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Q.

If equal volumes of oxygen and nitrogen undergoing diffusion, if oxygen diffuses in l0 min, then under similar conditions time period for diffusion of nitrogen is x .y minutes, then the value of x .y is

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answer is 9.3.

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Detailed Solution

Rate of diffusion ∝1Mwrate of diffusion = volume diffusedtime∴1tO21tN2=MN2MO2=2832=0.93 or tN2tO2=0.93∴tN2=0.93×10=9.3min

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