First slide

Enthalpy of Combustion

Question

Human body requires 2370 K. Cal of energy daily. The heat of combustion of glucose is –790 K.cal/mole. The amount of glucose required for daily consumption is

Easy

Solution

$\large {C_6}{H_{12}}{O_{{6_{(g)}}}}\; + \;6{O_{{2_{(g)}}}}\; \to \;6{CO_{{2_{(g)}}}}\; + \;6{H_2}{O_{(l)}}$

$\large {\Delta _{com}}H = - 790K.cal$

GMW of glucose= 180 g;
Weight of glucose required= $\frac{2370 \times 180}{790} = 540 grams;$

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