{"id":346525,"date":"2023-01-06T15:16:31","date_gmt":"2023-01-06T09:46:31","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/question\/a-10-cm-tall-object-is-placed-perpendicular-to-the-principle-axis-of-a-convex-lens-of-focal-length-12-cm-the-distance-from-the-object-from-the-lens-is-18-cm-find-the-nature\/"},"modified":"2025-06-26T17:53:19","modified_gmt":"2025-06-26T12:23:19","slug":"a-10-cm-tall-object-is-placed-perpendicular-to-the-principle-axis-of-a-convex-lens-of-focal-length-12-cm-the-distance-from-the-object-from-the-lens-is-18-cm-find-the-nature","status":"publish","type":"questions","link":"https:\/\/infinitylearn.com\/surge\/question\/physics\/a-10cm-tall-object-is-placed-perpendicular-to-the-principle\/","title":{"rendered":"A 10\u00a0cm tall object is placed perpendicular to the principle axis of a convex lens of focal length\u00a012\u00a0cm. The distance from the object from the lens is\u00a018\u00a0cm. Find the nature, position and size of the image by choosing the correct option?"},"content":{"rendered":"","protected":false},"author":1,"template":"","meta":{"_yoast_wpseo_focuskw":"","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"A 10\u00a0cm tall object is placed perpendicular to the principle axis of a convex lens of focal length\u00a012\u00a0cm. The distance from the object from the lens is\u00a018\u00a0cm. Find the nature, position and size of the image by choosing the correct option?","custom_permalink":"question\/physics\/a-10cm-tall-object-is-placed-perpendicular-to-the-principle\/"},"categories":[],"acf":{"question":"

A <\/span>10<\/mn> cm<\/mi><\/math> tall object is placed perpendicular to the principle axis of a convex lens of focal length<\/span> <\/mi>12<\/mn> cm<\/mi><\/math>. The distance from the object from the lens is<\/span> <\/mi>18<\/mn> cm<\/mi><\/math>. Find the nature, position and size of the image by choosing the correct option?<\/span><\/p>

<\/p>

<\/p><\/spanstyle=\"font-family:'timesnewroman';-aw-import:ignore\"><\/pstyle=\"margin-top:0pt;margin-bottom:10pt;line-height:115%;font-size:12pt\"><\/spanstyle=\"font-family:'timesnewroman';-aw-import:ignore\"><\/pstyle=\"margin-top:0pt;margin-bottom:10pt;line-height:115%;font-size:12pt\">","options":[{"option":"Position: <\/span>33<\/mn> cm<\/mi><\/math> away from lens, nature: Virtual and erect, size: <\/span>-<\/mo>10<\/mn> cm<\/mi><\/math>","correct":false},{"option":"Position: <\/span>36<\/mn> cm<\/mi><\/math> away from lens, nature: Real and inverted, size: <\/span>-<\/mo>20<\/mn> cm<\/mi><\/math>","correct":true},{"option":"Position: <\/span>35<\/mn> cm<\/mi><\/math> away from lens, nature: Real and inverted<\/span>  <\/span>size: <\/span>20<\/mn> cm<\/mi><\/math>","correct":false},{"option":"Position: <\/span>37<\/mn> cm<\/mi><\/math> away from lens, nature: Real and inverted, size: <\/span>10<\/mn> cm<\/mi><\/math> <\/span> <\/span>","correct":false}],"solution":"Position: <\/span>36<\/mn> cm<\/mi><\/math> away from lens, nature: Real and inverted, size: <\/span>-<\/mo>20<\/mn> cm<\/mi><\/math>. <\/span>The size of the image is <\/span>20<\/mn> cm<\/mi><\/math> and negative sign denote the nature of image is inverted.<\/span>
Given,<\/span>
Object height, <\/span>h<\/mi>=<\/mo> <\/mi>+<\/mo>10<\/mn> cm<\/mi><\/math>
Focal length, <\/span>f<\/mi>=<\/mo> <\/mi>+<\/mo>12<\/mn> cm<\/mi><\/math>
Object distance, <\/span>u<\/mi>=<\/mo> <\/mi>-<\/mo>18<\/mn> cm<\/mi><\/math>
By applying the Lens formula, we get <\/span>
\u21d2<\/mo>   <\/mi>1<\/mn><\/mrow>v<\/mi><\/mrow><\/mfrac>  <\/mi>-<\/mo> <\/mi>1<\/mn><\/mrow>u<\/mi><\/mrow><\/mfrac> <\/mi>=<\/mo>1<\/mn><\/mrow>f<\/mi><\/mrow><\/mfrac><\/math>
\u21d2<\/mo>1<\/mn><\/mrow>v<\/mi><\/mrow><\/mfrac>  <\/mi>-<\/mo> <\/mi>1<\/mn><\/mrow>-<\/mo>18<\/mn><\/mrow><\/mfrac> <\/mi>=<\/mo>1<\/mn><\/mrow>12<\/mn><\/mrow><\/mfrac><\/math>
\u21d2<\/mo>                   <\/mi>1<\/mn><\/mrow>v<\/mi><\/mrow><\/mfrac> <\/mi>=<\/mo>1<\/mn><\/mrow>12<\/mn><\/mrow><\/mfrac>-<\/mo> <\/mi>1<\/mn><\/mrow>18<\/mn><\/mrow><\/mfrac><\/math>
\u21d2<\/mo>                   <\/mi>1<\/mn><\/mrow>v<\/mi><\/mrow><\/mfrac> <\/mi>=<\/mo>3<\/mn>-<\/mo>2<\/mn><\/mrow>36<\/mn><\/mrow><\/mfrac><\/math>
\u21d2<\/mo>                   <\/mi>1<\/mn><\/mrow>v<\/mi><\/mrow><\/mfrac> <\/mi>=<\/mo>1<\/mn><\/mrow>36<\/mn><\/mrow><\/mfrac><\/math>
\u21d2<\/mo>                      <\/mi>v <\/mi>=<\/mo> <\/mi>+<\/mo>36<\/mn> cm<\/mi>.<\/mo><\/math> <\/span>Hence, the position of the image is <\/span>36<\/mn> cm<\/mi><\/math> away from the lens, and the + sign denotes that the image is real. And the size of the image can be determined by<\/span>
m <\/mi>=<\/mo>  <\/mi>h<\/mi>'<\/mo><\/mrow>h<\/mi><\/mrow><\/mfrac> <\/mi>=<\/mo> <\/mi>v<\/mi><\/mrow>u<\/mi><\/mrow><\/mfrac> <\/mi><\/math>
\u21d2<\/mo>         <\/mi>h<\/mi>'<\/mo><\/mrow>10<\/mn><\/mrow><\/mfrac>=<\/mo> <\/mi>36<\/mn><\/mrow>-<\/mo>18<\/mn><\/mrow><\/mfrac><\/math> <\/span>\u21d2<\/mo>          h<\/mi>\u2019<\/mo> <\/mi>=<\/mo> <\/mi>-<\/mo>20<\/mn> cm<\/mi><\/math>
 <\/span>","subject":""},"yoast_head":"\nA 10\u00a0cm tall object is placed perpendicular to the principle axis of a convex lens of focal length\u00a012\u00a0cm. The distance from the object from the lens is\u00a018\u00a0cm. Find the nature, position and size of the image by choosing the correct option? - Infinity Learn by Sri Chaitanya<\/title>\n<meta name=\"description\" content=\"A 10\u00a0cm tall object is placed perpendicular to the principle axis of a convex lens of focal length\u00a012\u00a0cm. The distance from the object from the lens is\u00a018\u00a0cm. 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