Carboxylic acids readily dissolve in aqueous sodium bicarbonate, liberating carbon dioxide. Which one of the following is correct?

Moderate

A

Free carboxylic acid and its conjugate base are of comparable stability
B

The free carboxylic acid is more stable than its conjugate base
C

The conjugate base of the carboxylic acid is more stable than the free carboxylic acid
D

The conjugate acid of the carboxylic acid is more stable than the free carboxylic acid

Solution

$RCOOH + {NaHCO}_{3} ⇌ RCOONa + H_{2} O + {CO}_{2}$
or $RCOOH + {HCO}_{3}^{-} ⇌ {RCOO}^{-} + H_{2} O + {CO}_{2}$
conjugate base, ${RCOO}^{-}$ is more stable. That is why equilibrium shifts in forward direction.

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