First slide

Aplicaitons of VBT

Question

Considering H₂O as a weak field ligand, the number of unpaired electrons in $Mn {(H_{2} O)}_{6}^{2 +}$ will be:

Moderate

A

3
B

2
C

5
D

4

Solution

$_{25} Mn : 3 d^{5}, 4 s^{2}$
${Mn}^{2 +} : 3 d^{5}$ , i.e., 5 unpaired electrons because H₂O is weak field ligand and does not force to pairing.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App