First slide

Gaseous state

Question

At 400 K, the root mean square (rms) speed of a gas X (molecular weight = 40) is equal to the most probable speed of gas Y at 60K. The molecular weight of the gas Y is

Moderate

A
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B
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C
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D
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Solution

$u_{rms} = u_{mps} = \sqrt{\frac{3 RT}{M (X)}} = \sqrt{\frac{2 RT}{M (Y)}} = \frac{3 R \times 400}{40} = \frac{2 R \times 60}{M (Y)} M (Y) = 4$

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