First slide
Enthalpy of formation
Question

If ΔfHC2H4 and ΔfHC2H6 areX1, and X2, kcalmol-1, then heat of hydrogenation of C2H is

Easy
Solution

2C+2H2​⟶C2​H4​ , ΔH0f​=x1​kcal/mol

C2​H4​⟶2C+2H2​ , ΔH0f=−x1​kcal/mol.....(1)
2C+3H2​⟶C2​H6 , ​ΔH0f​=x2​kcal/mol.....(2)

adding eqn(1)&(2), we have

C2​H4​+2C+3H2​⟶C2​H6​+2C+2H2​  ΔH0R​=−x1​+x2​
C2​H4​+H2​⟶C2​H6​ , ΔH0R​=(x2​−x1​)kcal/mol
Hence the heat of hydrogenation of C2​H4​ is (x2​−x1​)kcal/mol.

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