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Q.

A buffer has equal volumes of 0.2 M NH4OH and 0.02 M NH4Cl. The PKb of the base is 5.The PH of buffer is

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a

9.4

b

11.4

c

10.0

d

8.44

answer is C.

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Detailed Solution

POH=PKb+logsaltbase       =5+log0.020.2       =5+log110=5-1=4PH=14-POH=14-4=10
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