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Acidic buffer
Question

100 mL of 0.02 M benzoic acid pKa = 4.2 is titrated using 0.02 M NaOH. pH values after 50 mL and 100 mL of NaOH have been added are

Difficult
Solution

 On  50ml NaOH addition           C6H5COOH+OH-    C6H5COO-+H2O  t = 0       2               1                     0 teq             1               1                     1 pH = pKa = 4.2 On 100 ml NaOH addition           C6H5COOH+OH-  C6H5COO-+ H2O t = 0;       2              2                   0 teq             2              2                   2                                                                                C6H5COO- = 2200 = 0.01 M     pH = 7 + pKa + 12 log C               = 7 + 4.22 + 12 log 0.01 = 8.1  

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