First slide

Thermodynamic properties

Question

Heat capacity (C_V) of an ideal gas is X KJ/ mole/K. To rise its temperature from 298 K to 318 K, heat to be supplied per 10g gas will be (in KJ) [MW =16]

Moderate

Solution

$C_{v} for one mole (16 g) = X; C_{v} for 10 grams = \frac{10 X}{16}; q_{v} = C_{v} ∆ T; q_{v} = \frac{10 X}{16} \times 20 = 12.5 X;$

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