First slide

Solubility product(KSP)

Question

If Ksp of Ag₂CO₃ is 8×10^–12, the molar solubility of Ag₂CO₃ in 0.1M AgNO₃ is :

Moderate

A

$\large 8 \times {10^{ - 12}}\,M$
B

$8 \times {10^{ - 10}}\,M$
C

$8 \times {10^{ - 11}}\,M$
D

$8 \times {10^{ - 13}}\,M$

Solution

Let the molar solubility of Ag₂CO₃ in 0.1 M AgNO₃ be S' which will be less due to common ion effect
$\large AgN{O_3}\left( {aq} \right)\xrightarrow{{}}\mathop {A{g^ + }\left( {aq} \right)}\limits_{0.1 + 2S} + \mathop {NO_3^ - }\limits_{0.1} \left( {aq} \right)$
$\large A{g_2}C{O_3}\left( {aq} \right) \rightleftharpoons \mathop {A{g_2}C{O_3}\left( {aq} \right)}\limits_{S'} \xrightarrow{{}}\mathop {2A{g^ + }\left( {aq} \right)}\limits_{2S' + 0.1} + \mathop {CO_3^{ - 2}}\limits_{S'} \left( {aq} \right)$
$\large {\left[ {A{g^ + }} \right]_{total}} = 2S' + 0.1\sim 0.1$
$\large {\left[ {A{g^ + }} \right]^2} \times \left[ {CO_3^{ - 2}} \right] = 8 \times {10^{ - 12}}$
⇒ 10^-2 x S' = 8 x 10^-12
⇒ S' = 8 x 10^-10

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App