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Heat capacity (CV) of an ideal gas is X KJ/ mole/K. To rise its temperature from 298 K to 318 K, heat to be supplied per 10g gas will be (in KJ) [MW =16]

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Detailed Solution

Cv for one mole(16g)=X; Cv for 10 grams =10X16; qv=Cv∆T; qv=10X16×20=12.5X;

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