0.02<span class=\"mbin\">\u00d7<\/span>10<\/span><span class=\"vlist-s\">\u200b<\/span><\/span><\/span><\/span><\/span><\/span><\/span><\/p>\n<h3><span class=\"ez-toc-section\" id=\"Finding_the_Strength_of_KMnO%E2%82%84_Solution\"><\/span>Finding the Strength of KMnO\u2084 Solution<span class=\"ez-toc-section-end\"><\/span><\/h3>\n<p>Strength (grams per liter) = <strong>Molarity \u00d7 Molecular Weight of KMnO\u2084<\/strong><br \/>\n(Since molecular weight of KMnO\u2084 = <strong>158 g\/mol<\/strong>)<\/p>\n<p>&nbsp;<\/p>\n<math display=\"block\" xmlns=\"http:\/\/www.w3.org\/1998\/Math\/MathML\"><semantics><mrow><mtext>Strength<\/mtext><mo>=<\/mo><mi>M<\/mi><mo>\u00d7<\/mo><mn>158<\/mn><\/mrow><annotation encoding=\"application\/x-tex\">\\text{Strength} = M \\times 158<\/annotation><\/semantics><\/math>\n<p><span class=\"katex-html\" aria-hidden=\"true\"><span class=\"base\"><span class=\"mord text\"><span class=\"mord\">Strength<\/span><\/span><span class=\"mrel\">=<\/span><\/span><span class=\"base\"><span class=\"mord mathnormal\">M<\/span><span class=\"mbin\">\u00d7<\/span><\/span><span class=\"base\"><span class=\"mord\">158<\/span><\/span><\/span><\/p>\n<p>Thus, we can determine the <strong>molarity and strength of the potassium permanganate solution<\/strong> based on the volume used in the titration.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"Conclusion\"><\/span>Conclusion<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ol>\n<li>We prepared an <strong>M\/50 solution of oxalic acid<\/strong> by dissolving <strong>2.52 g of oxalic acid dihydrate in 1 liter of water<\/strong>.<\/li>\n<li>We performed a <strong>redox titration<\/strong> using oxalic acid and KMnO\u2084 in the presence of sulfuric acid.<\/li>\n<li>We used the <strong>titration formula to calculate the molarity and strength<\/strong> of the potassium permanganate solution.<\/li>\n<\/ol>\n<p>This experiment helps us understand <strong>how titrations are used to determine unknown concentrations<\/strong>, which is a crucial technique in chemistry.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>In this experiment, we will learn: How to prepare an M\/50 solution of oxalic acid (H\u2082C\u2082O\u2084). How to use this [&hellip;]<\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_yoast_wpseo_focuskw":"M\/50","_yoast_wpseo_title":"Prepare M\/50 Solution of Oxalic Acid. With its help, Determine 50 the Molarity and Strength of the Given Solution of Potassium Permanganate","_yoast_wpseo_metadesc":"Get Prepare M\/50 Solution of Oxalic Acid. With its help, Determine 50 the Molarity and Strength of the Given Solution of Potassium Permanganate on Infinity Learn.","custom_permalink":"study-material\/cbse\/chemistry\/prepare-m-50-solution-of-oxalic-acid-with-its-help-determine-50-the-molarity-and-strength-of-the-given-solution-of-potassium-permanganate\/"},"categories":[92,21],"tags":[],"table_tags":[],"acf":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v17.9 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Prepare M\/50 Solution of Oxalic Acid. 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