First slide

PH of strong acids and strong bases

Question

Assuming complete ionisation, the pH of 0.1 M HCI is 1. The molarity of $H_{2} {SO}_{4}$ with the same pH is

Moderate

A

0.01
B

0.2
C

0.05
D

2.0

Solution

$[H^{+}] in 0.1 MHCl = 0.1$
$For same pH, [H^{+}] in H_{2} {SO}_{4} = 0.1 M$
$One mole H_{2} {SO}_{4} gives 2 moles of of H^{+} ions$
$H_{2} {SO}_{4} ⟶ 2 H^{+} + {SO}_{4}^{2 -}$
$∴ 0.1 M [H^{+}] will be given by$
$= \frac{0.1}{2} = 0.05 {MH}_{2} {SO}_{4}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App