If the ionisation constant of acetic acid is 1.8×10-5 at what concentration will it be dissociated to 2%?
I M
0.018 M
0.18 M
0.045 M
CH3COOH⇌CH3COO-+H+
Initial C 0 0
at equil C(1-α) Cα C α
K=Cα·CαC(1-α)=Cα21-α=Cα2
or, C=Kα2=1.8×10-5(0.02)2=0.045M