First slide

Enthalpy of formation

Question

Cl_(g)+ e^- → Cl^-_(g), EA=-348 KJ/mol at 0 K. then ΔH for same process at 300K (in KJ) [R=8x 10^-3J/mol/K] :
$[Hint: \Delta H = EA\;\ -\;\ \frac{5}{2}RT]$

Moderate

A

+354
B

+348
C

-354
D

Zero

Solution

$\begin{array}{l} \Delta H = E.A - \frac{5}{2}RT = - 348 - [\frac{5}{2} \times 8 \times {10^{ - 3}} \times 300]\\\\ \,\,\,\,\,\,\,\, = - 348 - [6] = - 354KJ \end{array}$

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