Change in enthalpy when 11.2 dm3 of He at NTP is heated in a cylinder to 1000C is (assume ideal behaviour)(Hint : ΔH = nCpΔT, for mono atomic gas CP = 5/2R)

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answer is 2.

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Detailed Solution

At STP, 11.2 dm3=0.5 moles; R=8.314 J K-1mole-1; ∆H=nCpdt; ∆H=0.5×52×8.314×100=1039.25 J ;

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