First slide

Gaseous state

Question

1g H₂, 2g He and 3g NO are contained in 1 .1 L flask at 300 K. Total pressure exerted by the mixture is

Moderate

A

5.45 atm
B

6.0 atm
C

24.63 atm
D

134.34 atm

Solution

$P = \frac{n (total)}{V} RT n_{total} = n (H_{2}) + n (He) + n (NO) = \frac{1}{2} + \frac{2}{4} + \frac{3}{30} = 1 .1 mol ∴ P = \frac{1 .1 \times 0 .0821 \times 300}{1 .1} = 24 .63 atm$

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