If S1,S2,S3 and S4 are the solubilities of AgCl in water, in 0.01 M CaCl2, in 0.01 M NaCl and in 0.05 M AgNO3 respectively at a certain temperature, the correct order of solubilities is
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a
S1>S2>S3>S4
b
S1>S3>S2>S4
c
S1>S2=S3>S4
d
S1>S3>S4>S2
answer is B.
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Detailed Solution
0.01M CaCl2= 0.02 M Cl-, 0.01NaCl = 0.01M Cl-0.05 M AgNO3 = 0.05 M Ag+Ag+Cl-=Ksp (const.) Hence, S2=Ksp0.02=50 KspS3=Ksp0.01=100 KspS4=Ksp0.05= 20 Ksp or S1=Ksp= maximum