{"id":254744,"date":"2022-09-10T11:19:41","date_gmt":"2022-09-10T05:49:41","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/question\/the-distance-between-h-and-cl%e2%88%92-ions-in-hci-molecule-is-1-28%e2%80%89a%e2%88%98-what-will-be-the-potential-due-to-this-dipole-at-a-distance-of-12%e2%80%89a\/"},"modified":"2022-09-10T11:19:41","modified_gmt":"2022-09-10T05:49:41","slug":"the-distance-between-h-and-cl%e2%88%92-ions-in-hci-molecule-is-1-28%e2%80%89a%e2%88%98-what-will-be-the-potential-due-to-this-dipole-at-a-distance-of-12%e2%80%89a","status":"publish","type":"questions","link":"https:\/\/infinitylearn.com\/surge\/question\/physics\/the--distance-between-h-----and-cl-----ions-in-hci-molec\/","title":{"rendered":"The distance between H+ \u00a0and Cl\u2212 \u00a0ions in HCI molecule is 1.28\u2009A\u2218 . What will be the potential due to this dipole at a distance of 12\u2009A\u2218 \u00a0on the axis of dipole?"},"content":{"rendered":"","protected":false},"author":1,"template":"","meta":{"_yoast_wpseo_focuskw":"","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"The distance between H+ \u00a0and Cl\u2212 \u00a0ions in HCI molecule is 1.28\u2009A\u2218 . What will be the potential due to this dipole at a distance of 12\u2009A\u2218 \u00a0on the axis of dipole?","custom_permalink":"question\/physics\/the--distance-between-h-----and-cl-----ions-in-hci-molec\/"},"categories":[],"acf":{"question":"

The distance between H<\/mi>+<\/mo><\/msup><\/mrow><\/math> <\/xml> and C<\/mi>l<\/mi>\u2212<\/mo><\/msup><\/mrow><\/math> <\/xml> ions in HCI molecule is 1.28<\/mn>\u2009<\/mtext>A<\/mi>\u2218<\/mo><\/mover><\/mrow><\/math> <\/xml>. What will be the potential due to this dipole at a distance of 12<\/mn>\u2009<\/mtext>A<\/mi>\u2218<\/mo><\/mover><\/mrow><\/math> <\/xml> on the axis of dipole? <\/p>","options":[{"option":"

0.13 V <\/p>","correct":true},{"option":"

13 V <\/p>","correct":false},{"option":"

1.3 V <\/p>","correct":false},{"option":"

130 V <\/p>","correct":false}],"solution":"

Here, 2<\/mn>a<\/mi>=<\/mo>1.28<\/mn>\u2009<\/mtext>\u2009<\/mtext>A<\/mi>\u2218<\/mo><\/mover>=<\/mo>1.28<\/mn>\u2009<\/mtext>\u2009<\/mtext>\u00d7<\/mo>\u2009<\/mtext>10<\/mn><\/mrow>\u2212<\/mo>10<\/mn><\/mrow><\/msup>m<\/mi><\/mrow><\/math> <\/xml> <\/p>

           V<\/mi>=<\/mo>?<\/mo>,<\/mo>\u2009<\/mtext>r<\/mi>=<\/mo>12<\/mn>A<\/mi>\u2218<\/mo><\/mover>=<\/mo>12<\/mn>\u2009<\/mtext>\u2009<\/mtext>\u00d7<\/mo>\u2009<\/mtext>10<\/mn><\/mrow>\u2212<\/mo>10<\/mn><\/mrow><\/msup>m<\/mi><\/mrow><\/math> <\/xml><\/p>

As the point is on axial line of dipole<\/p>

\u2234<\/mo><\/math> <\/xml>               V<\/mi>=<\/mo>k<\/mi>\u2009<\/mtext>q<\/mi>\u2009<\/mtext>(<\/mo>2<\/mn>\u2009<\/mtext>a<\/mi>)<\/mo><\/mrow>r<\/mi>2<\/mn><\/msup><\/mrow><\/mfrac><\/mrow><\/math> <\/xml><\/p>

=<\/mo>9<\/mn>\u2009<\/mtext>\u2009<\/mtext>\u00d7<\/mo>\u2009<\/mtext>10<\/mn><\/mrow>9<\/mn><\/msup>\u00d7<\/mo>1.6<\/mn>\u2009<\/mtext>\u2009<\/mtext>\u00d7<\/mo>\u2009<\/mtext>10<\/mn><\/mrow>\u2212<\/mo>19<\/mn><\/mrow><\/msup>(<\/mo>1.28<\/mn>\u2009<\/mtext>\u2009<\/mtext>\u00d7<\/mo>\u2009<\/mtext>10<\/mn><\/mrow>\u2212<\/mo>10<\/mn><\/mrow><\/msup>)<\/mo><\/mrow>(<\/mo>12<\/mn>\u2009<\/mtext>\u00d7<\/mo>\u2009<\/mtext>10<\/mn><\/mrow>\u2212<\/mo>10<\/mn><\/mrow><\/msup>)<\/mo><\/mrow>2<\/mn><\/msup><\/mrow><\/mfrac><\/mrow><\/math> <\/xml><\/p>

=<\/mo>0.128<\/mn>\u2009<\/mtext>\u2248<\/mo>\u2009<\/mtext>0.13<\/mn>\u2009<\/mtext>V<\/mi><\/mrow><\/math> <\/xml><\/p>

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