For a given reaction, ΔH=35.5kJmol−1and ΔS=83.6JK−1mol−1 The reaction is spontaneous at(Assume that ΔH and ΔS do not vary with temperature.)
For a spontaneous reaction,
ΔG<0 i.e., ΔH-TΔS<0 T>ΔHΔS T>35.5×100083.6=424.6≈425 K ∴T>425 K