First slide

Thermodynamic properties

Question

Change in enthalpy when 11.2 dm³ of He at NTP is heated in a cylinder to 100⁰C is (assume ideal behaviour)(Hint : ΔH = nCpΔT, for mono atomic gas C_P = 5/2R)

Easy

Solution

$At STP, 11.2 {dm}^{3} = 0.5 moles; R = 8.314 J K^{- 1} {mole}^{- 1}; ∆ H = {nC}_{p} dt; ∆ H = 0.5 \times \frac{5}{2} \times 8.314 \times 100 = 1039.25 J;$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App