Calculate the solubility of A2X3 in pure water, assuming that neither kind of ion reacts with water. The solubility product of A2X3,Ksp=1.1×10-23

A2X3⟶2A3++3X2-Ksp=A3+2X2-3=1.1×10-23 If S= solubility of A2X3, then A3+=2S;  X2-=3Stherefore, Ksp=(2S)2(3S)3=(108)S5=1.1×10-23Thus, S5=1×10-25S=1.0×10-5 mol L