First slide

Basic Buffer

Question

A buffer has equal volumes of 0.2 M ${NH}_{4} OH$ and 0.02 M ${NH}_{4} Cl .$ The $P^{K_{b}}$ of the base is 5.The $P^{H}$ of buffer is

Moderate

A

9.4
B

11.4
C

10.0
D

8.44

Solution

$P^{OH} = P^{K_{b}} + \log \frac{[salt]}{[base]}$
$= 5 + \log \frac{0.02}{0.2}$
$= 5 + \log \frac{1}{10} = 5 - 1 = 4$
$P^{H} = 14 - P^{OH} = 14 - 4 = 10$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App