Iodiine atom, in the third excited state, reacts with fluorine to form a compound ‘x’. The formula and shape of ‘x’ are
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a
IF5 ,pentagonal
b
IF4 ,tetrahedral
c
IF4 , pentagonal bipyramidal
d
IF7 , pentagonal bipyramidal
answer is D.
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Detailed Solution
In third excited state, Iodine has the outermost configuration : ns1np3 nd3 , in its velence shell it has 7 unpaired electrons.Thus it forms IF7. Its hybridisation is sp3d3 .Shape is pentagonal bipyramidal.