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Q.

At 250C, the solubility product of MgOH2 is 1.0× 10-11. At which pH, will Mg2+ ions start precipitating in the form of MgOH2 from a solution of 0.001 M Mg2+ ions ?

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a

9

b

10

c

11

d

8

answer is B.

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Detailed Solution

MgOH2  ⇌  Mg2+  +  2OH-KSP = Mg2+  OH-2 OH- = KSPMg2+ = 1 × 10-110.001 pOH = - log OH- = - log 10-4 pOH = 4 and pH = 10 pH = 14 - pOH = 14 - 4 = 10
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