An ideal gaseous sample at initial state i (Po, Vo, To) is allowed to expand to volume 2 Vo using two different process; in the first process the equation of process is 2PV²=K1 and in second process the equation of the process is PV= K2. Then,
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
Work done in first process will be greater than workdone in second process (magnitude wise)
b
The order of values of work done can not be compared unless we know the value of K1 and K2.
c
Value of work done (magnitude) in second process is greater than the work done in first process irrespective of the value of K1 and K2
d
1st process is not possible
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Work done in adiabaticprocessW = K1-γVf1-γ-Vi1-γCaluculation of work done in 1st Process:2PV2 = K1From the equation :PV2 = K12 and γ=2W1 = K121-2Vf-1-Vi-1W1=-K12Vf-1-Vi-1Caluculation of work done in second process : It is expansion work PV1 = K2 ; γ = 1W2 = K21-1Vi1-1-Vf1-1=∞W2 > W1