{"id":339262,"date":"2023-01-06T10:52:14","date_gmt":"2023-01-06T05:22:14","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/question\/the-certain-force-acting-on-a-20-kg-mass-changes-its-velocity-from-5-m-s-1-to-2-m-s-1-calculate-the-work-done-by-the-force\/"},"modified":"2025-06-30T11:01:31","modified_gmt":"2025-06-30T05:31:31","slug":"the-certain-force-acting-on-a-20-kg-mass-changes-its-velocity-from-5-m-s-1-to-2-m-s-1-calculate-the-work-done-by-the-force","status":"publish","type":"questions","link":"https:\/\/infinitylearn.com\/surge\/question\/physics\/the-certain-force-acting-on-a-20kg-mass-changes-its-velocit\/","title":{"rendered":"The certain force acting on a 20\u00a0kg mass changes its velocity from 5\u00a0m\u00a0s-1 to 2\u00a0m\u00a0s-1. Calculate the work done by the force."},"content":{"rendered":"","protected":false},"author":1,"template":"","meta":{"_yoast_wpseo_focuskw":"","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"The certain force acting on a 20\u00a0kg mass changes its velocity from 5\u00a0m\u00a0s-1 to 2\u00a0m\u00a0s-1. Calculate the work done by the force.","custom_permalink":"question\/physics\/the-certain-force-acting-on-a-20kg-mass-changes-its-velocit\/"},"categories":[],"acf":{"question":"

The certain force acting on a <\/span>20<\/mn> kg<\/mi><\/math> mass changes its velocity from <\/span>5<\/mn> m <\/mi>s<\/mi><\/mrow>-<\/mo>1<\/mn><\/mrow><\/msup><\/math> to <\/span>2<\/mn> m <\/mi>s<\/mi><\/mrow>-<\/mo>1<\/mn><\/mrow><\/msup><\/math>. Calculate the work done by the force.<\/span><\/p>

<\/p>

<\/p><\/spanstyle=\"font-family:'timesnewroman';-aw-import:ignore\"><\/pstyle=\"margin-top:0pt;margin-bottom:0pt;page-break-inside:avoid;line-height:normal;widows:0;orphans:0;font-size:12pt\"><\/spanstyle=\"font-family:'timesnewroman';-aw-import:ignore\"><\/pstyle=\"margin-top:0pt;margin-bottom:0pt;page-break-inside:avoid;line-height:normal;widows:0;orphans:0;font-size:12pt\">","options":[{"option":"-<\/mo>250<\/mn> J<\/mi><\/math>","correct":false},{"option":"250<\/mn> J<\/mi><\/math>","correct":false},{"option":"-<\/mo>210<\/mn> J<\/mi><\/math>","correct":true},{"option":"240<\/mn> J<\/mi><\/math> <\/span>","correct":false}],"solution":"The certain force acting on a <\/span>20<\/mn> kg<\/mi><\/math> mass changes its velocity from <\/span>5<\/mn> m <\/mi>s<\/mi><\/mrow>-<\/mo>1<\/mn><\/mrow><\/msup><\/math> to <\/span>2<\/mn> m <\/mi>s<\/mi><\/mrow>-<\/mo>1<\/mn><\/mrow><\/msup><\/math>. The work done by the force is <\/span>-<\/mo>210<\/mn> J<\/mi><\/math>.<\/span>
Given data in the problem,<\/span>
Mass, <\/span>m <\/mi>=<\/mo> <\/mi>20<\/mn> kg<\/mi><\/math>
Initial velocities, <\/span>u <\/mi>=<\/mo> <\/mi>5<\/mn> m<\/mi>s<\/mi><\/mrow>-<\/mo>1<\/mn><\/mrow><\/msup><\/math>
Final velocity, <\/span>v <\/mi>=<\/mo> <\/mi>2<\/mn> m <\/mi>s<\/mi><\/mrow>-<\/mo>1<\/mn><\/mrow><\/msup><\/math>
Work done, W = change in kinetic energy in mass<\/span>
\u21d2<\/mo>W<\/mi>=<\/mo>(<\/mo>E<\/mi><\/mrow>k<\/mi><\/mrow><\/msub>)<\/mo><\/mrow>f<\/mi><\/mrow><\/msub> <\/mi>-<\/mo> <\/mi>(<\/mo>E<\/mi><\/mrow>k<\/mi><\/mrow><\/msub>)<\/mo><\/mrow>i<\/mi><\/mrow><\/msub><\/math> <\/span>\u21d2<\/mo>W<\/mi>=<\/mo>1<\/mn><\/mrow>2<\/mn><\/mrow><\/mfrac>m<\/mi>v<\/mi><\/mrow>2<\/mn><\/mrow><\/msup>-<\/mo>1<\/mn><\/mrow>2<\/mn><\/mrow><\/mfrac>m<\/mi>u<\/mi><\/mrow>2<\/mn><\/mrow><\/msup><\/math> <\/span>\u21d2<\/mo>W<\/mi>=<\/mo>1<\/mn><\/mrow>2<\/mn><\/mrow><\/mfrac>m<\/mi>v<\/mi><\/mrow>2<\/mn><\/mrow><\/msup>-<\/mo>u<\/mi><\/mrow>2<\/mn><\/mrow><\/msup><\/mrow><\/mfenced><\/math> <\/span>\u21d2<\/mo>W<\/mi>=<\/mo>1<\/mn><\/mrow>2<\/mn><\/mrow><\/mfrac> <\/mi>\u00d7<\/mo> <\/mi>20<\/mn> <\/mi>\u00d7<\/mo> <\/mi>2<\/mn><\/mrow>2<\/mn><\/mrow><\/msup>-<\/mo>5<\/mn><\/mrow>2<\/mn><\/mrow><\/msup><\/mrow><\/mfenced><\/math> <\/span>\u21d2<\/mo>W<\/mi>=<\/mo>-<\/mo>210<\/mn> J<\/mi><\/math> (Negative sign indicate that the work is done by object and its kinetic energy decreases.) A negative sign indicates that the work is done by the object and its kinetic energy is decreased.<\/span>
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