50 Examples of Balanced Chemical Equations with Answers

Chemical reactions happen all around us, from cooking food to rust forming on iron. These reactions are written as chemical equations, which show how substances change into new substances. But just writing an equation is not enough – it must be balanced to follow the Law of Conservation of Mass. This law states that matter cannot be created or destroyed in a chemical reaction. So, the number of atoms of each element must be the same on both sides of the equation.

What is a Balanced Chemical Equation?

A balanced chemical equation represents a chemical reaction where the number of atoms for each element is the same on both the reactant and product sides. For example:

2H₂ + O₂ → 2H₂O

Why is Balancing Chemical Equations Important?

Balancing chemical equations is necessary because:

1. It follows the Law of Conservation of Mass – The total mass of reactants must equal the total mass of products.
2. It ensures correct chemical proportions – In real-life reactions, incorrect proportions can cause dangerous or ineffective results.
3. It helps in calculations – Scientists and engineers use balanced equations to calculate how much of each substance is needed or produced.

How to Balance a Chemical Equation?

• Write the unbalanced equation.
• Count the number of atoms of each element on both sides.
• Use coefficients (whole numbers) to balance atoms.
• Ensure that the mass is conserved.
• Double-check your answer.

50 Balanced Chemical Equations with Answers PDF

Are you searching for a PDF of 50 balanced chemical equations with answers for Class 10 science? This FREE resource is perfect for CBSE, ICSE, and other state board students. It includes different types of chemical reactions like combustion, synthesis, decomposition, and neutralization — all explained with balanced equations and step-by-step answers. Whether you're preparing for exams or doing homework, this chemical equations pdf download will make your learning simple and clear. Download now and get a complete list of important chemical equations for class 10 with answers in an easy-to-read format. 

Download: 50 examples of balanced chemical equations with answers pdf

In this article, you will find 50 examples of balanced chemical equations with answers. These examples include different types of reactions such as combustion, synthesis, decomposition, single replacement, double replacement, acid-base neutralization, redox, and precipitation reactions.

If you are a Class 10 student, this list will help you prepare for exams. If you want to study offline, you can also download the 50 examples of balanced chemical equations with answers PDF provided at the end of this article.

Let’s explore these 50 balanced chemical equations and understand how to apply them!

50 Examples of Balanced Chemical Equations with Answers

1. Combustion Reactions

• CH₄ + 2O₂ → CO₂ + 2H₂O
• C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
• C₂H₆ + 7/2 O₂ → 2CO₂ + 3H₂O
• C₄H₁₀ + 13/2 O₂ → 4CO₂ + 5H₂O
• C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O

2. Synthesis (Combination) Reactions

• 2H₂ + O₂ → 2H₂O
• N₂ + 3H₂ → 2NH₃
• 2Na + Cl₂ → 2NaCl
• CaO + CO₂ → CaCO₃
• 2Mg + O₂ → 2MgO

3. Decomposition Reactions

• 2H₂O → 2H₂ + O₂
• CaCO₃ → CaO + CO₂
• 2HgO → 2Hg + O₂
• 2KClO₃ → 2KCl + 3O₂
• NH₄NO₃ → N₂O + 2H₂O

4. Single Replacement Reactions

• Zn + 2HCl → ZnCl₂ + H₂
• Fe + CuSO₄ → FeSO₄ + Cu
• Mg + 2HCl → MgCl₂ + H₂
• Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag
• Al + Fe₂O₃ → Al₂O₃ + Fe

5. Double Replacement Reactions

• AgNO₃ + NaCl → AgCl + NaNO₃
• BaCl₂ + Na₂SO₄ → BaSO₄ + 2NaCl
• HCl + NaOH → NaCl + H₂O
• Pb(NO₃)₂ + KI → PbI₂ + 2KNO₃
• Na₂CO₃ + CaCl₂ → CaCO₃ + 2NaCl

