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Q.

Enthalpy of combustion of Rhombic sulphur is -2400 kJ/mole. Enthalpy os formation sulphur dioxide is

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a

-2400 kJ

b

-19200 kJ

c

-600 kJ

d

-300 kJ

answer is D.

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Detailed Solution

Rhombic sulphur is S8(α)S8α+8O2g→8SO2g,ΔH=−2400 kJ ;Dividing throughout by 818S8α+O2g→SO2g,ΔH= -300 kJ ;Standard enthalpy of formation of SO2 is -300 kJ/mole ;
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