{"id":618420,"date":"2023-06-20T13:38:34","date_gmt":"2023-06-20T08:08:34","guid":{"rendered":"https:\/\/infinitylearn.com\/surge\/question\/state-true-or-false-a-circle-has-radius-2-cm-it-is-divided-into-two-segments-by-a-chord-of-length-2-cm-then-angle-subtended-by-the-chord-at-a-point-in-the-major\/"},"modified":"2025-06-26T14:52:14","modified_gmt":"2025-06-26T09:22:14","slug":"state-true-or-false-a-circle-has-radius-2-cm-it-is-divided-into-two-segments-by-a-chord-of-length-2-cm-then-angle-subtended-by-the-chord-at-a-point-in-the-major","status":"publish","type":"questions","link":"https:\/\/infinitylearn.com\/surge\/question\/mathematics\/state-true-or-falsea-circle-has-radius-----------2--\/","title":{"rendered":"State true or false.A circle has radius           2       \u00a0\u00a0 cm. It is divided into two segments by a chord of length 2 cm. Then angle subtended by the chord at a point in the major segment is 55\u00ba."},"content":{"rendered":"","protected":false},"author":1,"template":"","meta":{"_yoast_wpseo_focuskw":"","_yoast_wpseo_title":"","_yoast_wpseo_metadesc":"State true or false.A circle has radius 2 \u00a0\u00a0 cm. It is divided into two segments by a chord of length 2 cm. Then angle subtended by the chord at a point in the major segment is 55\u00ba.","custom_permalink":"question\/mathematics\/state-true-or-falsea-circle-has-radius-----------2--\/"},"categories":[],"acf":{"question":"<p style=\"margin-top:0pt; margin-bottom:0pt; line-height:normal\"><span>State true or false.<\/span><\/p><br><p style=\"margin-top:0pt; margin-bottom:0pt; line-height:normal\"><span>A circle has radius <\/span>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:msqrt>\r\n    <m:mn>2<\/m:mn>\r\n   <\/m:msqrt>\r\n   <\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span>&nbsp; <\/span><span>cm. It is divided into two segments by a chord of length 2 cm. Then angle subtended by the chord at a point in the major segment is 55\u00ba.<\/span><\/p><br><pstyle=\"margin-top:0pt;margin-bottom:0pt;line-height:normal\"><spanstyle=\"-aw-import:ignore\"><p><\/p><pstyle=\"margin-top:0pt;margin-bottom:0pt;line-height:normal\"><spanstyle=\"-aw-import:ignore\"><p><\/p><\/spanstyle=\"-aw-import:ignore\"><\/pstyle=\"margin-top:0pt;margin-bottom:0pt;line-height:normal\"><\/spanstyle=\"-aw-import:ignore\"><\/pstyle=\"margin-top:0pt;margin-bottom:0pt;line-height:normal\">","options":[{"option":"<span>True<\/span>","correct":false},{"option":"<span>False<\/span><span>&nbsp;<\/span>","correct":true}],"solution":"<span>Given that a circle has radius <\/span>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:msqrt>\r\n    <m:mn>2<\/m:mn>\r\n   <\/m:msqrt>\r\n   <\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span>&nbsp; <\/span><span>cm. It is divided into two segments by a chord of length 2 cm. Then angle subtended by the chord at a point in the major segment is 55\u00ba.<\/span><br><span>Creating figure using given data:<\/span><br><img src=\"data:image\/jpeg;base64,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\" width=\"141\" height=\"160\" alt=\"\" class=\"image_resized\" style=\"width:141px;height:160px\"><span>We have<\/span>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:mi>B<\/m:mi><m:mi>C<\/m:mi><m:mo>=<\/m:mo><m:mn>2<\/m:mn><\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span>.