Understanding how many 3-digit numbers are divisible by 7 is a classic math problem often explored in competitive exams and school-level number theory. This article explains the logic behind solving it step by step, while also covering related concepts like divisibility, arithmetic sequences, and key terms for better comprehension.
A 3-digit number is any number from 100 to 999. These are numbers with exactly three digits and represent the smallest to largest values in that numerical range.
If a number is divisible by 7, it means that when you divide it by 7, the remainder is 0. In other words:
N % 7 = 0Where % denotes the remainder.
For example:
105 ÷ 7 = 15 → ✔️ divisible
106 ÷ 7 = 15.14 → ❌ not divisible
We’ll use a simple method involving Arithmetic Progression (AP).
We start at 100 and go upward:
100 ÷ 7 ≈ 14.28 → next whole number = 15
15 × 7 = 105
So, the first 3-digit number divisible by 7 is 105.
We stop at 999 and go downward:
999 ÷ 7 ≈ 142.71 → take floor value = 142
142 × 7 = 994
So, the last 3-digit number divisible by 7 is 994.
Now we form an AP: 105, 112, 119, ..., 994
First term (a) = 105
Common difference (d) = 7
Last term (l) = 994
We use the AP formula:
n = ((l - a) / d) + 1
n = ((994 - 105) / 7) + 1
n = (889 / 7) + 1 = 127 + 1 = 128
There are 128 three-digit numbers that are divisible by 7.
Here is the complete list of all 128 three-digit numbers divisible by 7:
105, 112, 119, 126, 133, 140, 147, 154, 161, 168, 175, 182, 189, 196, 203, 210, 217, 224, 231, 238, 245, 252, 259, 266, 273, 280, 287, 294, 301, 308, 315, 322, 329, 336, 343, 350, 357, 364, 371, 378, 385, 392, 399, 406, 413, 420, 427, 434, 441, 448, 455, 462, 469, 476, 483, 490, 497, 504, 511, 518, 525, 532, 539, 546, 553, 560, 567, 574, 581, 588, 595, 602, 609, 616, 623, 630, 637, 644, 651, 658, 665, 672, 679, 686, 693, 700, 707, 714, 721, 728, 735, 742, 749, 756, 763, 770, 777, 784, 791, 798, 805, 812, 819, 826, 833, 840, 847, 854, 861, 868, 875, 882, 889, 896, 903, 910, 917, 924, 931, 938, 945, 952, 959, 966, 973, 980, 987, 994
These numbers follow an arithmetic progression with a common difference of 7.
Q. What is the smallest 3-digit number?
Ans. 100
Q. What is the largest 3-digit number?
Ans. 999
Q. Define what it means for a number to be divisible by 7.
Ans. A number is divisible by 7 if it gives a remainder of 0 when divided by 7 (i.e., N mod 7=0)
Q. What is the formula for finding the total terms in an arithmetic progression (AP)?
Ans. n= (l−a)/ d +1
Q. First 3-digit number divisible by 7
Ans. 105 (Because 7×15=105)
Q. Last 3-digit number divisible by 7
Ans. 994 (Because 7×142=994)
Q. First five terms in AP
Ans. 105, 112, 119, 126, 133
Q. Use AP formula to find total terms
Ans. 𝑛= 994−105 / 7 + 1
= 889/7 + 1
= 127 + 1
= 128
Q. 203 divisible by 7? Show your work.
Ans. 203÷7=29
Yes, 203 is divisible by 7.
Q. List all 3-digit numbers divisible by 7 between 200 and 300
Ans. 203, 210, 217, 224, 231, 238, 245, 252, 259, 266, 273, 280, 287, 294
Q. What is the 15th number in the sequence?
Ans. Use: a+(n−1)d
= 105+14×7
= 105+98
=203
Smallest 3-digit number divisible by 7 = 105
Largest 3-digit number divisible by 7 = 994
These numbers form an arithmetic progression (AP) with a common difference of 7.
Use the AP formula:
𝑛= 994−105/7 + 1
= 127+1
=128
128
No, 458409 ÷ 7 = 65515.571
Not an integer → Not divisible by 7
Yes, 2430780 ÷ 7 = 347254.2857
Yes, 5929 ÷ 7 = 847
Yes, 343 = 7³ → A perfect cube of 7
343 ÷ 7 = 49
Yes, 3852 ÷ 7
= 550.2857