Enthalpy of combustion of diamond is 395kJ/mole and Enthalpy of combustion of graphite is 393kJ/mole. Enthalpy change when one mole of diamond converts to one mole of graphite is
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answer is 2.
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Detailed Solution
Combustion is always exothermic, ∆H=-ve; Cdiamond+O2g →CO2g; ∆H=-395kJ -I ; Cgraphite+ O2g →CO2g; ∆H=-393kJ -II; Eq I - Eq II Cdiamond→ Cgraphite; ∆H=-2kJ/mole