Enthalpy of combustion of Rhombic sulphur is -2400 kJ/mole. Enthalpy os formation sulphur dioxide is
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a
-2400 kJ
b
-19200 kJ
c
-600 kJ
d
-300 kJ
answer is D.
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Detailed Solution
Rhombic sulphur is S8(α)S8α+8O2g→8SO2g,ΔH=−2400 kJ ;Dividing throughout by 818S8α+O2g→SO2g,ΔH= -300 kJ ;Standard enthalpy of formation of SO2 is -300 kJ/mole ;