First slide

Ionic product of water

Question

At 100⁰C, ionic product of water is 51.3 ×10^–14M². Then dissociation constant of water at 100⁰C is

Easy

A

1.72 x 10^-15
B

1.009 x 10^-15
C

9.243 x 10^-15
D

5.2 x 10^-16

Solution

At 100^oC, K_w = 51.3 x 10^-14 M²
$K_{i} = \frac{K_{w}}{55.55} = \frac{51.3 \times 10^{- 14} M^{2}}{55.55 M}$
K_i = 9.23 x 10^-15 M

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