{"id":251396,"date":"2022-09-10T10:39:55","date_gmt":"2022-09-10T05:09:55","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/question\/the-electric-field-intensity-due-to-a-dipole-of-length-10-cm-and-having-a-charge-of-500-%ce%bcc-at-a-point-on-the-axis-at-a-distance-20-cm-from-one-of-the-charges-in-air-is\/"},"modified":"2022-09-10T10:39:55","modified_gmt":"2022-09-10T05:09:55","slug":"the-electric-field-intensity-due-to-a-dipole-of-length-10-cm-and-having-a-charge-of-500-%ce%bcc-at-a-point-on-the-axis-at-a-distance-20-cm-from-one-of-the-charges-in-air-is","status":"publish","type":"questions","link":"https:\/\/infinitylearn.com\/surge\/question\/physics\/the-electric-field-intensity-due-to-a-dipole-of-length-10-cm\/","title":{"rendered":"The electric field intensity due to a dipole of length 10 cm and having a charge of 500 \u03bcC, at a point on the axis at a distance 20 cm from one of the charges in air, is"},"content":{"rendered":"","protected":false},"author":1,"template":"","meta":{"_yoast_wpseo_focuskw":"","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"The electric field intensity due to a dipole of length 10 cm and having a charge of 500 \u03bcC, at a point on the axis at a distance 20 cm from one of the charges in air, is","custom_permalink":"question\/physics\/the-electric-field-intensity-due-to-a-dipole-of-length-10-cm\/"},"categories":[],"acf":{"question":"

The electric field intensity due to a dipole of length 10 cm and having a charge of 500 \u03bcC, at a point on the axis at a distance 20 cm from one of the charges in air, is<\/p>","options":[{"option":"

6.25 x 107<\/sup> N\/C<\/p>","correct":true},{"option":"

9.28 x 107<\/sup> N\/C<\/p>","correct":false},{"option":"

13.1x1111<\/sup> N\/C<\/p>","correct":false},{"option":"

20.5 x 107<\/sup> N\/C<\/p>","correct":false}],"solution":"

 We know, <\/mtext>E<\/mi>=<\/mo>9<\/mn>\u00d7<\/mo>10<\/mn>9<\/mn><\/msup>\u00b7<\/mo>2<\/mn>pr<\/mi><\/mrow>r<\/mi>2<\/mn><\/msup>-<\/mo>l<\/mi>2<\/mn><\/msup><\/mrow><\/mfenced>2<\/mn><\/msup><\/mfrac><\/math><\/p>
<\/figure>

 where <\/mtext>p<\/mi><\/mtd>=<\/mo><\/mtd>500<\/mn>\u00d7<\/mo>10<\/mn>-<\/mo>6<\/mn><\/mrow><\/msup><\/mrow><\/mfenced>\u00d7<\/mo>10<\/mn>\u00d7<\/mo>10<\/mn>-<\/mo>2<\/mn><\/mrow><\/msup><\/mrow><\/mfenced>=<\/mo>5<\/mn>\u00d7<\/mo>10<\/mn>-<\/mo>5<\/mn><\/mrow><\/msup>Cm<\/mi><\/mtd><\/mtr>r<\/mi><\/mtd>=<\/mo><\/mtd>25<\/mn> <\/mo>cm<\/mi>=<\/mo>0<\/mn>.<\/mo>25<\/mn> <\/mo>m<\/mi>,<\/mo>l<\/mi>=<\/mo>5<\/mn> <\/mo>cm<\/mi>=<\/mo>0<\/mn>.<\/mo>05<\/mn> <\/mo>m<\/mi><\/mtd><\/mtr>E<\/mi><\/mtd>=<\/mo><\/mtd>9<\/mn>\u00d7<\/mo>10<\/mn>9<\/mn><\/msup>\u00d7<\/mo>2<\/mn>\u00d7<\/mo>5<\/mn>\u00d7<\/mo>10<\/mn>-<\/mo>5<\/mn><\/mrow><\/msup>\u00d7<\/mo>0<\/mn>.<\/mo>25<\/mn><\/mrow>(<\/mo>0<\/mn>.<\/mo>25<\/mn>)<\/mo>2<\/mn><\/msup>-<\/mo>(<\/mo>0<\/mn>.<\/mo>05<\/mn>)<\/mo>2<\/mn><\/msup><\/mrow><\/mfenced>2<\/mn><\/msup><\/mfrac><\/mtd><\/mtr> <\/mtd>=<\/mo><\/mtd>6<\/mn>.<\/mo>25<\/mn>\u00d7<\/mo>10<\/mn>7<\/mn><\/msup> <\/mo>N<\/mi>\/<\/mo>C<\/mi><\/mtd><\/mtr><\/mtable><\/math><\/p>","subject":""},"yoast_head":"\nThe electric field intensity due to a dipole of length 10 cm and having a charge of 500 \u03bcC, at a point on the axis at a distance 20 cm from one of the charges in air, is - 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