<\/span><br><span>Now squaring on both sides of <\/span>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:mi>B<\/m:mi><m:mi>C<\/m:mi><m:mo>=<\/m:mo><m:mn>2<\/m:mn><\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span>. <\/span><br>\r\n<math>\r\n <m:semantics>\r\n  <m:mtable columnalign=\"left\">\r\n   <m:mtr>\r\n    <m:mtd>\r\n     <m:msup>\r\n      <m:mfenced>\r\n       <m:mrow>\r\n        <m:mi>B<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n      <\/m:mfenced>\r\n      <m:mn>2<\/m:mn>\r\n     <\/m:msup>\r\n     <m:mo>=<\/m:mo><m:msup>\r\n      <m:mn>2<\/m:mn>\r\n      <m:mn>2<\/m:mn>\r\n     <\/m:msup>\r\n     \r\n    <\/m:mtd>\r\n   <\/m:mtr>\r\n   <m:mtr>\r\n    <m:mtd>\r\n     <m:msup>\r\n      <m:mfenced>\r\n       <m:mrow>\r\n        <m:mi>B<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n      <\/m:mfenced>\r\n      <m:mn>2<\/m:mn>\r\n     <\/m:msup>\r\n     <m:mn>4<\/m:mn><m:mo>=<\/m:mo><m:mn>2<\/m:mn><m:mo>+<\/m:mo><m:mn>2<\/m:mn>\r\n    <\/m:mtd>\r\n   <\/m:mtr>\r\n   <m:mtr>\r\n    <m:mtd>\r\n     <m:msup>\r\n      <m:mfenced>\r\n       <m:mrow>\r\n        <m:mi>B<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n      <\/m:mfenced>\r\n      <m:mn>2<\/m:mn>\r\n     <\/m:msup>\r\n     <m:mo>=<\/m:mo><m:mo stretchy=\"false\">(<\/m:mo><m:msqrt>\r\n      <m:mrow>\r\n       <m:mn>2<\/m:mn><m:msup>\r\n        <m:mo stretchy=\"false\">)<\/m:mo>\r\n        <m:mn>2<\/m:mn>\r\n       <\/m:msup>\r\n       <\/m:mrow>\r\n     <\/m:msqrt>\r\n     <m:mo>+<\/m:mo><m:mo stretchy=\"false\">(<\/m:mo><m:msqrt>\r\n      <m:mrow>\r\n       <m:mn>2<\/m:mn><m:msup>\r\n        <m:mo stretchy=\"false\">)<\/m:mo>\r\n        <m:mn>2<\/m:mn>\r\n       <\/m:msup>\r\n       <\/m:mrow>\r\n     <\/m:msqrt>\r\n     \r\n    <\/m:mtd>\r\n   <\/m:mtr>\r\n  <\/m:mtable>\r\n  \r\n <\/m:semantics><\/math>&nbsp;<span> <\/span>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:msup>\r\n    <m:mrow>\r\n     <m:mfenced>\r\n      <m:mrow>\r\n       <m:mi>B<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n     <\/m:mfenced><\/m:mrow>\r\n    <m:mn>2<\/m:mn>\r\n   <\/m:msup>\r\n   <m:mo>=<\/m:mo><m:msup>\r\n    <m:mrow>\r\n     <m:mfenced>\r\n      <m:mrow>\r\n       <m:mi>O<\/m:mi><m:mi>B<\/m:mi><\/m:mrow>\r\n     <\/m:mfenced><\/m:mrow>\r\n    <m:mn>2<\/m:mn>\r\n   <\/m:msup>\r\n   <m:mo>+<\/m:mo><m:msup>\r\n    <m:mrow>\r\n     <m:mfenced>\r\n      <m:mrow>\r\n       <m:mi>O<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n     <\/m:mfenced><\/m:mrow>\r\n    <m:mn>2<\/m:mn>\r\n   <\/m:msup>\r\n   <\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span> <\/span><span>So, in triangle BOC we have,<\/span><br>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:msup>\r\n    <m:mrow>\r\n     <m:mfenced>\r\n      <m:mrow>\r\n       <m:mi>B<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n     <\/m:mfenced><\/m:mrow>\r\n    <m:mn>2<\/m:mn>\r\n   <\/m:msup>\r\n   <m:mo>=<\/m:mo><m:msup>\r\n    <m:mrow>\r\n     <m:mfenced>\r\n      <m:mrow>\r\n       <m:mi>O<\/m:mi><m:mi>B<\/m:mi><\/m:mrow>\r\n     <\/m:mfenced><\/m:mrow>\r\n    <m:mn>2<\/m:mn>\r\n   <\/m:msup>\r\n   <m:mo>+<\/m:mo><m:msup>\r\n    <m:mrow>\r\n     <m:mfenced>\r\n      <m:mrow>\r\n       <m:mi>O<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n     <\/m:mfenced><\/m:mrow>\r\n    <m:mn>2<\/m:mn>\r\n   <\/m:msup>\r\n   <\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span> <\/span><span>Thus <\/span>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:mo>\u2220<\/m:mo><m:mi>B<\/m:mi><m:mi>O<\/m:mi><m:mi>C<\/m:mi><m:mo>=<\/m:mo><m:msup>\r\n    <m:mrow>\r\n     <m:mn>90<\/m:mn><\/m:mrow>\r\n    <m:mo>\u00b0<\/m:mo>\r\n   <\/m:msup>\r\n   <\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span> (By Converse of Pythagoras theorem). <\/span><br><span>So, <\/span>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:mi>a<\/m:mi><m:mi>r<\/m:mi><m:mi>c<\/m:mi><m:mi>B<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span> subtends <\/span>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:mo>\u2220<\/m:mo><m:mi>B<\/m:mi><m:mi>O<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span> from the center O and angle <\/span>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:mo>\u2220<\/m:mo><m:mi>B<\/m:mi><m:mi>A<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span> at left segment of the circle, <\/span><br><span>Since the angle subtended by an arc at the center is double the angle subtended by it at any point on the left part of the circle, therefore<\/span>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:mo>\u2220<\/m:mo><m:mi>B<\/m:mi><m:mi>O<\/m:mi><m:mi>C<\/m:mi><m:mo>=<\/m:mo><m:mn>2<\/m:mn><m:mo>\u2220<\/m:mo><m:mi>B<\/m:mi><m:mi>A<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span>.<\/span><br>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:mo>\u2220<\/m:mo><m:mi>B<\/m:mi><m:mi>O<\/m:mi><m:mi>C<\/m:mi><m:mo>=<\/m:mo><m:mn>2<\/m:mn><m:mo>\u2220<\/m:mo><m:mi>B<\/m:mi><m:mi>A<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span> <\/span>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:msup>\r\n    <m:mrow>\r\n     <m:mn>90<\/m:mn><\/m:mrow>\r\n    <m:mo>\u00b0<\/m:mo>\r\n   <\/m:msup>\r\n   <m:mo>=<\/m:mo><m:mn>2<\/m:mn><m:mo>\u2220<\/m:mo><m:mi>B<\/m:mi><m:mi>A<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<br>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:mfrac>\r\n    <m:mrow>\r\n     <m:msup>\r\n      <m:mrow>\r\n       <m:mn>90<\/m:mn><\/m:mrow>\r\n      <m:mo>\u00b0<\/m:mo>\r\n     <\/m:msup>\r\n     <\/m:mrow>\r\n    <m:mn>2<\/m:mn>\r\n   <\/m:mfrac>\r\n   <m:mo>=<\/m:mo><m:mo>\u2220<\/m:mo><m:mi>B<\/m:mi><m:mi>A<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span> <\/span>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:msup>\r\n    <m:mrow>\r\n     <m:mn>45<\/m:mn><\/m:mrow>\r\n    <m:mo>\u00b0<\/m:mo>\r\n   <\/m:msup>\r\n   <m:mo>=<\/m:mo><m:mo>\u2220<\/m:mo><m:mi>B<\/m:mi><m:mi>A<\/m:mi><m:mi>C<\/m:mi><\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span> <\/span>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:mo>\u2220<\/m:mo><m:mi>B<\/m:mi><m:mi>A<\/m:mi><m:mi>C<\/m:mi><m:mo>=<\/m:mo><m:msup>\r\n    <m:mrow>\r\n     <m:mn>45<\/m:mn><\/m:mrow>\r\n    <m:mo>\u00b0<\/m:mo>\r\n   <\/m:msup>\r\n   <\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span> <\/span><span>As the angle subtended by the chord at a point in major segment is <\/span>\r\n<math>\r\n <m:semantics>\r\n  <m:mrow>\r\n   <m:msup>\r\n    <m:mrow>\r\n     <m:mn>45<\/m:mn><\/m:mrow>\r\n    <m:mo>\u00b0<\/m:mo>\r\n   <\/m:msup>\r\n   <\/m:mrow>\r\n <\/m:semantics><\/math>&nbsp;<span>, thus statement is false.<\/span><br><span>Hence, option 2 is correct.<\/span><br><span>&nbsp;<\/span>","subject":"Mathematics"},"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v17.9 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>State true or false.A circle has radius      2    \u00a0\u00a0 cm. 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