6. Redox Reactions

• Fe₂O₃ + 3CO → 2Fe + 3CO₂
• MnO₂ + 4HCl → MnCl₂ + Cl₂ + 2H₂O
• 2K + 2H₂O → 2KOH + H₂
• CuO + H₂ → Cu + H₂O
• 2Al + Fe₂O₃ → Al₂O₃ + 2Fe

6. Acid-Base Neutralization Reactions

• HCl + NaOH → NaCl + H₂O
• H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
• HNO₃ + KOH → KNO₃ + H₂O
• CH₃COOH + NaOH → CH₃COONa + H₂O
• H₂CO₃ + Ca(OH)₂ → CaCO₃ + 2H₂O

8. Precipitation Reactions

• Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃
• BaCl₂ + Na₂SO₄ → BaSO₄ + 2NaCl
• NaOH + CuSO₄ → Cu(OH)₂ + Na₂SO₄
• CaCl₂ + Na₂CO₃ → CaCO₃ + 2NaCl
• FeCl₃ + NaOH → Fe(OH)₃ + 3NaCl

7. Other Important Reactions

• KClO₃ → KCl + O₂
• NH₃ + HCl → NH₄Cl
• SO₂ + O₂ → SO₃
• Na₂O + H₂O → 2NaOH
• P₄ + 5O₂ → P₄O₁₀
• Al₂O₃ + 6HCl → 2AlCl₃ + 3H₂O
• 2H₂S + 3O₂ → 2SO₂ + 2H₂O
• 2Fe + 3Cl₂ → 2FeCl₃
• 2K + Cl₂ → 2KCl
• C + O₂ → CO₂

Unbalanced and Balanced Chemical Equations (with Answers) 

Write the Balanced Chemical Equations for the Following Reactions

Q1. Unbalanced Equation:
Al + O₂ → Al₂O₃

Step-by-Step Solution

Write number of atoms:
Al 1, 2
O 2, 3

Balance Al:
Add 2 in front of Al → 2Al + O₂ → Al₂O₃

Balance O:
Now we have 3 O atoms in product. Use 3O₂ and 2Al₂O₃:
→ 4Al + 3O₂ → 2Al₂O₃

Final Balanced Equation:
4Al + 3O₂ → 2Al₂O₃

Q2. Unbalanced Equation:
Fe + HCl → FeCl₂ + H₂

Atoms count:

Element, Reactants, Products
Fe 1, 1
H 1, 2
Cl 1, 2

Balance Cl and H:
Place 2 before HCl → Fe + 2HCl → FeCl₂ + H₂

Final Balanced Equation:
Fe + 2HCl → FeCl₂ + H₂

Q3. Unbalanced Equation:
Na + H₂O → NaOH + H₂

Atoms count:
Na 1, 1
H 2, 2
O 1, 1

Everything is already balanced when we use 2Na:
→ 2Na + 2H₂O → 2NaOH + H₂

Final Balanced Equation:
2Na + 2H₂O → 2NaOH + H₂

Q4. Unbalanced Equation:
CaCl₂ + Na₂CO₃ → CaCO₃ + NaCl

Atoms count:
Ca 1, 1
Cl 2, 1
Na 2, 1
CO₃ 1, 1

Balance Na and Cl:
Place 2 before NaCl → CaCl₂ + Na₂CO₃ → CaCO₃ + 2NaCl

Final Balanced Equation:
CaCl₂ + Na₂CO₃ → CaCO₃ + 2NaCl

Q5. Unbalanced Equation:
C₃H₈ + O₂ → CO₂ + H₂O

Step-by-Step Solution:
Atoms count:
C 3 
H 8 

Balance C and H first:
→ C₃H₈ + O₂ → 3CO₂ + 4H₂O
(C = 3, H = 8)

Now count O on right side:
3CO₂ = 6O, 4H₂O = 4O → Total = 10 O
So use 5O₂

Final Balanced Equation:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O