First slide

PH of strong acids and strong bases

Question

$10^{- 6} M$ NaOH is diluted by 100 times. The pH of diluted base is

Moderate

A

Between 6 and 7
B

Between 10 and 11
C

Between 7 and 8
D

Between 5 and 6

Solution

After dilution, $[{OH}^{-}] = 10^{- 8} M$
or $[H^{+}] = 10^{- 6} M .$ pH cannot be 6 because total
$[{OH}^{-}] = 10^{- 7} + 10^{- 8} = 10^{- 7} (1 + 0.1)$
$= 10^{- 7} \times 1.1 or [H^{+}] = 10^{- 14} / (10^{- 7} \times 1.1)$
$= 9.09 \times 10^{- 8}$
$∴ pH = 8 - \log 9.09 = 8 - 0.9546 = 7.0454$

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