First slide

Enthalpy of formation

Question

Enthalpy of combustion of Rhombic sulphur is -2400 kJ/mole. Enthalpy os formation sulphur dioxide is

Moderate

A

-2400 kJ
B

-19200 kJ
C

-600 kJ
D

-300 kJ

Solution

Rhombic sulphur is S₈(α)
$\begin{array}{l} S_{8} (α) + 8 O_{2} (g) \to 8 {SO}_{2} (g), ΔH = - 2400 kJ; \\ Dividing throughout by 8 \\ \frac{1}{8} S_{8} (α) + O_{2} (g) \to {SO}_{2} (g), ΔH = - 300 kJ; \\ Standard enthalpy of formation of {SO}_{2} is - 300 kJ / mole; \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App