{"id":258970,"date":"2022-09-10T12:09:20","date_gmt":"2022-09-10T06:39:20","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/question\/a-particle-of-mass-2kg-is-initially-at-rest-a-force-acts-on-it-whose-magnitude-changes-with-time-the-force-time-graph-is-shown-below-the-velocity-of-the-particle-at-t10-sec\/"},"modified":"2022-09-10T12:09:20","modified_gmt":"2022-09-10T06:39:20","slug":"a-particle-of-mass-2kg-is-initially-at-rest-a-force-acts-on-it-whose-magnitude-changes-with-time-the-force-time-graph-is-shown-below-the-velocity-of-the-particle-at-t10-sec","status":"publish","type":"questions","link":"https:\/\/infinitylearn.com\/surge\/question\/physics\/a-particle-of-mass-2kg-is-initially-at-rest-a-force-acts-o\/","title":{"rendered":"\u00a0A particle of mass 2kg is initially at rest. \u00a0A force acts on it whose magnitude changes with time. \u00a0The force-time graph is shown below. \u00a0The velocity of the particle at t=10 sec is\u00a0\u00a0\u00a0"},"content":{"rendered":"","protected":false},"author":1,"template":"","meta":{"_yoast_wpseo_focuskw":"","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"\u00a0A particle of mass 2kg is initially at rest. \u00a0A force acts on it whose magnitude changes with time. \u00a0The force-time graph is shown below. \u00a0The velocity of the particle at t=10 sec is\u00a0\u00a0\u00a0","custom_permalink":"question\/physics\/a-particle-of-mass-2kg-is-initially-at-rest-a-force-acts-o\/"},"categories":[],"acf":{"question":"

 A particle of mass 2kg is initially at rest.  A force acts on it whose magnitude changes with time.  The force-time graph is shown below.  The velocity of the particle at t=10 sec is 
 <\/p>

<\/figure>

 <\/p>","options":[{"option":"

75<\/mn>\u2009\u2009<\/mtext>m<\/mi>s<\/mi>\u2212<\/mo>1<\/mn><\/mrow><\/msup><\/math><\/p>","correct":false},{"option":"

10<\/mn>\u2009\u2009<\/mtext>m<\/mi>s<\/mi>\u2212<\/mo>1<\/mn><\/mrow><\/msup><\/math><\/p>","correct":false},{"option":"

50<\/mn>\u2009\u2009<\/mtext>m<\/mi>s<\/mi>\u2212<\/mo>1<\/mn><\/mrow><\/msup><\/math><\/p>","correct":true},{"option":"

26<\/mn>\u2009\u2009<\/mtext>m<\/mi>s<\/mi>\u2212<\/mo>1<\/mn><\/mrow><\/msup><\/math><\/p>","correct":false}],"solution":"

Area under the force-time graph is impulse i.e., change in momentum.
\u21d2<\/mo>\u2206<\/mo>p<\/mi>=<\/mo>1<\/mn>2<\/mn><\/mfrac>2<\/mn>\u00d7<\/mo>10<\/mn>+<\/mo>2<\/mn>\u00d7<\/mo>10<\/mn>+<\/mo>1<\/mn>2<\/mn><\/mfrac>\u00d7<\/mo>2<\/mn>\u00d7<\/mo>10<\/mn>+<\/mo>20<\/mn><\/mrow><\/mfenced>+<\/mo>1<\/mn>2<\/mn><\/mfrac>\u00d7<\/mo>4<\/mn>\u00d7<\/mo>20<\/mn><\/math>
\u21d2<\/mo>m<\/mi>v<\/mi>\u2212<\/mo>u<\/mi><\/mrow><\/mfenced>\u2009<\/mtext>=<\/mo>\u2009<\/mtext>10<\/mn>+<\/mo>20<\/mn>+<\/mo>30<\/mn>+<\/mo>40<\/mn><\/math>
\u21d2<\/mo>2<\/mn>\u00d7<\/mo>v<\/mi>\u2009<\/mtext>=<\/mo>\u2009<\/mtext>100<\/mn><\/math>
\u21d2<\/mo>v<\/mi>\u2009<\/mtext>=<\/mo>50<\/mn>m<\/mi>\/<\/mo>s<\/mi><\/math><\/p>","subject":""},"yoast_head":"\n\u00a0A particle of mass 2kg is initially at rest. \u00a0A force acts on it whose magnitude changes with time. \u00a0The force-time graph is shown below. \u00a0The velocity of the particle at t=10 sec is\u00a0\u00a0\u00a0 - Infinity Learn by Sri Chaitanya<\/title>\n<meta name=\"description\" content=\"\u00a0A particle of mass 2kg is initially at rest. \u00a0A force acts on it whose magnitude changes with time. \u00a0The force-time graph is shown below. \u00a0The velocity of the particle at t=10 sec is\u00a0\u00a0\u00a0\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/infinitylearn.com\/surge\/question\/physics\/a-particle-of-mass-2kg-is-initially-at-rest-a-force-acts-o\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"\u00a0A particle of mass 2kg is initially at rest. \u00a0A force acts on it whose magnitude changes with time. \u00a0The force-time graph is shown below. \u00a0The velocity of the particle at t=10 sec is\u00a0\u00a0\u00a0 - 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